Presentation is loading. Please wait.

Presentation is loading. Please wait.

The Derivative (cont.) 3.1.

Similar presentations


Presentation on theme: "The Derivative (cont.) 3.1."— Presentation transcript:

1 The Derivative (cont.) 3.1

2 A Differential Function is Continuous
If y = f(x) has a derivative at x = c, then f(x) is continuous at x = c. When the Derivative Fails to Exist The derivative fails to exist when The graph of the function has a corner. The graph of the function has a vertical tangent. The graph of the function has a break (discontinuity).

3 To be differentiable, a function must be continuous and smooth.
Derivatives will fail to exist at: corner cusp discontinuity vertical tangent

4 Continuity does not imply Differentiability
Differentiability implies Continuity

5 Find the interval where the function is differentiable.
Limit does not exist, so the function is not continuous and not differentiable at x = 0 Possible point of discontinuity at x = 0

6 Using your calculator Graph |x| + 1 Zoom in on “corner”
Notice the corner does not change A differentiable curve will “straighten out”

7 Find at x = 2. Example: 1. Graph the function
2. Press 2nd TRACE to enter the CALC Menu 3. Select 6. dy/dx 4. Press 2 and ENTER 5. BE CAREFUL! The calculator gave an answer of The answer is 12! This should only be used as a check for your homework. You cannot use this method on a test/quiz!!


Download ppt "The Derivative (cont.) 3.1."

Similar presentations


Ads by Google