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Yet another important mathematical concept

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1 Yet another important mathematical concept
Functions Yet another important mathematical concept

2 Functions Most basic representation: Arrow Diagrams B A 𝑓

3 Functions Most basic representation: Arrow Diagrams
A is called the domain and B is called the co-domain and we say that β€œf is such that it maps elements from A to B” (𝑓:𝐴↦𝐡) B A 𝑓 Linger on this

4 Functions Most basic representation: Arrow Diagrams
A is called the domain and B is called the co-domain and we say that β€œf is such that it maps elements from A to B” (𝑓:𝐴↦𝐡) B A 𝑓 \mapsto in LaTeX

5 Example 1 Yes No Is this a function? A B 𝑓 1 2 4 3

6 Example 1 Yes No Is this a function? 𝑓 A B Domain: {0, 1, 2, 3, 4}
Co-domain: {0, 1, 4} Formula (that we came up with): 𝑓 π‘₯ = π‘₯ 2 % 5 (where % is the MOD operation) A B 𝑓 1 2 4 3

7 Example 2 Yes No Is this a function? A B 1 2 4 3

8 Example 2 Yes No Is this a function? 3 A B
Every element of the domain should map to some co-domain element! A B 1 2 4 3

9 Example 3 Yes No Is this a function? 𝑓:ℕ↦ℕ, and 𝑓 π‘₯ = π‘₯ 2

10 Example 3 Yes No Is this a function? 𝑓:ℕ↦ℕ, and 𝑓 π‘₯ = π‘₯ 2
For any odd selection of π‘₯βˆˆβ„•, there is no π‘₯ 2 ∈ β„•!

11 Arrow Diagrams: Pros and Cons
Good for introducing functions as mappings No information on other function properties (continuous, integrable, monotonic, …) Help us decouple functions from other mappings in 𝐴 ×𝐡 Only possible for functions with small, finite domains and co-domains Clarify what the domain and what the co-domain is …. Good for teaching us what onto and 1-1 means …

12 Arrow Diagrams: Pros and Cons
Good for introducing functions as mappings No information on other function properties (continuous, integrable, monotonic, …) Help us decouple functions from other mappings in 𝐴 ×𝐡 Only possible for functions with small, finite domains and co-domains Clarify what the domain and what the co-domain is … Good for teaching us what onto and 1-1 means Those are important cons….

13 Graphs We can also represent functions by their graphs…

14 (β€œvertical line test”)
Graphs (pros,cons) Which has its owns pros and cons Pros Cons Easy to determine 1-1 functions (β€œhorizontal line test”) Cannot compute the derivative at any point, only draw it Easy to determine non-functions (β€œvertical line test”) Cannot compute the value of the function at any point Can determine monotonicity and continuity easily Cannot compute the indefinite integral of the function Can easily determine if the function intersects the axes Cannot determine where it intersects the axes …

15 Short quiz

16 Short quiz Yes No Are the following valid functions?

17 Short quiz Yes No Are the following valid functions?

18 Short quiz Yes No Are the following valid functions? Log function

19 Short quiz Yes No Are the following valid functions?

20 Short quiz Yes No Fails the β€œvertical line” test
Are the following valid functions? Fails the β€œvertical line” test

21 Short quiz Yes No Are the following valid functions? B A 𝑓

22 Short quiz Yes No Are the following valid functions? 𝑓 B A
It just happens to not be β€œ1-1” (term we’ll explain momentarily)!

