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CMPT 300: Operating Systems I

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1 CMPT 300: Operating Systems I
School of Computing Science Simon Fraser University CMPT 300: Operating Systems I Ch 6: Process Synchronization Dr. Mohamed Hefeeda

2 Objectives Understand The Critical-Section Problem
And its hardware and software solutions

3 Consumer-Producer Problem
Classic example of process coordination Two processes sharing a buffer One places items into the buffer (producer) Must wait if the buffer if full The other takes items from the buffer (consumer) Must wait if buffer is empty Solution: Keep a counter on number of items in the buffer

4 Producer Process while (true) { /* produce an item in nextProduced */
while (count == BUFFER_SIZE) ; // do nothing buffer [in] = nextProduced; in = (in + 1) % BUFFER_SIZE; count++; }

5 Consumer Process while (true) { while (count == 0) ; // do nothing
nextConsumed = buffer[out]; out = (out + 1) % BUFFER_SIZE; count--; /*consume item in nextConsumed */ } What can go wrong with this solution?

6 Race Condition count++ could be implemented as register1 = count
register1 = register1 + 1 count = register1 count-- could be implemented as register2 = count register2 = register2 - 1 count = register2 Consider this execution interleaving with “count = 5” initially: S0: producer executes register1 = count {register1 = 5} S1: producer executes register1 = register {register1 = 6} S2: consumer executes register2 = count {register2 = 5} S3: consumer executes register2 = register {register2 = 4} S4: producer executes count = register1 {count = 6 } S5: consumer executes count = register2 {count = 4}

7 Race Condition Occurs when multiple processes manipulate shared data concurrently and the result depends on the particular order of manipulation Data inconsistency may arise Solution idea Mark code segment that manipulates shared data as critical section If a process is executing its critical section, no other processes can execute their critical sections More formally, any method that solves the Critical-Section Problem must satisfy three requirements …

8 Critical-Section (CS) Problem
Mutual Exclusion - If process Pi is executing in its critical section, then no other processes can be executing in their critical sections Progress - If no process is executing in its critical section and there exist some processes that wish to enter their critical section, then selection of the process that will enter the critical section next cannot be postponed indefinitely Bounded Waiting - A bound must exist on the number of times that other processes are allowed to enter their critical sections after a process has made a request to enter its critical section and before that request is granted Assumptions Each process executes at a nonzero speed No restriction on the relative speed of the N processes

9 Solutions for CS Problem
Disable interrupts during running CS Currently running code would execute without preemption Possible only on uniprocessor systems. Why? Problems Users could make CS arbitrary large unresponsive system Solutions using software only Solutions using hardware support

10 Peterson’s Solution Software solution; no hardware support
Two process solution Assume LOAD and STORE instructions are atomic (i.e., cannot be interrupted) may not always be true in modern computers The two processes share two variables: int turn; Boolean flag[2]; turn indicates whose turn it is to enter critical section The flag array indicates whether a process is ready to enter critical section flag[i] = true ==> process Pi is ready

11 Algorithm for Process Pi
while (true) { flag[i] = TRUE; turn = j; while (flag[j] && turn == j) ; CRITICAL SECTION flag[i] = FALSE; REMAINDER SECTION } Does this algorithm satisfy the three requirements? Yes.

12 Synchronization Hardware
Many systems provide hardware support for critical section code  more efficient and easier for programmers Modern machines provide special atomic (non-interruptable) hardware instructions Either test memory word and set value Or swap contents of two memory words

13 TestAndndSet Instruction
Definition: boolean TestAndSet (boolean *target) { boolean rv = *target; *target = TRUE; return rv; }

14 Solution using TestAndSet
Shared boolean variable lock, initialized to false while (true) { while ( TestAndSet (&lock ) ) ; /* do nothing // critical section lock = FALSE; // remainder section } Does this algorithm satisfy the three requirements? NO. A process can wait indefinitely for another faster process that is accessing its CS. Check Fig 6.8 for a modified version.

