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Derivation of PV = nRT The ideal gas equation is an empirical law - i.e., deduced from the results of various experiments. Several great scientific minds.

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Presentation on theme: "Derivation of PV = nRT The ideal gas equation is an empirical law - i.e., deduced from the results of various experiments. Several great scientific minds."— Presentation transcript:

1 Derivation of PV = nRT The ideal gas equation is an empirical law - i.e., deduced from the results of various experiments. Several great scientific minds (incl. Boltzmann, Maxwell) attempted to lay a theoretical basis for this law - i.e., to deduce a mathematical model for an ideal gas. // This is the very essence of science - an attempt to explain and understand measurements and observations of the natural world within a self-consistent, predictive model. //

2 The Postulates of Kinetic Theory:
1 The volume occupied by a gas is very large compared with the volume of the molecules themselves. 2 Gas molecules are considered as point-like hard spheres. 3 Molecules exert no forces on one another except during collisions which are perfectly elastic (no energy loss). 4 Molecules move in random directions.

3 Ramifications: Consider a cubical box of gas side L containing N molecules: vx vy vz L A Consider one molecule with velocities vx, vy, vz in x, y, z directions such that its total speed v is given by Consider the x direction only: Upon collision with side A the molecule undergoes a momentum change = -2mvx. vx -vx The molecule hits the wall every 2L/vx seconds. Hence the rate of change of momentum =

4 Recall Newton’s Law: Force = rate of change of momentum
Hence the force on wall A arising from one molecule is mvx2/L. The total force exerted on the wall is the sum of all the forces exerted by each molecule of which there are N. But pressure = force per unit area and so Because motion is random, vx2 = vy2 = vz2 = v2/3, so we arrive finally at:

5 Kinetic Energy The KE of a single molecule is ½ mv2
The average KE per molecule ½ mv2 Hence for N molecules: And yet we know So PV = 2/3 KEN We also know from the ideal gas equation that PV = nRT and so if N = N0, we can extract a molar kinetic energy:

6 Profound Implications:
All gases at the same temperature have the same molar kinetic energy. Kinetic energy  T, in fact they can be used interchangeably The average kinetic energy per molecule is given by: k = R/N0 = x J K-1 is called the Boltzmann constant (effectively the universal gas constant per molecule).

7 The Maxwell-Boltzmann Speed Distribution
The shape of the speed distribution curve is similar for all gases and is called the Maxwell-Boltzmann speed distribution. Number of molecules Speed / m s-1 T1 T3 > T2 > T1 T2 T3

8 Different Average Speeds
We can identify three important speeds on the M-B distribution Number of molecules Speed v / m s-1 vMP the most probable speed v the mean, or average, speed vrms the root mean square speed =

9 Any one of which is enough to characterize the distribution:
So for 298 K N2: vMP = 420 ms-1, v = 474 ms-1, vrms = 515 ms-1 _ (n.b., take care to use SI units in calculations)

10 Collision Rate and Mean Free Path
Imagine following a particular molecule moving through a gas for one second: hit miss d crel x 1s = c (m) How many collisions will our molecule make per second?

11 The volume of the cylinder is:
Our molecule will collide with every other molecule in the “cylinder” it sweeps out. Which is how many? The volume of the cylinder is: p d2 crel The ideal gas equation gives us the number of molecules per unit volume: PV = nRT and n = N / N0 Hence the number density N / V = P N0 /RT = P/kT So the number of collisions per second is: P where s = pd2 is called the collision cross-section. kT x c d density) (# (Volume) z rel 2 σ = p

12 So for example the number of collisions made per second by an average N2 molecule in air at STP is:
z ≈ 2 x 109 s-1 Put another way the molecule typically travels for an average of only 5 x s between collisions. At an average speed of 475 ms-1, the mean distance traveled between collisions – the, mean free path, l, can be calculated to be l = 475 m s-1 x 5 x s = 2.4 x m (which is about 103 molecular diameters)

13 Discuss How Cross Section Depends on Probe and Velocity
Molecular beam attenuation experiments

14 Attenuation data for the scattering of a thermal beam (1100 K) of CsCl by Ar atoms and by the polar CH2F2 molecules in a 44 mm cell. The log of the transmission decreases linearly with the pressure of the target gas. [Adapted from H. Schumacher, R. B. Bernstein, and E.W. Rothe, J. Chem. Phys. 33, 584 (1960).]

15 The operational definition of a collision is that one molecule collides with another when a force acts between them. We need to make it quantitative, but, loosely speaking, the longer the range of the force, the more likely is a collision. The very polar molecule CsCl has a longer range of attraction to another polar molecule than to a spherical atom. The implication that the cross-section depends on the range and strength of the intermolecular force carries with it an obvious corollary: the magnitude of the collision cross-section is a property of the two molecules that are colliding. Strictly speaking, a molecule does not have 'a size' whose value is independent of how we probe it.


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