23 Function formulae Yes No Are the following valid functions? B A 𝑓

24 Function formulae Yes No
Are the following valid functions? B A 𝑓 Fails the β€œvertical line” test (2 different `y’s mapped to by the same `x’)

25 Surjective functions A function 𝑓:π‘‹β†¦π‘Œ is called surjective (or onto) iff βˆ€π‘¦βˆˆπ‘Œ, βˆƒπ‘₯βˆˆπ‘‹:𝑓 π‘₯ =𝑦

26 Surjective functions A function 𝑓:π‘‹β†¦π‘Œ is called surjective (or onto) iff βˆ€π‘¦βˆˆπ‘Œ, βˆƒπ‘₯βˆˆπ‘‹:𝑓 π‘₯ =𝑦 Intuitively: 𝑓 β€² 𝑠 co-domain is β€œfull” with pointers

27 Surjective functions A function 𝑓:π‘‹β†¦π‘Œ is called surjective (or onto) iff βˆ€π‘¦βˆˆπ‘Œ, βˆƒπ‘₯βˆˆπ‘‹:𝑓 π‘₯ =𝑦 Intuitively: 𝑓 β€² 𝑠 co-domain is β€œfull” with pointers Mnemonic rule to remember the name β€œsurjective”: in French, β€œsur” means β€œabove”, β€œon”, or β€œonto”.

28 Surjective functions A function 𝑓:π‘‹β†¦π‘Œ is called surjective (or onto) iff βˆ€π‘¦βˆˆπ‘Œ, βˆƒπ‘₯βˆˆπ‘‹ [𝑓 π‘₯ =𝑦] Intuitively: 𝑓 β€² 𝑠 co-domain is β€œfull” with pointers Mnemonic rule to remember the name β€œsurjective”: in French, β€œsur” means β€œabove”, β€œon”, or β€œonto”. β€œsur”

29 Quiz on surjectivity Yes No Something Else Is 𝑓 π‘₯ = π‘₯ 2 surjective?

30 Quiz on surjectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 surjective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 surjective? We have not provided you with either the domain or the co-domain!

31 Quiz on surjectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 surjective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 surjective? We have not provided you with either the domain or the co-domain! 𝐷=ℝ, 𝐢=ℝ: Non-Surjective! (e.g -1 is not mapped to)

32 Quiz on surjectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 surjective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 surjective? We have not provided you with either the domain or the co-domain! 𝐷=ℝ, 𝐢=ℝ: Non-Surjective! (e.g -1 is not mapped to) 𝐷=ℝ,𝐢= ℝ β‰₯0 : Surjective!

33 Quiz on surjectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 surjective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 surjective? We have not provided you with either the domain or the co-domain! 𝐷=ℝ, 𝐢=ℝ: Non-Surjective! (e.g -1 is not mapped to) 𝐷=ℝ,𝐢= ℝ β‰₯0 : Surjective! 𝐷=β„•,𝐢=? such that it is surjective?

34 Quiz on surjectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 surjective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 surjective? We have not provided you with either the domain or the co-domain! 𝐷=ℝ, 𝐢=ℝ: Non-Surjective! (e.g -1 is not mapped to) 𝐷=ℝ,𝐢= ℝ β‰₯0 : Surjective! 𝐷=β„•,𝐢=π‘†π‘„π‘ˆπ΄π‘…πΈπ‘†: Surjective!

35 Injective functions A function 𝑓:π‘‹β†¦π‘Œ is called injective (or 1-1) iff
(βˆ€ π‘₯ 1 , π‘₯ 2 βˆˆπ‘‹) [𝑓 π‘₯ 1 =𝑓 π‘₯ 2 β‡’ π‘₯ 1 = π‘₯ 2 ] Intuitively: Every element of the co-domain is mapped to by at most one element of the domain.

36 Injective functions A function 𝑓:π‘‹β†¦π‘Œ is called injective (or 1-1) iff
(βˆ€ π‘₯ 1 , π‘₯ 2 βˆˆπ‘‹) [𝑓 π‘₯ 1 =𝑓 π‘₯ 2 β‡’ π‘₯ 1 = π‘₯ 2 ] Intuitively: Every element of the co-domain is mapped to by at most one element of the domain. Why β€œat most one” and not exactly one?

