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3.2 Solve Linear Systems Algebraically

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Presentation on theme: "3.2 Solve Linear Systems Algebraically"— Presentation transcript:

1 3.2 Solve Linear Systems Algebraically

2 The Substitution Method
x = -2y + 2 Solve this equation for x Substitute -2y + 2 for x in the first equation. 3x + 4y = -4 3(-2y+2)+4y = -4 -6y+6+4y = -4 Finally, substitute 5 for y (in x = -2y +2) and solve for x. x = -8 y = 5 (-8,5) is the solution to the system.

3 The Substitution Method
Check the ordered pair (-8,5) by substituting it into each equation to verify it is really the solution. x = -8 y = 5 (-8,5) is the solution to the system.

4 The Linear Combination Method: Multiplying One Equation
Multiply the first equation by -2 -2 Add the equations together 3y = -18 y = -6 Use this value for y and substitute it into either of the equations. Solve for x. The ordered pair (-11/2,-6) is the solution to this system x=-(11/2) 4x – 5(-6) = 8

5 The Linear Combination Method: Multiplying One Equation
Multiply the first equation by -2 -2 3y = -18 Why Choose the multiplier -2?? y = -6 The ordered pair (-11/2,-6) is the solution to this system x=-(11/2)

6 (1/2,4)

7 Solve the system using the Linear Combination Method.
(-1,5)

8 What about these?? a. x-2y=3 b. 6x-10y=12 2x-4y= x+25y=-30


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