15 Swap Instruction Definition: void Swap (boolean *a, boolean *b) {
boolean temp = *a; *a = *b; *b = temp; }

16 Solution using Swap Shared boolean variable lock initialized to FALSE;
Each process has a local boolean variable key while (true) { key = TRUE; while ( key == TRUE) Swap (&lock, &key ); // critical section lock = FALSE; // remainder section }

17 Semaphore Much easier to use than hardware-based solutions
Semaphore S – integer variable Two standard operations to modify S: wait() signal() These two operations are indivisible (atomic)

18 Semaphore Operations wait (S) { while (S <= 0) ; // no-op, called busy waiting, spinlock S--; } signal (S) { S++; Later, we will see how to implement these operations with no busy waiting

19 Semaphore Types and Usage
Two types Counting semaphore: can be any integer value Binary semaphore: can be 0 or 1 (known as mutex locks) Usage examples: Mutual exclusion Semaphore mutex; // initialized to 1 wait (mutex); Critical Section signal (mutex);

20 Semaphore Types and Usage (cont’d)
Process synchronization: S2 in P2 should be executed after S1 in P1 P1: S1; signal (sem); P2: wait (sem); S2; Control access to a resource with finite number of instances e.g., producer-consumer problem with finite buffer

21 Semaphore Implementation with no Busy Waiting
Each semaphore has: value (of type integer) waiting queue Two operations: block – place the process invoking the operation in the waiting queue wakeup – remove one of the processes from the waiting queue and place it in the ready queue

22 Semaphore Implementation with no Busy Waiting
wait (S) { value--; if (value < 0) { add this process to waiting queue block(); } signal (S) { value++; if (value <= 0) { /*some processes are waiting*/ remove a process P from waiting queue wakeup(P);

23 Semaphore Implementation
Must guarantee that no two processes can execute wait and signal on same semaphore at same time Thus, implementation becomes the critical section problem where wait and signal code are placed in critical section, and protected by Disabling interrupts (uniprocessor systems only) Busy waiting or spinlocks (multiprocessor systems) Well, why do we not do the above in applications? Applications may spend long (and unknown) amount of time in critical sections, unlike kernel which spends short and known beforehand time in critical section (~ ten instructions)

24 Deadlock and Starvation
Deadlock – two or more processes are waiting indefinitely for an event that can be caused by only one of the waiting processes Let S and Q be two semaphores initialized to 1 P0 P1 wait (S); wait (Q); wait (Q); wait (S); . . signal (S); signal (Q); signal (Q); signal (S); Starvation – indefinite blocking. A process may never be removed from the semaphore queue in which it is suspended

25 Classical Problems of Synchronization
Bounded-Buffer (Producer-Consumer) Problem Dining-Philosophers Problem Readers-Writers Problem These problems are abstractions that can be used to model many other resource sharing problems used to test newly proposed synchronization schemes

26 Bounded-Buffer Problem
N buffers, each can hold one item Semaphore mutex initialized to the value 1 Semaphore full initialized to the value 0 Semaphore empty initialized to the value N

27 Bounded Buffer Problem (cont’d)
Structure of the producer process while (true) { // produce an item wait (empty); wait (mutex); // add item to buffer signal (mutex); signal (full); }

28 Bounded Buffer Problem (cont’d)
Structure of the consumer process while (true) { wait (full); wait (mutex); // remove an item from buffer signal (mutex); signal (empty); // consume removed item }

29 Dining-Philosophers Problem
Philosophers alternate between eating and thinking To eat, a philosopher needs two chopsticks (at her left and right) Models multiple processes sharing multiple resources Write a program for each philosopher s.t. no starvation/deadlock occurs Solution approach: Bowl of rice (data set) Array of semaphores: chopstick [5] initialized to 1

30 Dining-Philosophers Problem: Philosopher i
While (true) { wait ( chopstick[i] ); wait ( chopstick[ (i + 1) % 5] ); // eat signal ( chopstick[i] ); signal (chopstick[ (i + 1) % 5] ); // think } What can go wrong with this solution? All philosophers pick their left chopsticks at same time (deadlock) Solutions? Pick chopsticks only if both are available Asymmetric: odd philosopher picks left chopstick first, even picks right first

31 Readers-Writers Problem
A data set is shared among a number of concurrent processes Readers – only read the data set; they do not perform any updates Writers – can both read and write Problem – allow multiple readers to read at the same time. Only one single writer can access the shared data at the same time. Shared Data Data set Semaphore mutex initialized to 1 Semaphore wrt initialized to 1 Integer readcount initialized to 0

32 Readers-Writers Problem (cont’d)
The structure of a writer process while (true) { wait (wrt) ; // writing is performed signal (wrt) ; }

33 Readers-Writers Problem (cont’d)
Idea of reader processes: The first reader needs to check that there is no writer in CS Other readers access CS right away, but they need to update the current number of readers in CS (readcount) while (true) { wait (mutex) ; // mutex: protects readcount readcount ++ ; if (readercount == 1) wait (wrt) ; signal (mutex) // reading is performed wait (mutex) ; readcount - - ; if (redacount == 0) signal (wrt) ; signal (mutex) ; }

