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Sergey Antipov antipov@anl.gov Simulations Sergey Antipov antipov@anl.gov.

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Presentation on theme: "Sergey Antipov antipov@anl.gov Simulations Sergey Antipov antipov@anl.gov."— Presentation transcript:

1 Sergey Antipov antipov@anl.gov
Simulations Sergey Antipov

2 Simulation geometry 2000 V 24 μ insulation Conductor thickness is 1 μ
Pore length is 480 μ (20:1) Background ε=4, inside the pore ε=1. Shell conductivity - varies ground

3 results 127 MΩ resistance of a single pore
Question: Is quoted number of 100 MΩ for a single pore or the whole assembly. How many pores are there? Streamlines – electric field. Color of the streamline corresponds to the magnitude of Ez. For a low conductivity (high resistance) pore does not change the direction of electric field much. z

4 Zoom in 127 MΩ Streamlines – electric field.
Refraction of the field lines corresponds to the difference in dielectric constant of a substrate (ε=4) and the pore (air/vacuum)

5 Previous case with 1012 times lower resistance
For an extremely high values of conductivity (low resistance = short) pore forces electric field to align Streamlines – electric field.

6 6 pores 127 MΩ each Streamlines – electric field.


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