37 Injective functions A function 𝑓:π‘‹β†¦π‘Œ is called injective (or 1-1) iff
(βˆ€ π‘₯ 1 , π‘₯ 2 βˆˆπ‘‹) [𝑓 π‘₯ 1 =𝑓 π‘₯ 2 β‡’ π‘₯ 1 = π‘₯ 2 ] Intuitively: Every element of the co-domain is mapped to by at most one element of the domain. Why at most one and not exactly one? Because 1-1 but not onto functions are possible! X Y 𝑓

38 Quiz on injectivity Yes No Something Else Is 𝑓 π‘₯ = π‘₯ 2 injective?

39 Quiz on injectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 injective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 injective? We need domains and codomains!

40 Quiz on injectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 injective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 injective? We need domains and codomains! 𝐷=ℝ, 𝐢=ℝ: Non-Injective! (e.g βˆ’3 2 = 3 2 =9)

41 Quiz on injectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 injective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 injective? We need domains and codomains! 𝐷=ℝ, 𝐢=ℝ: Non-Injective! (e.g βˆ’3 2 = 3 2 =9) 𝐷=ℝ,𝐢= ℝ β‰₯0 : Nonβˆ’Injective! (same example works)

42 Quiz on injectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 injective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 injective? We need domains and codomains! 𝐷=ℝ, 𝐢=ℝ: Non-Injective! (e.g βˆ’3 2 = 3 2 =9) 𝐷=ℝ,𝐢= ℝ β‰₯0 : Nonβˆ’Injective! (same example works) 𝐷=β„€,𝐢=π‘†π‘„π‘ˆπ΄π‘…πΈπ‘†: Nonβˆ’Injective! (same example works)

43 Quiz on injectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 injective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 injective? We need domains and codomains! 𝐷=ℝ, 𝐢=ℝ: Non-Injective! (e.g βˆ’3 2 = 3 2 =9) 𝐷=ℝ,𝐢= ℝ β‰₯0 : Nonβˆ’Injective! (same example works) 𝐷=β„€,𝐢=π‘†π‘„π‘ˆπ΄π‘…πΈπ‘†: Nonβˆ’Injective! (same example works) Can this function ever be injective?

44 Quiz on injectivity Yes No Is 𝑓 π‘₯ = π‘₯ 2 injective?
Something Else Is 𝑓 π‘₯ = π‘₯ 2 injective? We need domains and codomains! 𝐷=ℝ, 𝐢=ℝ: Non-Injective! (e.g βˆ’3 2 = 3 2 =9) 𝐷=ℝ,𝐢= ℝ β‰₯0 : Nonβˆ’Injective! (same example works) 𝐷=β„€,𝐢=π‘†π‘„π‘ˆπ΄π‘…πΈπ‘†: Nonβˆ’Injective! (same example works) Can this function ever be injective? Yes. Pick 𝐷=β„•,𝐢=π‘†π‘„π‘ˆπ΄π‘…πΈπ‘†

45 Making functions onto or 1-1
To make a function onto, we need to make the co-domain smaller. To make a function 1-1 , we need to make the domain smaller.

46 Bijective functions A function 𝑓:π‘‹β†¦π‘Œ is called bijective (or a bijection, or a 1- 1 correspondence) iff it is both surjective and injective. We will try to avoid using the term β€œ1-1 correspondence” (your book uses it) since it can confuse us with the notion of an injective (or 1-1) function.

47 Quiz on bijections

48 Quiz on bijections Yes No Are the following functions bijections?
(In all examples, 𝐢=ℝ)

49 Quiz on bijections Yes No Are the following functions bijections?
𝑓 π‘₯ = π‘₯ , π‘₯βˆˆβ„ (In all examples, 𝐢=ℝ)

50 Quiz on bijections Yes No Are the following functions bijections?
(In all examples, 𝐢=ℝ) Non-injective!

51 Quiz on bijections Yes No Are the following functions bijections?
𝑓 π‘₯ = π‘₯ , π‘₯βˆˆβ„ 𝑓 π‘₯ =π‘Žβ‹…π‘₯+𝑏, π‘Ž,π‘₯,π‘βˆˆβ„ (In all examples, 𝐢=ℝ)

52 Quiz on bijections Yes No
Are the following functions bijections? 𝑓 π‘₯ = π‘₯ , π‘₯βˆˆβ„ No 𝑓 π‘₯ =π‘Žβ‹…π‘₯+𝑏, π‘Ž,π‘₯,π‘βˆˆβ„ No (In all examples, 𝐢=ℝ) !!!! For a = 0, the graph of the function fails the β€œhorizontal line test”!

