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Lecture 11 Overview Self-Reducibility
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Overview on Greedy Algorithms
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Revisit Minimum Spanning Tree
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Exchange Property
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Self-Reducibility
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Max Independent Set in Matroid
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Exchange Property
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Self-Reducibility
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Overview on Greedy Algorithms
Self-Reducibility Exchange Property Matroid
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Local Ratio Method
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Basic Idea Proof
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Basic Idea
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Minimum Spanning Tree
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Activity Selection
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Puzzle
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Independent Set in Interval Graphs
Activity 9 Activity 8 Activity 7 Activity 6 Activity 5 Activity 4 Activity 3 Activity 2 Activity 1 time We must schedule jobs on a single processor with no preemption. Each job may be scheduled in one interval only. The problem is to select a maximum weight subset of non-conflicting jobs.
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Independent Set in Interval Graphs
Slide from Independent Set in Interval Graphs Activity9 Activity8 Activity7 Activity6 Activity5 Activity4 Activity3 Activity2 Activity1 time Maximize s.t. For each instance I For each time t
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Maximal Solutions We say that a feasible schedule is I-maximal if either it contains instance I, or it does not contain I but adding I to it will render it infeasible. Activity9 Activity8 Activity7 Activity6 Activity5 Activity4 Activity3 Activity2 Activity1 I2 I1 time The schedule above is I1-maximal and also I2-maximal
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An effective profit function
Slide from An effective profit function Activity9 Activity8 Activity7 Activity6 Activity5 Activity4 Activity3 Activity2 Activity1 P1=0 P1= P(Î) P1=0 P1=0 P1=0 P1= P(Î) P1=0 P1= P(Î) P1= P(Î) Î Let Î be an interval that ends first;
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An effective profit function
Slide from An effective profit function Activity9 Activity8 Activity7 Activity6 Activity5 Activity4 Activity3 Activity2 Activity1 P1=0 P1= P(Î) P1=0 P1=0 P1=0 P1= P(Î) P1=0 P1= P(Î) P1= P(Î) Î For every feasible solution x: p1 ·x p(Î) For every Î-maximal solution x: p1 ·x p(Î) Every Î-maximal is optimal.
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Independent Set in Interval Graphs: An Optimization Algorithm
Slide from Independent Set in Interval Graphs: An Optimization Algorithm Algorithm MaxIS( S, p ) If S = Φ then return Φ ; If I S p(I) 0 then return MaxIS( S - {I}, p); Let Î S that ends first; I S define: p1 (I) = p(Î) (I in conflict with Î) ; IS = MaxIS( S, p- p1 ) ; If IS is Î-maximal then return IS else return IS {Î};
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Running Example P(I5) = 3 -4 P(I6) = 6 -4 -2 P(I3) = 5 -5 P(I2) = 3 -5
Slide from Running Example P(I5) = P(I6) = P(I3) = P(I2) = P(I1) = P(I4) = -4 -5 -2
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Solution 1 Solution 2
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Minimum Weight Arborescence
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Definition
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Problem
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Key Point 1
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Key Point 2
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Why?
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Key Point 3
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Matroid Greedy Local Ratio Divide-and-Conquer Dynamic Programming Self-reducibility
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A Property of MST
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