Presentation is loading. Please wait.

Presentation is loading. Please wait.

BIBD and Adjusted Sums of Squares

Similar presentations


Presentation on theme: "BIBD and Adjusted Sums of Squares"— Presentation transcript:

1 BIBD and Adjusted Sums of Squares
Type I and Type III Sums of Squares

2 Confounding in Unbalanced Designs
When designs are “unbalanced”, typically with missing values, our estimates of Treatment Effects can be biased. When designs are “unbalanced”, the usual computation formulas for Sums of Squares can give misleading results, since some of the variability in the data can be explained by two or more variables.

3 Example BIBD from Hicks
See what happens with the correct model if we compare means of Treatment A and Treatment B.

4 What would be a simple linear model and what does it say about any treatment mean comparison?
Notation for layout and model.

5 Suppose we want to compare treatment 1 to treatment 2?
The model says that if we compare averages, then we get a possible bias due to block.

6 Type I vs. Type III in partitioning variation
If an experimental design is not a balanced and complete factorial design, it is not an orthogonal design. If a two factor design is not orthogonal, then the SSModel will not partition into unique components, i.e., some components of variation may be explained by either factor individually (or simultaneously). Type I SS are computing according to the order in which terms are entered in the model. Type III SS are computed in an order independent fashion, i.e. each term gets the SS as though it were the last term entered for Type I SS.

7 If BIBD, design is unbalanced and some variation may be explained by either factor.
If we use a Venn diagram:

8 Notation for Hicks’ example
There are only two possible factors, Block and Trt. There are only three possible simple additive models one could run. In SAS syntax they are: Model 1: Model Y=Block; Model 2: Model Y=Trt; Model 3: Model Y=Block Trt; Put Venn diagram on board for reference.

9 Adjusted SS notation Each model has its own “Model Sums of Squares”.
These are used to derive the “Adjusted Sums of Squares”. SS(Block)=Model Sums of Squares for Model 1 SS(Trt)=Model Sums of Squares for Model 2 SS(Block,Trt)=Model Sums of Squares for Model 3

10 The Sums of Squares for Block and Treatment can be adjusted to remove any possible confounding.
Adjusting Block Sums of Squares for the effect of Trt: SS(Block|Trt)= SSModel(Block,Trt)- SSModel(Trt) Adjusting Trt Sums of Squares for the effect of Block: SS(Trt|Block)= SSModel(Block,Trt)- SSModel(Block)

11 From Hicks’ Example SS(Block)=100.667 SS(Trt)=975.333
SS(Block,Trt)=

12 For SAS model Y=Block Trt;
Source df Type I SS Type III SS Block 3 SS(Block) SS(Block|Trt) = = Trt 3 SS(Trt|Block) SS(Trt|Block) = =

13 ANOVA Type III and Type I (Block first term in Model)

14 For SAS model Y=Trt Block;
Source df Type I SS Type III SS Trt 3 SS(Trt) SS(Trt|Block) = = Block 3 SS(Block|Trt) SS(Block|Trt) = =

15 ANOVA Type III and Type I (Trt. First term in Model)

16 How does variation partition?

17 How this can work-I Hicks example

18 When does case I happen? In Regression, when two Predictor variables are positively correlated, either one could explain the “same” part of the variation in the Response variable. The overlap in their ability to predict is what is adjusted “out” of their Sums of Squares.

19 Example BIBD From Montgomery (things can go the other way)

20 ANOVA with Adjusted and Unadjusted Sums of Squares

21 Sequential Fit with Block first

22 Sequential Fit with Treatment first

23 LS Means Plot

24 LS Means for Treatment, Tukey HSD

25 How this can work- II Montgomery example

26 When does case II happen?
Sometimes two Predictor variables can predict the Response better in combination than the total of they might predict by themselves. In Regression this can occur when Predictor variables are negatively correlated.


Download ppt "BIBD and Adjusted Sums of Squares"

Similar presentations


Ads by Google