2. Possible observations:
Each pool is decreasing/Both functions are decreasing
Both functions have positive domain and range values
a(x) is decreasing faster than d(x)/ Aly’s pool is draining at a faster rate than Dayne’s
d(x) has less water in the pool initially; a(x) has more water initially
At some point, each pool has the same amount of water (where the two lines intersect)
d(x) is draining at a slower rate
Each pool is decreasing at a constant rate, but not the same rate
Dayne’s pool has less water in it initially
Aly’s pool will be empty before Dayne’s but they will both be empty at some point in time

3. 24,000 represents the initial amount of water in the pool
2. d(x) = 24,000 − 1000x
24,000 represents the initial amount of water in the pool
−1000 represents the rate at which the water is draining 3.
24,000 24

4. 4. Domain of water being emptied in Dayne’s pool: [0, 24]
5. Range of amount of water in Dayne’s pool: [0, 24,000]
6. a(x) = 28,000 − 1400x
Domain of water being emptied in Aly’s pool: [0, 20] Range of amount of water in Aly’s pool: [0, 28,000]
7. a(x) = d(x) at x = 10
Algebraically: a(x) = d(x)
28,000 − 1400x = 24,000 − 1000x

5. 8. a(5)= 21,000.
This means that at 5 minutes, there are 21,000 gallons of water in Aly’s pool.
9. If d(x)=2000, then x= 22.
This means that when there are 2000 gallons of water left, 22 minutes have passed.
10. a(x) > d(x) from 0 minutes to 10 minutes.
This is when Aly’s pool has more water.