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Published byLesley Sanders Modified over 5 years ago
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Objective Factor quadratic trinomials of the form ax2 + bx + c.
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When you multiply (3x + 2)(2x + 5), the coefficient of the x2-term is the product of the coefficients of the x-terms. Also, the constant term in the trinomial is the product of the constants in the binomials. (3x + 2)(2x + 5) = 6x2 + 19x + 10
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Example 1: Factoring ax2 + bx + c by Guess and Check
Factor 6x2 + 11x + 4 by guess and check. ( )( ) Write two sets of parentheses. ( x + )( x + ) The first term is 6x2, so at least one variable term has a coefficient other than 1. The coefficient of the x2 term is 6. The constant term in the trinomial is 4. (2x + 4)(3x + 1) = 6x2 + 14x + 4 (1x + 4)(6x + 1) = 6x2 + 25x + 4 Try factors of 6 for the coefficients and factors of 4 for the constant terms. (1x + 2)(6x + 2) = 6x2 + 14x + 4 (1x + 1)(6x + 4) = 6x2 + 10x + 4 (3x + 4)(2x + 1) = 6x2 + 11x + 4
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Check It Out! Example 1a
Factor each trinomial by guess and check. 6x2 + 11x + 3 ( )( ) Write two sets of parentheses. ( x + )( x + ) The first term is 6x2, so at least one variable term has a coefficient other than 1. The coefficient of the x2 term is 6. The constant term in the trinomial is 3. (2x + 1)(3x + 3) = 6x2 + 9x + 3 Try factors of 6 for the coefficients and factors of 3 for the constant terms. (1x + 3)(6x + 1) = 6x2 + 19x + 3 (1x + 1)(6x + 3) = 6x2 + 9x + 3 (3x + 1)(2x + 3) = 6x2 + 11x + 3
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Check It Out! Example 1b
Factor each trinomial by guess and check. 3x2 – 2x – 8 ( )( ) Write two sets of parentheses. The first term is 3x2, so at least one variable term has a coefficient other than 1. ( x + )( x + ) The coefficient of the x2 term is 3. The constant term in the trinomial is –8. (1x – 1)(3x + 8) = 3x2 + 5x – 8 Try factors of 3 for the coefficients and factors of 8 for the constant terms. (1x – 4)(3x + 2) = 3x2 – 10x – 8 (1x – 8)(3x + 1) = 3x2 – 23x – 8 (1x – 2)(3x + 4) = 3x2 – 2x – 8
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Example 3A: Factoring ax2 + bx + c When c is Negative
Factor each trinomial. Check your answer. 3n2 + 11n – 4 a = 3 and c = – 4, Outer + Inner = 11 . ( n + )( n+ ) Factors of 3 Factors of 4 Outer + Inner 1 and 3 –1 and 4 1(4) + 3(–1) = 1 –2 and 2 1(2) + 3(–2) = – 4 –4 and 1 1(1) + 3(–4) = –11 4 and –1 1(–1) + 3(4) = 11 (n + 4)(3n – 1) Use the Foil method. Check (n + 4)(3n – 1) = 3n2 – n + 12n – 4 = 3n2 + 11n – 4
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Example 3C: Factoring ax2 + bx + c When c is Negative
Factor each trinomial. Check your answer. 4x2 – 15x – 4 a = 4 and c = –4, Outer + Inner = –15. ( x + )( x+ ) Factors of 4 Factors of – 4 Outer + Inner 1 and 4 –1 and 4 1(4) – 1(4) = 0 –2 and 2 1(2) – 2(4) = –6 –4 and 1 1(1) – 4(4) = –15 (x – 4)(4x + 1) Use the Foil method. Check (x – 4)(4x + 1) = 4x2 + x – 16x – 4 = 4x2 – 15x – 4
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Example 4A: Factoring ax2 + bx + c When a is Negative
Factor –2x2 – 5x – 3. –1(2x2 + 5x + 3) Factor out –1. a = 2 and c = 3; Outer + Inner = 5 –1( x + )( x+ ) Factors of 2 Factors of Outer + Inner 1 and 2 3 and 1 1(1) + 3(2) = 7 1 and 3 1(3) + 1(2) = 5 (x + 1)(2x + 3) –1(x + 1)(2x + 3)
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