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Unit 4 – Lesson 1 Apply Triangle Sum Properties

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Presentation on theme: "Unit 4 – Lesson 1 Apply Triangle Sum Properties"— Presentation transcript:

1 Unit 4 – Lesson 1 Apply Triangle Sum Properties And Angle Relationships

2 All sides are  Type of ∆ Definition Picture Equilateral Triangle
CLASSIFICATION BY SIDES

3 At least 2 sides  leg leg base Type of ∆ Definition Picture
Isosceles Triangle At least 2 sides  CLASSIFICATION BY SIDES leg leg base

4 No sides are  Type of ∆ Definition Picture Scalene Triangle
CLASSIFICATION BY SIDES

5 All angles are  Type of ∆ Definition Picture Equiangular Triangle
CLASSIFICATION BY ANGLES

6 All angles are acute Type of ∆ Definition Picture Acute Triangle
CLASSIFICATION BY ANGLES

7 hypotenuse leg One right angle leg Type of ∆ Definition Picture
Right Triangle hypotenuse leg One right angle CLASSIFICATION BY ANGLES leg

8 One obtuse angle and 2 acute angles
Type of ∆ Definition Picture Obtuse Triangle One obtuse angle and 2 acute angles CLASSIFICATION BY ANGLES

9 Interior Angles – Angles inside a shape Exterior Angles – Angles outside a shape Corollary – Statement easily proved from another statement

10 b c a b c a The sum of the measures of a triangle = _______ 180°

11 If two triangles have two angles that are _______,
If two triangles have two angles that are _______, then the third angle is also ___________. B E 80° 80° 40° 60° 40° 60° A C D F

12 The measure of an exterior angle of a triangle is equal to the sum of the measures of the two remote interior angles. a + b = 180° b + c + d = 180° b + c + d = a + b c + d = a

13 The acute angles of a right triangle are
______________. complementary a + c + 90 = 180° a a + c = 90° c

14 Classify the triangle by its sides and angles.
scalene right

15 Classify the triangle by its sides and angles.
equilateral equiangular

16 Classify the triangle by its sides and angles.
isosceles obtuse

17 4. Find the value of x. Then classify the triangle by its angles.
2x + 3x + 55 = 180 5x + 55 = 180 75° 5x = 125 50° x = 25° acute

18 4. Find the value of x. Then classify the triangle by its angles.
4x – 5 + 3x = 180 7x + 40 = 180 75° 7x = 140 65° x = 20° acute

19 4. Find the value of x. Then classify the triangle by its angles.
2x x x + 1 = 180 52° 7x + 5 = 180 52° 76° 7x = 175 x = 25° acute

20 5. Find the measure of each exterior angle shown.
x + 80 = 3x – 22 -x x 80 = 2x – 22 102 = 2x 51° = x 3(51) – 22 = 131°

21 5. Find the measure of each exterior angle shown.
2x – x = 6x – 7 x = 6x – 7 -x x 103 = 5x – 7 110 = 5x 22° = x 6(22) – 7 = 125°

22 5. Find the measure of each exterior angle shown.
2x = 4x + 8 2x + 54 = 4x + 8 -2x x 54 = 2x + 8 46 = 2x 23° = x 4(23) + 8 = 100°

23 6. Solve for the variables.
65° 25° y = 180 y = 180 y = 25°

24 6. Solve for the variables.
5y = 180 5y = 180 5y = 55 y = 11° 55°

25 7. Find the measure of each missing angle.
120° 30° 60° 30° 60° 120°

26 HW Problem 4.1 # 26 Ans: 4.1 221 229 1-6, 14-18, 21-26 (FRONT PAGE)
LT Page # Assignment Due 4.1 221 229 1-6, 14-18, (FRONT PAGE) 32, 33, 35, 15, 16 (BACK PAGE) 4.1 # 26 Ans:


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