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Quarterly 3 Review.

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Presentation on theme: "Quarterly 3 Review."β€” Presentation transcript:

1 Quarterly 3 Review

2 2. Find the value of x: 2π‘₯ + 5 5 = π‘₯ + 10 4 .
The ratio of two supplementary angles is 4:5. Find the measure of the smaller angle. 2. Find the value of x: 2π‘₯ = π‘₯ smaller angle = 4x 4x + 5x = 180 smaller angle = 4 (20) 9x = 180 smaller angle = 80Β° x = 20 4(2x + 5) = 5(x + 10) 8x + 20 = 5x +50 3x = 30 x = 10

3 For #3-5, use the diagram below.
trapezoid ABCD is similar to trapezoid EHGF. 3. Find x. 4. Find y. π‘₯ 21 = 2 3 3π‘₯=42 x = 14 10 𝑦 = 2 3 y = 15 2𝑦=30 𝐴𝐡 𝐸𝐻 = 𝐡𝐢 𝐻𝐺 = 𝐢𝐷 𝐺𝐹 = 𝐴𝐷 𝐸𝐹 π‘₯ 21 = 𝐡𝐢 𝐻𝐺 = = 10 𝑦 Scale Factor = = 2 3

4 For #3-5, use the diagram below.
trapezoid ABCD is similar to trapezoid EHGF. 3. Find x. 4. Find y. 5. Find m∠A. x = 14 m∠𝐸=143Β° y = 15 π‘šβˆ π΄=π‘šβˆ πΈ π‘šβˆ π΅=π‘šβˆ π» π‘šβˆ πΆ=π‘šβˆ πΊ π‘šβˆ π·=π‘šβˆ πΉ m∠𝐴=143Β° ≫ ≫

5 For #6 and #7, use the diagram below. 𝐴𝐼 βˆ₯ 𝐷𝑆 6. Find x. 7. Find y.
𝐴𝐼 βˆ₯ 𝐷𝑆 6. Find x. 7. Find y. 𝑦 12 = = 3 π‘₯+3 3 π‘₯ + 3 = 5 13 π‘₯= = 4 4 5 39=5(π‘₯+3) 𝑦 12 = 5 13 𝑦= = 13𝑦=60

6 8. In isosceles βˆ†XYZ, π‘‹π‘Œ β‰… π‘Œπ‘ . m∠Y = 40Β°, find m∠X and m∠Z.
x + x + 40 = 180 Y 2x + 40 = 180 40° 2x = 140 x = 70 m∠X = 70° x° x° m∠Z = 70° X Z

7 9. βˆ†MON is similar to βˆ†QOP. Find the scale factor.
𝑀𝑂 𝑄𝑂 = 𝑂𝑁 𝑂𝑃 = 𝑀𝑁 𝑄𝑃 9 12 = = 𝑀𝑁 𝑄𝑃 9 12 = 3 4 = 3 4 Scale Factor is 3 4

8 10. Given: a βˆ₯ b βˆ₯ c Find x. = 21 π‘₯ 12x = 336 x = 28

9 AA similarity postulate
11. Are the triangles shown similar? If so, which postulate or theorem justifies the similarity. AA similarity postulate

10 For #12 and #13, WXYZ is a parallogram.
2y + 10 = 4y – 12 22 = 2y 11 = y 32Β° 148Β° y = 11 10x – 2 = 148 2y + 10 15 10x = 150 2(11) + 10 x = 15 11 32

11 14. In βˆ†XYZ, P and Q are midpoints of π‘‹π‘Œ and 𝑋𝑍
14. In βˆ†XYZ, P and Q are midpoints of π‘‹π‘Œ and 𝑋𝑍 . PQ = (5x + 2) and YZ = (3x + 18). Find PQ. 3x + 18 = 2(5x + 2) 3x + 18 = 10x + 4 18 = 7x + 4 7x = 14 x = 2 5x + 2 PQ = 5x + 2 PQ = 5(2) + 2 3x + 18 PQ = PQ = 12

12 15. ABCD is a trapezoid. 𝐸𝐹 is the median
15. ABCD is a trapezoid. 𝐸𝐹 is the median AB = (x – 3), EF = 10, and DC = (2x – 4). Find x. (x – 3) + (2x – 4) = 2(10) 3x – 7 = 20 3x = 27 x = 9 x – 3 10 2x – 4

