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Presentation on theme: "Splash Screen."— Presentation transcript:

1 Splash Screen

2 Five-Minute Check (over Lesson 2–7) CCSS Then/Now
Postulate 2.10: Protractor Postulate Postulate 2.11: Angle Addition Postulate Example 1: Use the Angle Addition Postulate Theorems 2.3 and 2.4 Example 2: Real-World Example: Use Supplement or Complement Theorem 2.5: Properties of Angle Congruence Proof: Symmetric Property of Congruence Theorems 2.6 and 2.7 Proof: One Case of the Congruent Supplements Theorem Example 3: Proofs Using Congruent Comp. or Suppl. Theorems Theorem 2.8: Vertical Angles Theorem Example 4: Use Vertical Angles Theorems 2.9–2.13: Right Angle Theorems Lesson Menu

3 D. Segment Addition Postulate
Justify the statement with a property of equality or a property of congruence. A. Transitive Property B. Symmetric Property C. Reflexive Property D. Segment Addition Postulate 5-Minute Check 1

4 D. Segment Addition Postulate
Justify the statement with a property of equality or a property of congruence. A. Transitive Property B. Symmetric Property C. Reflexive Property D. Segment Addition Postulate 5-Minute Check 1

5 D. Segment Addition Postulate
Justify the statement with a property of equality or a property of congruence. A. Transitive Property B. Symmetric Property C. Reflexive Property D. Segment Addition Postulate 5-Minute Check 2

6 D. Segment Addition Postulate
Justify the statement with a property of equality or a property of congruence. A. Transitive Property B. Symmetric Property C. Reflexive Property D. Segment Addition Postulate 5-Minute Check 2

7 D. Segment Addition Postulate
Justify the statement with a property of equality or a property of congruence. If H is between G and I, then GH + HI = GI. A. Transitive Property B. Symmetric Property C. Reflexive Property D. Segment Addition Postulate 5-Minute Check 3

8 D. Segment Addition Postulate
Justify the statement with a property of equality or a property of congruence. If H is between G and I, then GH + HI = GI. A. Transitive Property B. Symmetric Property C. Reflexive Property D. Segment Addition Postulate 5-Minute Check 3

9 State a conclusion that can be drawn from the statement given using the property indicated. W is between X and Z; Segment Addition Postulate. A. WX > WZ B. XW + WZ = XZ C. XW + XZ = WZ D. WZ – XZ = XW 5-Minute Check 4

10 State a conclusion that can be drawn from the statement given using the property indicated. W is between X and Z; Segment Addition Postulate. A. WX > WZ B. XW + WZ = XZ C. XW + XZ = WZ D. WZ – XZ = XW 5-Minute Check 4

11 State a conclusion that can be drawn from the statements given using the property indicated.
LM  NO ___ A. B. C. D. 5-Minute Check 5

12 State a conclusion that can be drawn from the statements given using the property indicated.
LM  NO ___ A. B. C. D. 5-Minute Check 5

13 Given B is the midpoint of AC, which of the following is true?
___ A. AB + BC = AC B. AB + AC = BC C. AB = 2AC D. BC = 2AB 5-Minute Check 6

14 Given B is the midpoint of AC, which of the following is true?
___ A. AB + BC = AC B. AB + AC = BC C. AB = 2AC D. BC = 2AB 5-Minute Check 6

15 G.CO.9 Prove theorems about lines and angles. Mathematical Practices
Content Standards G.CO.9 Prove theorems about lines and angles. Mathematical Practices 3 Construct viable arguments and critique the reasoning of others. 6 Attend to precision. CCSS

16 You identified and used special pairs of angles.
Write proofs involving supplementary and complementary angles. Write proofs involving congruent and right angles. Then/Now

17 Concept

18 Concept

19 m1 + m2 = 90 Angle Addition Postulate 42 + m2 = 90 m1 = 42
Use the Angle Addition Postulate CONSTRUCTION Using a protractor, a construction worker measures that the angle a beam makes with a ceiling is 42°. What is the measure of the angle the beam makes with the wall? The ceiling and the wall make a 90 angle. Let 1 be the angle between the beam and the ceiling. Let 2 be the angle between the beam and the wall. m1 + m2 = 90 Angle Addition Postulate 42 + m2 = 90 m1 = 42 42 – 42 + m2 = 90 – 42 Subtraction Property of Equality m2 = 48 Substitution Example 1

20 Use the Angle Addition Postulate
Answer: Example 1

21 Answer: The beam makes a 48° angle with the wall.
Use the Angle Addition Postulate Answer: The beam makes a 48° angle with the wall. Example 1

