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Published byElisabeth Phelps Modified over 5 years ago
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Match graph and equation Not all equations will have a graph
I can write a quadratic equation from a graph. Warm Up Page 353 Problem 8-82 Match graph and equation Not all equations will have a graph
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B E A G D I
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Homework Questions
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Solve using Zero Product Property.
(π₯+1)(π₯β2) = 0 (π₯β4)( π₯+1) = 0 (2π₯β3)( 3π₯+5) = 0 π₯=β1 and π₯=2 π₯=4 and π₯=β1 π₯=3/2 and π₯=β5/3
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Can you work backwards? x-int = ( -1, 0) x-int = (2, 0) π¦=(π₯+1)( π₯β2)
π¦= (π₯ β4) ( π₯+1)
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Now you try some . . . x-int = ( -3, 0) x-int = (1, 0) π¦=(π₯+3)( π₯β1)
π¦=(π₯β2)( π₯+2) π¦=(π₯β3)(π₯+5)
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Parabolas come in different shapes.
It is the leading coefficient that makes the difference!
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What do you know about this graph?
x-int = (-2,0) x-int = (1,0) 3rd Point = (0, 8) π¦= π (π₯+2)(π₯β1) We need to find a!
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What do you know about this graph?
(0,8) π¦= π(π₯+2)(π₯β1) Plug in (0, 8) 8= π( 0+2)(0β1) 8= π(2)(β1) 8= β2π β4 = π π = β π(π + π)( π β π) π = β π π π βππ+π
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Try One: π = π(π β π)(π + π) π = ππ(π β π) π = π π π βππ x-int = (2,0)
3rd Point = (1, -4) π¦ = π(π₯ β2)(π₯+0) β4 = π(1β2)( 1+ 0) β4 = π (β1)(1) β4 = βπ 4 = π π = π(π β π)(π + π) π = ππ(π β π) π = π π π βππ
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Remember Jen, from the water balloon problem . . .
Jenβs data Remember Jen, from the water balloon problem . . . Find the rule!
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Finish Retake Problem Set
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