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Part (a) Total # of cars turning left = L(t) dt 18 = 1,658 cars.

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Presentation on theme: "Part (a) Total # of cars turning left = L(t) dt 18 = 1,658 cars."— Presentation transcript:

1 Part (a) Total # of cars turning left = L(t) dt 18 = 1,658 cars

2 Part (b) NOTE: I originally got an answer of cars/hour by rounding to 3 decimal places mid-way through the problem. Would this be acceptable to the AP graders? NO. To be safe, wait until the end to round anything off. L(t) > 150 on the interval (12.428, ). The average value of L over this interval is… L(t) dt 12.428 16.122 1 cars/hour =

3 Part (c) 200, = 400 This means that the signal will be required if, during any 2-hour time interval, L(t) dt The graphing calculator shows us that L(t) has a maximum value at t = hours. Since this is greater than 400, the intersection WILL be eligible for a traffic signal. Centering around this max gives us a 2-hour interval from to hours. L(t) dt = 13.294 15.294


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