53 Quiz on bijections Yes No Are the following functions bijections?
𝑔 π‘₯ = π‘Žβ‹…π‘₯ 2 , π‘Ž,π‘₯∈ ℝ, π‘Ž>0 (In all examples, 𝐢=ℝ)

54 Quiz on bijections Yes No Are the following functions bijections?
(In all examples, 𝐢=ℝ) Non-injective!

55 Quiz on bijections Yes No Are the following functions bijections?
β„Ž 𝑛 =4𝑛 βˆ’1, π‘›βˆˆβ„€ (In all examples, 𝐢=ℝ)

56 Quiz on bijections Yes No Are the following functions bijections?
(In all examples, 𝐢=ℝ) Non-surjective! Set β„Ž 𝑛 =𝑦 and solve for 𝑛: 4𝑛 – 1 = 𝑦⇒𝑛= 𝑦+1 4 There are infinitely many choices of 𝑦 for which π‘›βˆ‰β„€!

57 Quiz on bijections Yes No Are the following functions bijections?
β„Ž π‘₯ =4π‘₯ βˆ’1, π‘₯βˆˆβ„ (In all examples, 𝐢=ℝ)

58 Quiz on bijections Yes No Are the following functions bijections?
(In all examples, 𝐢=ℝ) Surjective and injective! Surjective, since, if we set β„Ž 𝑛 =𝑦 and solve for 𝑛: 4𝑛 – 1 = 𝑦⇒𝑛= 𝑦+1 4 For every real 𝑦, there’s always a real solution 𝑛. Injective, since it’s of the form of (2) with π‘Žβ‰ 0.

59 Some interesting functions
We will examine a pair of interesting functions from ℝ to β„€. Given a real number π‘Ÿ, the floor of π‘Ÿ, denoted π‘Ÿ is the largest integer 𝑛:π‘›β‰€π‘Ÿ.

60 Floor and ceiling We will examine a pair of interesting functions from ℝ to β„€. Given a real number π‘Ÿ, the floor of π‘Ÿ, denoted π‘Ÿ is the largest integer 𝑛:π‘›β‰€π‘Ÿ. Given a real number π‘Ÿ, the ceiling of π‘Ÿ, denoted βŒˆπ‘ŸβŒ‰ is the smallest integer 𝑛:𝑛β‰₯π‘Ÿ.

61 Floor and ceiling We will examine a pair of interesting functions from ℝ to β„€. Given a real number π‘Ÿ, the floor of π‘Ÿ, denoted π‘Ÿ is the largest integer 𝑛:π‘›β‰€π‘Ÿ. Given a real number π‘Ÿ, the ceiling of π‘Ÿ, denoted βŒˆπ‘ŸβŒ‰ is the smallest integer 𝑛:𝑛β‰₯π‘Ÿ. ⌊ π‘Ÿ 1 βŒ‹ ⌈ π‘Ÿ 1 βŒ‰ ⌊ π‘Ÿ 2 βŒ‹ ⌈ π‘Ÿ 2 βŒ‰ -4 -3 -2 -1 1 2 3 4 5 6 7 π‘Ÿ 1 π‘Ÿ 2

62 Examples 1.3 =1

63 Examples 1.3 =1 10.3 =10

64 Examples 1.3 =1 10.3 =10 0.8 =1

65 Examples 1.3 =1 10.3 =10 0.8 =1 …1 =1

66 Examples 1.3 =1 10.3 =10 0.8 =1 …1 =1 βˆ’5.6 =βˆ’5 At this point, might be worth mentioning that those functions are not injective!

