1. 11.6 Areas of Circles, Sectors and Segments

2. A = r2 Area of a sector: a region bound by 2 radii and an arc.H
Sector HOP O P O

3. T108: A sec = (mHP) r2
360
Where r is the radius and the arc HP is measured in degrees.

4. 360 Find the area, leave in terms of . A sec = (marc) r2 = 60 r2
= 1/6 122
= 144/6 
= 24 
12m 60

5. Area of a segment: a segment is a region bound by a chord and its corresponding arc.X Y Z
The area of a segment is equal to the area of the sector - the area of the triangle.

6. Given arc AB is 90 degrees and AO = 10
Find the shaded area. A B O
Segment = sector - triangle

7. Find the shaded area.
What steps are needed? 12
120˚

8. Find area of ∆XYO and ∆XZO
Find m<X = 60˚
Find area of ∆XYO and ∆XZO
Subtract sector YOZ Y 12
120˚ X O Z