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Oxidation - Reduction RedOx.

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Presentation on theme: "Oxidation - Reduction RedOx."— Presentation transcript:

1 Oxidation - Reduction RedOx

2 RedOx reactions Chemical reactions involving an electron transfer between atoms. Elements will change oxidation state from the reactant side to the product side.

3 Rules of assigning oxidation states
If in doubt with + or - The higher e-neg will get the - ! Group 1 is +1 Group 2 is +2 Transition METALS are always positive! Fluorine is -1 H is +1 in covalent & -1 in binary ionic O is -2 except with F then O is +2, or in a peroxide then -1.

4 Cu(s) Zn(s) Cl2(g) O2(g) O3(g) C60(s) Ne(g)
…and Elements that are not bonded to a different element have oxidation states of zero. Examples Cu(s) Zn(s) Cl2(g) O2(g) O3(g) C60(s) Ne(g)

5 H2S H2SO3 H2SO4 NOW More complicated . . .
sulfur has a -2 oxidation state H2SO3 sulfur has a +4 oxidation state H2SO4 sulfur has a +6 oxidation state How? 

6 Assigning oxidation states to atoms in a polyatomic ion
Oxidation states on individual atoms must equal the charge on the ion (S+6 O4-2 ) -8 +6 = -2 (S O4-2 ) -8 = -2 (S O4) = -2 (SO4)

7 Try these . . . hydroxide ammonium chromate

8 Try these answers. . . Hydroxide OH-1 O: -2 H: +1
ammonium NH N: -3 (b/c higher e-neg) H: +1 Chromate CrO Cr: +6 O: -2

9 Put it all together……. Assign oxidation states to each atom in the compound
KClO3 MnCr2O7 K2PtCl6

10 Put it all together……. answers
KClO3 K: +1 Cl: +5 O: -2 MnCr2O7 Mn: +2 Cr: +6 O:-2 K2PtCl6 K: +1 Pt: +4 Cl: -1

11 2Na + 2HOH 2NaOH + H2 Hydroxide polyatomic ion Recognizing RedOx
If the oxidation state changes for any of the atoms it is considered a RedOx reaction 2Na + 2HOH NaOH + H2 Hydroxide polyatomic ion

12 Single Replacement Reactions are ALWAYS RedOX
Double Replacement Reactions are NEVER RedOX

13 RedOx: Yes or NO? HCl + NaOH  HOH + NaCl Mg + 2HCl  MgCl2 + H2
MnO2 + 4HBr MnBr2 + Br2 + 2H2O

14 RedOx Definitions….

15 Metals tend to undergo oxidation
+3 +2 +1 -1 -2 -3 Oxidation results in an increase in oxidation state Atoms that Lose e-lectrons undergo Oxidation Metals tend to undergo oxidation

16 Non-metals tend to undergo reduction
+3 +2 +1 -1 -2 -3 Reduction results in a decrease in oxidation state Atoms which Gain e-lectrons undergo Reduction Non-metals tend to undergo reduction

17 GeR

18 oxidation and reduction
In a RedOx reaction If one atom is being oxidized another must be reduced. In other words . . . oxidation and reduction always occur together

19

20 Assign oxidation states to each atom. Is this a RedOx reaction?
Al + CuCl2 Cu + AlCl3 Assign oxidation states to each atom. Is this a RedOx reaction? What species is oxidized? Reduced? Write a balanced equation based on these reactants.

21 2Al + 3CuCl2  2AlCl3 + 3Cu Write a balanced equation based on these reactants. Is this a RedOx reaction? YES What species is oxidized? Al0 Reduced? Cu+2

22 Assign oxidation states to all atoms What species is oxidized?
MnO2 + 4HCl  MnCl2 + Cl2 + 2H2O Assign oxidation states to all atoms What species is oxidized? How do you know? What species is reduced?

23 Oxidation state increases from -1 to 0 Cl-1 loses electrons
MnO2 + 4HCl  MnCl2 + Cl2 + 2H2O What species is oxidized? Cl -1 How do you know? Oxidation state increases from -1 to 0 Cl-1 loses electrons What species is reduced? Mn+4 Oxidation state decreases from +4 to +2 Mn+4 loses electrons

24 RedOx Practice Losing e- oxidation Gain e- Reduction Remember . . . +4
+3 +2 +1 -1 -2 -3 -4 Losing e- oxidation Gain e- Reduction Remember . . .

25 Writing half-reactions
A half reaction shows either oxidation or reduction of a RedOx reaction. The electrons being lost (oxidation) or gained (reduction) are also shown.

26 Oxidation half-reaction example
Fe(s)  Fe+3(aq) + 3e- Fe0 gets oxidized electrons are lost products conservation of mass AND CHARGE charges on both sides equal each other

27 Reduction half-reaction example
Sn+4 + 2e-  Sn+2 Sn+4 gets reduced electrons are gained reactants conservation of mass AND CHARGE charges on both sides equal each other

28 Practice KMnO4 + HCl  MnCl2 + KCl + Cl2 + H2O
Assign oxidation states…. What species is oxidized? ½ rxn? What species is reduced? Where does the electron transfer take place?

29 Answers KMnO4 + HCl  MnCl2 + KCl + Cl2 + H2O
What species is oxidized? Cl-1 ½ rxn? Cl-1  Cl0 + 1e- or 2Cl-  Cl20 + 2e- What species is reduced? Mn+7 ½ rxn? Mn+7 + 3e-  Mn+4 Where does the electron transfer take place? Cl- loses e- to Mn+7

30 The End I came I saw I RedOxed


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