34 Readers-Writers Problem (cont’d)
Some systems implement reader-writer locks E.g., Solaris, Linux, Pthreads API A process can ask for a reader-write lock either in read or write mode When would you use reader-writer locks? Applications where it is easy to identify readers only and writers only processes Applications with more readers than writers Tradeoff: cost vs. concurrency Reader-writer locks require more overhead to establish than semaphores, but they provide higher concurrency by allowing multiples readers in CS

35 Be Careful When Using Semaphores
Some common programming problems … signal (mutex) …. wait (mutex) Multiple processes can access CS at the same time wait (mutex) … wait (mutex) Processes may block for ever Forgetting wait (mutex) or signal (mutex)

36 Monitors Monitor: High-level abstraction that provides a convenient and effective mechanism for process synchronization Compiler (not programmer) takes care of mutual exculsion Only one process may be active within the monitor at a time monitor monitor_name { //shared variable declarations procedure P1 (…) { …. } procedure Pn (…) {……} Initialization code ( ….) { … } }

37 Schematic View of a Monitor

38 Condition Variables condition x, y;
Two operations on a condition variable: x.wait () – a process that invokes the operation is suspended. x.signal () – resumes one of processes (if any) that invoked x.wait () What is the difference between condition variables and semaphores? condition variable: if no process is suspended, signal has no effect semaphores: signal always increments semaphore's value Condition variables are usually used in monitors to provide a way to suspend/awake processes

39 Monitor with Condition Variables

40 Solution to Dining Philosophers
monitor DP { enum {THINKING, HUNGRY, EATING} state [5] ; condition self [5]; void pickup (int i) { state[i] = HUNGRY; test(i); //check both chopsticks if (state[i] != EATING) self [i].wait; } void putdown (int i) { state[i] = THINKING; // test left and right neighbors test((i + 4) % 5); test((i + 1) % 5);

41 Solution to Dining Philosophers (cont’d)
void test (int i) { if ( (state[i] == HUNGRY) && (state[(i + 4) % 5] != EATING) && (state[(i + 1) % 5] != EATING) ) { state[i] = EATING ; self[i].signal () ; } initialization_code() { for (int i = 0; i < 5; i++) state[i] = THINKING; } // end monitor

42 Solution to Dining Philosophers (cont’d)
Each philosopher invokes the operations pickup() and putdown() in the following sequence: dp.pickup (i) EAT dp.putdown (i)

43 Monitors Implementation
It is up to the compiler to ensure mutual exclusion in monitors Semaphores are usually used Languages like Java, C# (not C), and Concurrent Pascal provide monitors-like mechanisms Java public class SimpleClass { .... public synchronized void insert(…) { …} public synchronized void remove(…) { …} …. } Java guarantees that once a thread starts executing a synchronized method, no other thread can execute any other synchronized method in the class Java 1.5 has semaphores, condition variables, mutex locks, … In java.util.concurrent package Exercise: write a java solution for the Producer-Consumer problem

44 Synchronization Examples
Windows XP Linux Pthreads

45 Windows XP Synchronization
Masks interrupts to protect access to global resources on uniprocessor systems (inside kernel) Uses spinlocks on multiprocessor systems Also provides dispatcher objects for thread synchronization outside kernel, which can act as mutexes, semaphores, or events (condition variables)

46 Linux Synchronization
disables interrupts to implement short critical sections (on single processor systems) Linux provides: semaphores Spinlocks (on SMP) Reader-writer locks

47 Pthreads Synchronization
#include <pthread.h> pthread_mutex_t mutex; pthread_mutex_init(&mutex, null); pthread_mutex_lock(&mutex); pthread_mutex_unlock(&mutex); #include <semaphore.h> sem_t sem; sem_init(&sem, 0, 5); sem_wait(&sem); sem_post(&sem); Pthreads API is OS-independent It provides: mutex locks condition variables extensions include: semaphores read-write locks spin locks May not be portable

48 Summary Processor Synchronization
Techniques to coordinate access to shared data Race condition Multiple processes manipulating shared data and result depends on execution order Critical section problem Three requirements: mutual exclusion, progress, bounded waiting Software solution: Peterson’s Algorithm Hardware support: TestAndSet(), Swap() Busy waiting (or spinlocks) Semaphores: wait(), signal() must be atomic  moves the CS problem to kernel Monitors: high-level constructs (compiler) Some classical synchronization problems


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