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Creating Polynomials Given the Zeros.

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Presentation on theme: "Creating Polynomials Given the Zeros."— Presentation transcript:

1 Creating Polynomials Given the Zeros.

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6 What do we already know about polynomial functions?
They are either ODD functions They are either EVEN functions Linear y = 4x - 5 Cubic y = 4x3 - 5 Quadratics y = 4x2 - 5 Quadratics y = 4x2 - 5 Fifth Power y = 4x5 –x + 5 Quartics y = 4x4 - 5

7 We know that factoring and then solving those factors set equal to zero allows us to find possible x intercepts. TOOLS WE’VE USED Long Division (works on all factors of any degree) Factoring GCF Quadratic Formula (x + )(x + ) Synthetic Division (works only with factors of degree 1) The “6” step Grouping Cubic** p/q

8 Zeros are x-intercepts if they are real
We know that solutions of polynomial functions can be rational, irrational or imaginary. X intercepts are real. Zeros are x-intercepts if they are real Zeros are solutions that let the polynomial equal 0

9 We have seen that imaginaries and square roots come in pairs ( + or -).
So we could CREATE a polynomial if we were given the polynomial’s zeros.

10 -1, 2, 4 (x+1)(x- 2)(x- 4) f(x) =x3 - 5x2 +2x + 8 x3 - 5x2 +2x + 8
Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1 and the given zeros. -1, 2, 4 Step 1: Turn the zeros into factors. (x+1)(x- 2)(x- 4) Step 2: Multiply the factors together. f(x) =x3 - 5x2 +2x + 8 x3 - 5x2 +2x + 8 Step 3: Name it!

11 Step 1: Turn the zeros into factors.
Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1 and the given zeros. Must remember that “i”s and roots come in pairs. Step 1: Turn the zeros into factors. Step 2: Multiply factors.

12 Step 1: Turn the zeros into factors.
Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1 and the given zeros. Step 1: Turn the zeros into factors. Must remember that “i”s and roots come in pairs. Step 2: Multiply factors.

13 x x x x x x x x (x2+ 4x + 1) (x2+ 4x + 3) x2 2x x2 2x ix 4 2i 2x 2x 4
-1 -3 (x2+ 4x + 1) (x2+ 4x + 3)

14 x2+ 4x + 3 f(x) = x4+ 8x3 + 20x2 +16x + 3 x4 4x3 3x2 4x3 16x2 12x x2
-3


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