22 Find m1 if m2 = 58 and mJKL = 162.
B. 94 C. 104 D. 116 Example 1

23 Find m1 if m2 = 58 and mJKL = 162.
B. 94 C. 104 D. 116 Example 1

24 Concept

25 Use Supplement or Complement
TIME At 4 o’clock, the angle between the hour and minute hands of a clock is 120º. When the second hand bisects the angle between the hour and minute hands, what are the measures of the angles between the minute and second hands and between the second and hour hands? Understand Make a sketch of the situation. The time is 4 o’clock and the second hand bisects the angle between the hour and minute hands. Example 2

26 Use Supplement or Complement
Plan Use the Angle Addition Postulate and the definition of angle bisector. Solve Since the angles are congruent by the definition of angle bisector, each angle is 60°. Answer: Example 2

27 Answer: Both angles are 60°.
Use Supplement or Complement Plan Use the Angle Addition Postulate and the definition of angle bisector. Solve Since the angles are congruent by the definition of angle bisector, each angle is 60°. Answer: Both angles are 60°. Check Use the Angle Addition Postulate to check your answer. m1 + m2 = 120 = 120 120 = 120 Example 2

28 QUILTING The diagram shows one square for a particular quilt pattern
QUILTING The diagram shows one square for a particular quilt pattern. If mBAC = mDAE = 20, and BAE is a right angle, find mCAD. A. 20 B. 30 C. 40 D. 50 Example 2

29 QUILTING The diagram shows one square for a particular quilt pattern
QUILTING The diagram shows one square for a particular quilt pattern. If mBAC = mDAE = 20, and BAE is a right angle, find mCAD. A. 20 B. 30 C. 40 D. 50 Example 2

30 Concept

31 Concept

32 Concept

33 Concept

34 Given: Prove: Proofs Using Congruent Comp. or Suppl. Theorems
Example 3

35 1. m3 + m1 = 180; 1 and 4 form a linear pair.
Proofs Using Congruent Comp. or Suppl. Theorems Proof: Statements Reasons 1. Given 1. m3 + m1 = 180; 1 and 4 form a linear pair. 2. Linear pairs are supplementary. 2. 1 and 4 are supplementary. 3. Definition of supplementary angles 3. 3 and 1 are supplementary. 4. s suppl. to same  are . 4. 3  4 Example 3

36 In the figure, NYR and RYA form a linear pair, AXY and AXZ form a linear pair, and RYA and AXZ are congruent. Prove that NYR and AXY are congruent. Example 3

37 Which choice correctly completes the proof? Proof:
Statements Reasons 1. Given 1. NYR and RYA, AXY and AXZ form linear pairs. 2. If two s form a linear pair, then they are suppl. s. 2. NYR and RYA are supplementary. AXY and AXZ are supplementary. 3. Given 3. RYA  AXZ 4. NYR  AXY 4. ____________ ? Example 3

38 B. Definition of linear pair
A. Substitution B. Definition of linear pair C. s supp. to the same  or to  s are . D. Definition of supplementary s Example 3

39 B. Definition of linear pair
A. Substitution B. Definition of linear pair C. s supp. to the same  or to  s are . D. Definition of supplementary s Example 3

40 Concept

41 2. Vertical Angles Theorem
Use Vertical Angles If 1 and 2 are vertical angles and m1 = d – 32 and m2 = 175 – 2d, find m1 and m2. Justify each step. Statements Reasons Proof: 1. 1 and 2 are vertical s. 1. Given 2. 1  2 2. Vertical Angles Theorem 3. m1 = m2 3. Definition of congruent angles 4. d – 32 = 175 – 2d 4. Substitution Example 4

42 Statements Reasons 5. Addition Property 6. Addition Property
Use Vertical Angles Statements Reasons 5. 3d – 32 = 175 5. Addition Property 6. 3d = 207 6. Addition Property 7. d = 69 7. Division Property m1 = d – 32 m2 = 175 – 2d = 69 – 32 or 37 = 175 – 2(69) or 37 Answer: Example 4

43 Statements Reasons 5. Addition Property 6. Addition Property
Use Vertical Angles Statements Reasons 5. 3d – 32 = 175 5. Addition Property 6. 3d = 207 6. Addition Property 7. d = 69 7. Division Property m1 = d – 32 m2 = 175 – 2d = 69 – 32 or 37 = 175 – 2(69) or 37 Answer: m1 = 37 and m2 = 37 Example 4

44 A. B. C. D. Example 4

45 A. B. C. D. Example 4

46 Concept

47 End of the Lesson


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