67 Examples From these two we can deduce… 1.3 =1 10.3 =10 0.8 =1
…1 =1 βˆ’5.6 =βˆ’5 From these two we can deduce… At this point, might be worth mentioning that those functions are not injective!

68 Examples From these two we can deduce… that floor is non-injective!
1.3 =1 10.3 =10 0.8 =1 …1 =1 βˆ’5.6 =βˆ’6 From these two we can deduce… that floor is non-injective! (same for ceiling, of course) At this point, might be worth mentioning that those functions are not injective!

69 Vote! 3 = 3 2 4 3.5

70 Vote! 3 =3 πœ‹ = 3 2 4 3.5 3 πœ‹ 4 3.5

71 Vote! 3 2 4 3.5 3 =3 πœ‹ = 4 2 500 Γ— = 3 πœ‹ 4 3.5 2 500 Γ—500 2 500 Γ— Γ— 500 2 2 499 Γ— 500 2 Something else

72 Vote! 3 2 4 3.5 3 =3 πœ‹ = 4 2 500 Γ— = Γ— 500 2 βˆ€π‘›βˆˆβ„€, 𝑛 = 𝑛 =𝑛 3 πœ‹ 4 3.5 2 500 Γ—500 2 500 Γ— Γ— 500 2 2 499 Γ— 500 2 Something else T 𝐹

73 Vote! 3 =3 πœ‹ = 4 βˆ€π‘›βˆˆβ„€, 𝑛 = 𝑛 =𝑛 T βˆ€π‘›βˆˆβ„€, 𝑛 = 𝑛 =𝑛 3 2 4 3.5 3 πœ‹ 4 3.5 T
3 =3 πœ‹ = 4 2 500 Γ— = Γ— 500 2 βˆ€π‘›βˆˆβ„€, 𝑛 = 𝑛 =𝑛 T βˆ€π‘›βˆˆβ„€, 𝑛 = 𝑛 =𝑛 3 πœ‹ 4 3.5 2 500 Γ—500 2 500 Γ— Γ— 500 2 2 499 Γ— 500 2 Something else T 𝐹 T 𝐹

74 Vote! 3 =3 πœ‹ = 4 βˆ€π‘›βˆˆβ„€, 𝑛 = 𝑛 =𝑛 T βˆ€π‘›βˆˆβ„€, 𝑛 = 𝑛 =𝑛 T 3 2 4 3.5 3 πœ‹ 4 3.5
3 =3 πœ‹ = 4 2 500 Γ— = Γ— 500 2 βˆ€π‘›βˆˆβ„€, 𝑛 = 𝑛 =𝑛 T βˆ€π‘›βˆˆβ„€, 𝑛 = 𝑛 =𝑛 T 3 πœ‹ 4 3.5 2 500 Γ—500 2 500 Γ— Γ— 500 2 2 499 Γ— 500 2 Something else T 𝐹 T 𝐹

75 Relations

76 Functions ultra-formally
Consider the function that we talked about before: A B 𝑓 1 2 4 3

77 Functions ultra-formally
Consider the function that we talked about before: Can view it as the set of ordered pairs { 0,0 , 1,1 , 2,4 , 3,4 , (4, 1)} A B 𝑓 1 2 4 3

78 Functions ultra-formally
Let 𝐴, 𝐡 be sets. A function 𝑓:𝐴↦𝐡 is any subset 𝑆=𝐴 Γ— 𝐡 where βˆ€π‘Žβˆˆπ΄ [ βˆƒπ‘βˆˆπ΅ π‘Ž, 𝑏 βˆˆπ‘† ] (every element of the domain maps somewhere) βˆ€π‘Žβˆˆπ΄ [ βˆƒ 𝑏 1 ∈𝐡 π‘Ž, 𝑏 1 βˆˆπ‘† βˆ§βˆ€ 𝑏 2 β‰  𝑏 1 π‘Ž, 𝑏 2 βˆ‰π‘† ] (every element of the domain maps to exactly one element of the co-domain)

