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Quadratic Simultaneous Equations

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Presentation on theme: "Quadratic Simultaneous Equations"β€” Presentation transcript:

1 Quadratic Simultaneous Equations
Grade 9 Advanced Algebra Quadratic Simultaneous Equations Lesson Objective: to recap how to solve linear simultaneous equations and how to solve simultaneous equations when one of them is quadratic

2 Quadratic Simultaneous Equations
Expand the brackets (3+π‘₯) 2 = 3+π‘₯ 3+π‘₯ (3+π‘₯) 2 =9+ π‘₯ 2 +6π‘₯ π‘₯ 2 + 𝑦 2 =29 π‘¦βˆ’π‘₯=3 quadratic linear Substitute this into here… π‘₯ π‘₯ 2 +6π‘₯=29 Tidy up the equation a little bit… Rearranging the linear equation… 2π‘₯ 2 +6π‘₯+9=29 𝑦=3+π‘₯ Prepare our equation so we can use The Quadratic Formula Substitute it into the quadratic equation π‘₯ 2 + (3+π‘₯) 2 =29 2π‘₯ 2 +6π‘₯βˆ’20=0

3 Quadratic Simultaneous Equations
2π‘₯ 2 +6π‘₯βˆ’20=0 Remember our original equations? π‘₯ 2 + 𝑦 2 =29 π‘¦βˆ’π‘₯=3 Substitute x = 5 or -2 into the second equation (it’s a lot easier!) a = 2 b = 6 c = -20 𝑦=βˆ’2 π‘œπ‘Ÿ 5 π‘₯= βˆ’6Β± βˆ’(4Γ—2Γ—βˆ’20 2Γ—2 Pair up your answers… π‘Šβ„Žπ‘’π‘› π‘₯=βˆ’5, 𝑦=βˆ’2 π‘Šβ„Žπ‘’π‘› π‘₯=2, 𝑦=5 π‘₯=βˆ’5 π‘œπ‘Ÿ 2

4 Independent Task π‘₯ 2 + 𝑦 2 =25 𝑦=π‘₯βˆ’7 Hints
Substitute the linear equation into the quadratic equation Expand the brackets Prepare your equation so you can use The Quadratic Formula Find two values for x Substitute your two values for x into the linear equation to find two values for y Pair up your answers

5 Quadratic Simultaneous Equations
π‘₯ 2 + 𝑦 2 =25 𝑦=π‘₯βˆ’7 quadratic Substituting into the quadratic equation linear π‘₯ 2 + π‘₯ 2 βˆ’14π‘₯+49=25 Tidy up the equation a little bit… Substitute the linear equation into the quadratic equation 2π‘₯ 2 βˆ’14π‘₯+49=25 π‘₯ 2 + (π‘₯βˆ’7) 2 =25 Prepare our equation so we can use The Quadratic Formula Expand the brackets (π‘₯βˆ’7) 2 = π‘₯βˆ’7 π‘₯βˆ’7 (π‘₯βˆ’7) 2 = π‘₯ 2 βˆ’14π‘₯+49 2π‘₯ 2 βˆ’14π‘₯+24=0

6 Quadratic Simultaneous Equations
2π‘₯ 2 βˆ’14π‘₯+24=0 Going back to our original equations… π‘₯ 2 + 𝑦 2 =25 𝑦=π‘₯βˆ’7 Substitute x = 3 or 4 into the linear equation a = 2 b = -14 c = 24 𝑦=βˆ’4 π‘œπ‘Ÿ βˆ’3 π‘₯= βˆ’(βˆ’14)Β± (βˆ’14) 2 βˆ’(4Γ—2Γ—24) 2Γ—2 Pair up your answers… π‘Šβ„Žπ‘’π‘› π‘₯=3 𝑦=βˆ’4 π‘Šβ„Žπ‘’π‘› π‘₯=4, 𝑦=βˆ’3 π‘₯=3 π‘œπ‘Ÿ 4

7 Quadratic Simultaneous Equations
π‘₯ 2 + 𝑦 2 =18 π‘¦βˆ’2π‘₯=3 π‘₯ 2 + 𝑦 2 =40 x+𝑦=4 π‘₯ 2 + 𝑦 2 =5 𝑦=3π‘₯+1 π‘₯ 2 + 𝑦 2 =13 xβˆ’2𝑦=1

8 Quadratic Simultaneous Equations
Solutions π‘₯=βˆ’3, 𝑦=βˆ’3 π‘₯=0.6, 𝑦=4.2 π‘₯=6, 𝑦=βˆ’2 π‘₯=βˆ’2, 𝑦=6 π‘₯=0.4, 𝑦=2.2 π‘₯=βˆ’1,𝑦=βˆ’2 π‘₯=βˆ’3, 𝑦=βˆ’2 π‘₯=3.4, 𝑦=1.2


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