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Buffers.

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Presentation on theme: "Buffers."— Presentation transcript:

1 Buffers

2 Solutions of Acids or Bases and Their Salts
HF + H2O  H3O+ + F- Problem: The equilibrium [H+] in a 1.0 M HF solution is 2.7 x 10-2 M and the % dissociation is 2.7 % Calculate the [H+] and the percent dissociation of HF in a solution containing 1.0 M HF (Ka = 7.2 x 10-4) and 1.0 M NaF

3 Acid Base Pt 2 So what is the point of a buffer?? It contains two species that are conjugates of one another. One is an acid, the other is a base. With both an acid AND a base, you have the ability to neutralize anything added and maintain a fairly constant pH.

4 Problems Calculate the pH of a solution by adding 0.30 mol of HC2H3O2 and 0.30 mol of NaC2H3O2 to enough water to make 1.0 L. (Ka = 1.8 x 10-5)

5 Problems 2) Calculate the pH of a solution containing M of HNO2 and 0.10 M KNO2. (Ka = 4.5 x 10-4)

6 Another way to produce a buffer….
You could take one of the species and react it with a strong acid or strong base Stoichiometric reaction As long as you don’t completely consume the original substance, you still have some of that substance and you’ve stoichiometrically created the conjugate

7 Problems 3) Calculate [F-] and the pH of a soln that is 0.20 M HF and 0.10 M HCl.

8 A Better Way! (or at least a different way….)
Can always use ICE or……… Henderson-Hasselbach Equation: shows relationship of variables in a buffer solution.

9 Henderson-Hasselbach
pH = pKa + log([base]/[acid]) or pOH = pKb + log([acid]/[base])

10 Henderson-Hasselbach
What is the pH of a buffered soln that is 0.12 M lactic acid(HC3H5O3) and 0.10 M sodium lactate? Ka = 1.4 x 10-4

11 Henderson-Hasselbach
What is the pH of a buffered soln that is 0.12 M lactic acid(HC3H5O3) and 0.10 M sodium lactate? Ka = 1.4 x 10-4

12 Practice Calculate the pH of L of a buffered soln of 0.50 M formic acid,HCO2H, and 0.70 M sodium formate before and after adding 10.0 mL of 1.00 M HCl. Ka = 1.8x10-4

13 Practice Using an acetic acid/sodium acetate buffer solution, what ratio of acid to CB would you need to maintain a pH of 5.00? Ka = 1.8x10-5

14 Buffer Capacity Amount of acid or base it can neutralize before pH begins to change… 1 M HC2H3O2 and 1M NaC2H3O2 versus 0.1 M will have the same pH but different capacity to be a buffer.

15 Buffers [H+] or pH is determined by 2 factors:
Ka expression and value Ratio of [ ] CA or CB By adding OH- it will react and dec[acid] and inc [base]. By adding H+ it will react and dec [base] and inc [acid]

16 Optimal Buffering Problem: A chemist needs a solution buffered at pH 4.30 and can choose from the following acids(and their salts). Chloroacetic acid Ka 1.35 x 10-3 Proponoic acid Ka 1.3 x 10-5 Benzoic acid Ka 6.4 x 10-5 Hypochlorous acid Ka 3.5 x 10-8


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