Presentation is loading. Please wait.

Presentation is loading. Please wait.

Chemical/physical changes in the lab are open to atmosphere, so the changes occur at a constant pressure Heat content of a system at constant pressure.

Similar presentations


Presentation on theme: "Chemical/physical changes in the lab are open to atmosphere, so the changes occur at a constant pressure Heat content of a system at constant pressure."— Presentation transcript:

1 Calorimetry Remember… Heat released by system = Heat absorbed by surroundings

2 Chemical/physical changes in the lab are open to atmosphere, so the changes occur at a constant pressure Heat content of a system at constant pressure is called enthalpy, H Heat released or absorbed by system at constant pressure is the change in enthalpy, (∆H)

3 The reactions we look at are at constant pressure so q = ∆H
∆H is positive = ___________ ∆H is negative = ___________ qsys = ∆H = -qsurr = - m x C x ∆T

4 When 25 mL of water containing mol HCl at 25.0°C is added to 25.0 mL of water containing mol NaOH at 25.0°C in a foam cup calorimeter, a reaction occurs. Calculate the enthalpy change in kJ during this reaction if the highest temperature observed is 32.0°C. Assume the densities of the solutions are 1.00 g/mL.

5 Thermochemical Equations Show enthalpy change in the reaction
CaO + H2O  Ca(OH)2 + heat In a chem. rxn. ∆H for the rxn. can be written as product or reactant 2NaHCO  Na2CO3 + H2O + CO2 **absorbs 129 kJ of heat

6 The enthalpy change for the chemical equation exactly as it’s written
Heat of Reaction The enthalpy change for the chemical equation exactly as it’s written As ∆H (heat flow at constant pressure) q, + /- CaO H2O  Ca(OH) k J

7

8 Calculating Enthalpy Changes in a Reaction
2NaHCO kJ  Na2CO3 + H2O + CO2 What do we know from the equation?

9 2NaHCO kJ  Na2CO3 + H2O + CO2 How much heat would be needed to decompose 2.24 mol NaHCO3? How much heat would be absorbed in decomposing 9.0 g of NaHCO3?

10 If a piece of gold (C = 0. 129 J/g°C) with a mass of 45
If a piece of gold (C = J/g°C) with a mass of 45.5 g and a temperature of 80.5°C is dropped into 192 g of water at 15.0°C, what is the final temperature of the system?

11 Assigned problems on Worksheet
Homework Assigned problems on Worksheet Pg # 14, 15 Pg # 16-19


Download ppt "Chemical/physical changes in the lab are open to atmosphere, so the changes occur at a constant pressure Heat content of a system at constant pressure."

Similar presentations


Ads by Google