79 Functions ultra-formally
Let 𝐴, 𝐡 be sets. A function 𝑓:𝐴↦𝐡 is any subset 𝑆=𝐴 Γ— 𝐡 where βˆ€π‘Žβˆˆπ΄ [ βˆƒπ‘βˆˆπ΅ π‘Ž, 𝑏 βˆˆπ‘† ] (every element of the domain maps somewhere) βˆ€π‘Žβˆˆπ΄ [ βˆƒ 𝑏 1 ∈𝐡 π‘Ž, 𝑏 1 βˆˆπ‘† βˆ§βˆ€ 𝑏 2 β‰  𝑏 1 π‘Ž, 𝑏 2 βˆ‰π‘† ] (every element of the domain maps to exactly one element of the co-domain) We generalize the notion of a function to that of a relation! Any subset of 𝐴 Γ— 𝐡 that doesn’t abide by (1) or (2) we call a relation from A to B.

80 Examples (<, ℝ×ℝ) {…, βˆ’1.5, βˆ’1.2 , βˆ’1.4,βˆ’1.2 , 2 , 3 , 2 , 5 ,…}
{…, βˆ’1.5, βˆ’1.2 , βˆ’1.4,βˆ’1.2 , 2 , 3 , 2 , 5 ,…} Verbally tell them that is is β€œless than” on R^2

81 Examples (<, ℝ×ℝ) ≀,ℝ×ℝ
{…, βˆ’1.5, βˆ’1.2 , βˆ’1.4,βˆ’1.2 , 2 , 3 , 2 , 5 ,…} ≀,ℝ×ℝ {…, 2, 2 , 2, 2.1 , 2 , 3 , 2 , 5 ,…}

82 Examples (<, ℝ×ℝ) ≀,ℝ×ℝ 𝐡𝑖𝑙𝑙, ℝ×ℕ
{…, βˆ’1.5, βˆ’1.2 , βˆ’1.4,βˆ’1.2 , 2 , 3 , 2 , 5 ,…} ≀,ℝ×ℝ {…, 2, 2 , 2, 2.1 , 2 , 3 , 2 , 5 ,…} 𝐡𝑖𝑙𝑙, ℝ×ℕ { π‘Ÿ, 𝑛 | 𝑛 appears in the decimal expansion of π‘Ÿ } E.g: {…, πœ‹, 1 , 𝑒, 7 , , 4 , …} We would formally say that all of the above are elements of the relation β€œBill” Verbally state the names of the other relations.

83 Reflexivity A relation XβŠ†π΄ Γ— 𝐴 is reflexive if βˆ€π‘Žβˆˆπ΄ [ π‘Ž, π‘Ž βˆˆπ‘‹ ]

84 Reflexivity A relation XβŠ†π΄ Γ— 𝐴 is reflexive if βˆ€π‘Žβˆˆπ΄ π‘Ž, π‘Ž βˆˆπ‘‹ Examples:
βˆ€π‘Žβˆˆπ΄ π‘Ž, π‘Ž βˆˆπ‘‹ Examples: (≀,β„•Γ—β„•) is reflexive, since βˆ€π‘›βˆˆβ„• 𝑛≀𝑛 (<,β„•Γ—β„•) is not reflexive, since ∼ βˆ€π‘›βˆˆβ„• 𝑛<𝑛 (in fact, there is no such 𝑛) (π½π‘Žπ‘ π‘œπ‘›,β„•Γ—β„•) defined as { π‘₯, 𝑦 | π‘₯+𝑦β‰₯100} is not reflexive (e.g 10, 10 βˆ‰π½π‘Žπ‘ π‘œπ‘›)) Say verbally that one needs only one counter-example (a forall statement can be proven negative with just one witness)

