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Chain Rule AP Calculus.

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Presentation on theme: "Chain Rule AP Calculus."β€” Presentation transcript:

1 Chain Rule AP Calculus

2 𝑦= ( 2π‘₯ 2 +3π‘₯βˆ’1) 8 Differentiate

3 𝑦= ( 2π‘₯ 2 +3π‘₯βˆ’1) 8 𝑦 β€² =8 ( 2π‘₯ 2 +3π‘₯βˆ’1) 7 (4x+3)
Differentiate

4 𝑦= cos 3π‘₯ Find the derivative

5 𝑦= cos 3π‘₯ y’ = -sin 3x βˆ™3 y’ = -3 sin 3x
Find the derivative

6 𝑦= 1 ( 2π‘₯ 5 βˆ’7) 3 y = ( 2π‘₯ 5 βˆ’7) βˆ’3 dy/dx = βˆ’3 ( 2π‘₯ 5 βˆ’7) βˆ’4 βˆ™ 10π‘₯ 4 = βˆ’30 π‘₯ 4 ( 2π‘₯ 5 βˆ’7) βˆ’4
Find dy/dx

7 𝑓 π‘₯ = 2π‘₯+1 π‘₯ Find the derivative

8 𝑓 π‘₯ = 2π‘₯+1 π‘₯ = 2 + 1 π‘₯ = 2 + π‘₯ βˆ’1 f’(x) = βˆ’ π‘₯ βˆ’2
Find the derivative

9 𝑔 π‘₯ =sin⁑( π‘₯ 2 +1) Differentiate

10 𝑔 π‘₯ =sin⁑( π‘₯ 2 +1) gβ€˜(x) = cos( π‘₯ 2 +1)βˆ™2π‘₯ = 2x cos( π‘₯ 2 +1)
Differentiate

11 𝑦= 𝑠𝑖𝑛 4 π‘₯ Find y’

12 𝑦= 𝑠𝑖𝑛 4 π‘₯ y = ( sin π‘₯) 4 yβ€˜ = 4 ( sin π‘₯) 3 βˆ™ cos π‘₯
Find y’

13 𝑓 π‘₯ = π‘π‘œπ‘  2 3π‘₯ Find the derivative

14 𝑓 π‘₯ = π‘π‘œπ‘  2 3π‘₯ f’(x) = 2(cos 3x) βˆ™(βˆ’ sin 3π‘₯)βˆ™3 f’(x) = -6sin 3x cos 3x
Find the derivative


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