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5.2 Functions of Angles and Fundamental Identities

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1 5.2 Functions of Angles and Fundamental Identities
To define the six trigonometric functions, start with an angle  in standard position. Choose any point P having coordinates (x,y) on the terminal side as seen in the figure below. Notice that r > 0 since distance is never negative.

2 5.2 The Six Trigonometric Functions
The six trigonometric functions are sine, cosine, tangent, cotangent, secant, and cosecant. Trigonometric Functions Let (x,y) be a point other than the origin on the terminal side of an angle  in standard position. The distance from the point to the origin is The six trigonometric functions of angle  are as follows.

3 5.2 Finding Function Values of an Angle
Example The terminal side of angle  (beta) in standard position goes through (–3,–4). Find the values of the six trigonometric functions of . Solution

4 5.2 Quadrantal Angles The six trigonometric functions
can be found from any point on the line. Due to similar triangles, so sin = y/r is the same no matter which point is used to find it.

5 5.2 Reciprocal Identities
Since sin = y/r and csc = r/y, Similarly, we have the following reciprocal identities for any angle  that does not lead to a 0 denominator.

6 5.2 Using the Reciprocal Identities
Example Find sin if csc = Solution

7 5.2 Signs and Ranges of Function Values
In the definitions of the trigonometric functions, the distance r is never negative, so r > 0. Choose a point (x,y) in quadrant I, then both x and y will be positive, so the values of the six trigonometric functions will be positive in quadrant I. A point (x,y) in quadrant II has x < 0 and y > 0. This makes sine and cosecant positive for quadrant II angles, while the other four functions take on negative values. Similar results can be obtained for the other quadrants.

8 5.2 Signs and Ranges of Function Values
Example Identify the quadrant (or quadrants) of any angle  that satisfies sin > 0, tan < 0. Solution Since sin > 0 in quadrants I and II, while tan < 0 in quadrants II and IV, both conditions are met only in quadrant II.

9 5.2 Signs and Ranges of Function Values
The figure shows angle  as it increases from 0º to 90º. The value y increases as  increases, but never exceeds r, so y  r. Dividing both sides by r gives In a similar way, angles in quadrant IV suggests

10 5.2 Signs and Ranges of Function Values
Since for any angle . In a similar way, sec and csc are reciprocals of sin and cos, respectively, making

11 5.2 Ranges of Trigonometric Functions
Example Decide whether each statement is possible or impossible. (b) tan = (c) sec = .6 Solution Not possible since Possible since tangent can take on any value. Not possible since sec  –1 or sec  1. For any angle  for which for which the indicated function exists: –1  sin  and –1  cos  1; tan and cot may be equal to any real number; sec  –1 or sec  and csc  –1 or csc  1.

12 5.2 Pythagorean Identities
Three new identities from x2 + y2 = r2 Divide by r2 Since cos = x/r and sin = y/r, this result becomes Divide by x2 Dividing by y2 leads to cot2 + 1 = csc2.

13 5.2 Pythagorean Identities
Example Find sin and cos, if tan = 4/3 and  is in quadrant III. Solution Since  is in quadrant III, sin and cos will both be negative. Pythagorean Identities

14 5.2 Quotient Identities Recall that Consider the quotient of sin and cos where cos  0. Similarly Quotient Identities


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