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Exponential & Log Functions
Unit 13 Day 4
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Warm up! Solve: π₯+2 β 216 3π₯ = 1 216 A total of $12,000 is invested at an annual rate of 9%. Find the balance after 5 years if it is compounded a)Quarterly b)Monthly c)Continuously. Describe the transformations and graph: π¦= π₯β3 β2 π π₯ =β πππ 3 π₯β2 +4 X=-1/6 A=$18, A=$18, A=$18,819.75 a=2, b=1, h=3, k=0 a=-1, b=1, h=2, k=4
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Warm up answers π¦= π₯β3 β2 π π₯ =β πππ 3 π₯β2 +4
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Think-Ink-Pair-Share
How would you solveβ¦ 9 π₯ =49
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Changing Forms To change between exponential and logarithmic formsβ¦
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Changing Forms Examples
πππ 4 2=π₯ 4 π₯ =2 9 π₯ =3 πππ 9 3=π₯ ln π₯ =4 π 4 =π₯
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You Try! =8 πππ 4 8= 3 2 πππ =β2 4 β2 = 1 16
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Logarithmic Properties
loga1 = 0 (a0=1) Inverse Property loga ax = x loga a = 1 (a1=a) One-to-one property loga x = loga y then x = y also applies to exponential functions ax = ay then x = y
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Using the Properties Evaluate the following expressions ππ π 2 =
ππ π 2 = 2 πππ = -1 ln π 3π₯+4π¦ = 3x +4y
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You Try! Evaluate the following expressions π πππ₯ = πππ 5 5 3 =
πππ = 1.5 6 πππ 6 20π‘ = 20t
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Solving Exponential & Logarithmic Equations Example 1
Solve for x πππ 3 π₯=4 Change forms 3 4 =π₯ (on non-calculator part of test, this is an acceptable answer) π₯=81
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Solving Exponential & Logarithmic Equations Example 2 & 3
Solve for x ln π₯ =β3 Use the inverse property π₯= π β3 (exact answer/form) x=0.050 π π₯ =7 π₯= ln 7 ππ 1.95
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Solving Exponential & Logarithmic Equations Example 4
Solve for x ln π₯ β ln 3 =0 ln π₯ = ln (3) π₯=3
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Solving Exponential & Logarithmic Equations Example 5
How would you solve? π 2π₯ β3 π π₯ +2=0 πΉπππ‘ππ! π π₯ β1 π π₯ β2 =0 π π₯ β1 = π π₯ β2 =0 π π₯ = π π₯ =2 π₯= ln 1 =0 π₯= ln 2 =0.693
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You Try! Solve for x. πππ 2 π₯+3 β πππ 2 3π₯β4 =0
πππ 2 π₯+3 β πππ 2 3π₯β4 =0 7/2 or 3.5 log π₯=3 *remember log x = log10x x=1000 πππ 2 π₯ 2 +2π₯ = πππ 2 π₯+6 x=-3 x=2 π 2π₯ β3 π π₯ +2=0 x=ln4 2π₯ππ π₯ +π₯=0 π₯=0 π₯=π β1
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Solving Exponential & Logarithmic Equations Example 5Extraneous Solutions
Extraneous solutions occur when a solution is x = ln(c) and c β€ 0 Solve for x π 2π₯ β3 π π₯ β4=0 π π₯ +1 π π₯ β4 =0 π π₯ +1 = π π₯ β4 =0 π π₯ =β π π₯ =4 π₯= ln β π= π₯π§ π Extraneous!
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Applications Example 1 If you invest $500 at 6.75% compounded continuously, how long until it doubles? π΄=π π ππ‘ 1000=500 π π‘ 2= π (π‘) ln 2=0.0675π‘ t=10.27 years
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You Try! Applications If you invest $1000 for 7 years and now have $ , what was your interest rate (compounded continuously)? r = 5.99%
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Exit Ticket On a scale of 1 to 5 with 1 being βwere you speaking English?β 5 being βI totally got this!β How would you rate your understanding of todayβs lesson? Explain in a few words.
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