85 Symmetry A relation XβŠ†π΄ Γ— 𝐴 is symmetric if
βˆ€ π‘Ž 1 , π‘Ž 2 ∈𝐴 π‘Ž 1 , π‘Ž 2 βˆˆπ‘‹ β‡’ π‘Ž 2 , π‘Ž 1 βˆˆπ‘‹)

86 Symmetry A relation XβŠ†π΄ Γ— 𝐴 is symmetric if
βˆ€ π‘Ž 1 , π‘Ž 2 ∈𝐴 π‘Ž 1 , π‘Ž 2 βˆˆπ‘‹ β‡’ π‘Ž 2 , π‘Ž 1 βˆˆπ‘‹) Examples: (≀,β„•Γ—β„•) is not symmetric since 4≀5 but ∼(5≀4) (<,β„•Γ—β„•) is not symmetric (see above) (π½π‘Žπ‘ π‘œπ‘›,β„•Γ—β„•) defined as { π‘₯, 𝑦 | π‘₯+𝑦β‰₯100} is symmetric since π‘₯+𝑦≀100 β‡’(𝑦+π‘₯≀100)

87 βˆ€ π‘Ž 1 , π‘Ž 2 , π‘Ž 3 ∈𝐴 π‘Ž 1 , π‘Ž 2 βˆˆπ‘‹ ∧( π‘Ž 2 , π‘Ž 3 βˆˆπ‘‹)β‡’ π‘Ž 1 , π‘Ž 3 βˆˆπ‘‹)
Transitivity A relation XβŠ†π΄ Γ— 𝐴 is transitive if βˆ€ π‘Ž 1 , π‘Ž 2 , π‘Ž 3 ∈𝐴 π‘Ž 1 , π‘Ž 2 βˆˆπ‘‹ ∧( π‘Ž 2 , π‘Ž 3 βˆˆπ‘‹)β‡’ π‘Ž 1 , π‘Ž 3 βˆˆπ‘‹)

88 βˆ€ π‘Ž 1 , π‘Ž 2 , π‘Ž 3 ∈𝐴 π‘Ž 1 , π‘Ž 2 βˆˆπ‘‹ ∧( π‘Ž 2 , π‘Ž 3 βˆˆπ‘‹)β‡’ π‘Ž 1 , π‘Ž 3 βˆˆπ‘‹)
Transitivity A relation XβŠ†π΄ Γ— 𝐴 is transitive if βˆ€ π‘Ž 1 , π‘Ž 2 , π‘Ž 3 ∈𝐴 π‘Ž 1 , π‘Ž 2 βˆˆπ‘‹ ∧( π‘Ž 2 , π‘Ž 3 βˆˆπ‘‹)β‡’ π‘Ž 1 , π‘Ž 3 βˆˆπ‘‹) (≀,β„•Γ—β„•) is transitive since π‘₯≀𝑦 ∧ 𝑦≀𝑧 β‡’ π‘₯≀𝑧 (<,β„•Γ—β„•) is transitive (see above) (π½π‘Žπ‘ π‘œπ‘›,β„•Γ—β„•) defined as { π‘₯, 𝑦 | π‘₯+𝑦β‰₯100} ???

89 Transitivity A relation XβŠ†π΄ Γ— 𝐴 is transitive if
βˆ€ π‘Ž 1 , π‘Ž 2 , π‘Ž 3 ∈𝐴 π‘Ž 1 , π‘Ž 2 βˆˆπ‘‹ ∧( π‘Ž 2 , π‘Ž 3 βˆˆπ‘‹)β‡’ π‘Ž 1 , π‘Ž 3 βˆˆπ‘‹) (≀,β„•Γ—β„•) is transitive since π‘₯≀𝑦 ∧ 𝑦≀𝑧 β‡’ π‘₯≀𝑧 (<,β„•Γ—β„•) is transitive (see above) (π½π‘Žπ‘ π‘œπ‘›,β„•Γ—β„•) defined as { π‘₯, 𝑦 | π‘₯+𝑦β‰₯100} is not transitive since (counter-example): 1, 100 βˆˆπ½π‘Žπ‘ π‘œπ‘›βˆ§ 100, 5 βˆˆπ½π‘Žπ‘ π‘œπ‘› but 1, 5 βˆ‰π½π‘Žπ‘ π‘œπ‘›


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