13 16. The given figure is a parallelogram with its diagonals drawn, find the values of x and y.
2x + 6 = 26 4y – 10 = 6 2x = 20 4y = 16 x = 10 y = 4

14 17. Find x. 9x = 3x + 54 6x = 54 x = 9

15 18. A regular polygon has 18 sides
18. A regular polygon has 18 sides. Find the measure of each interior angle. π‘›βˆ’2 180 𝑛 18βˆ’ 160Β°

16 TRUE ; 8 + 8 > 15 TRUE TRUE For #19-21, answer TRUE or FALSE.
19. A triangle may have the sides measuring 8, 8, 15. 20. The diagonals of a rectangle are congruent. 21. All equilateral triangles are similar polygons. TRUE ; > 15 TRUE TRUE

17 22. If AM > AN, then m∠M ____ m∠N.
< 22. If AM > AN, then m∠M ____ m∠N. 5 4

18 23. L is the midpoint of 𝑀𝑁. ML = (2x + 3) and MN = (7x – 12). Find MN
23. L is the midpoint of 𝑀𝑁 . ML = (2x + 3) and MN = (7x – 12). Find MN. (Draw your own picture.) 2x + 3 ● M L N 7x – 12 2(2x + 3) = 7x – 12 MN = (7x – 12) MN = 7(6) – 12 4x + 6 = 7x – 12 MN = 42 – 12 18 = 3x MN = 30 6 = x x = 6

19 rotation translation reflection dilation
24. Draw an example of all the transformations for the figure below. rotation translation reflection dilation

20 For #25-27, use the diagram below. 25
For #25-27, use the diagram below. 25. Name a pair of alternate interior angles, a pair of same-side interior angles, and a pair of corresponding angles. alternate interior βˆ β€™s: ∠3 and ∠5 same-side interior ∠ β€² s: ∠3 and ∠4 corresponding βˆ β€™s: ∠2 and ∠5

21 26. Solve for x: m∠3 = (7x – 10)Β° and m∠4 = (15x – 8)Β°. 27
26. Solve for x: m∠3 = (7x – 10)Β° and m∠4 = (15x – 8)Β°. 27. Solve for y: m∠2 = ( 3(y – 4) )Β° and m∠5 = (y + 14)Β°. (7x – 10) + (15x – 8) = 180 22x – 18 = 180 22x = 198 x = 9 3(y – 4) = y + 14 3y – 12 = y + 14 2y = 26 y = 13

22 28. What type of transformation is shown below?
rotation

23 29. Write the definitions and draw a diagram of: Midpoint of a segment, Segment bisector, Median of a triangle, and Angle bisector. Midpoint of a segment – The point that divides the segment into two congruent segments. Segment bisector – A line, segment, ray, or plane that intersects the segment at its midpoint.

24 Median of a triangle – A segment from a vertex to the midpoint of the opposite side. Angle bisector – The ray that divides the angle into two congruent adjacent angles.

25 30. Given: 𝐴𝐢 βŠ₯ 𝐡𝐹 ; 𝐡𝐸 β‰… 𝐸𝐹 ; BAD  FAD Which of the following is the altitude, median, angle bisector of βˆ†ABF? altitude – 𝐴𝐢 median – 𝐴𝐸 angle bisector – 𝐴𝐷

26 31. Given: c βŠ₯ d. If m∠1 = (3x – 20)Β° and m∠2 = (5x + 6)Β°, find x.
(3x – 20) + (5x + 6) = 90 8x – 14 = 90 8x = 104 x = 13

27 32. Write a two-column proof
32. Write a two-column proof. Given: 𝐸𝐷 β‰… 𝐷𝐺 ; F is the midpoint 𝐸𝐺 Prove: ∠EDF β‰… ∠GDF Statements Reasons 1. 𝐸𝐷 β‰… 𝐷𝐺 1. Given 2. F is the midpoint of 𝐸𝐺 2. Given 3. 𝐸𝐹 β‰… 𝐹𝐺 3. Definition of midpoint 4. Reflexive property 4. 𝐷𝐹 β‰… 𝐷𝐹 5. SSS Post. 5. βˆ†EDF β‰… βˆ†GDF 6. CPCTC 6. ∠EDF β‰… ∠GDF


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