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- photometric aspects of image formation gray level images
point-wise operations linear filtering CS682, Jana Kosecka
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Image Brightness values I(x,y) CS682, Jana Kosecka
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Analog intensity function Temporal/spatial sampled function
Image model Mathematical tools Analog intensity function Temporal/spatial sampled function Quantization of the gray levels Point sets Random fields List of image features, regions Analysis Linear algebra Numerical methods Set theory, morphology Stochastic methods Geometry, AI, logic CS682, Jana Kosecka
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Basic Photometry CS682, Jana Kosecka
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Basic ingredients Radiance – amount of energy emitted along certain direction Iradiance – amount of energy received along certain direction BRDF – bidirectional reflectance distribution Lambertian surfaces – the appearance depends only on radiance, not on the viewing direction Image intensity for a Lambertian surface CS682, Jana Kosecka
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Challenges CS682, Jana Kosecka
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Images Images contain noise – sources sensor quality, light
fluctuations, quantization effects CS682, Jana Kosecka
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Image Noise Models Additive noise: Most commonly used
Multiplicative noise: Impulsive noise (salt and pepper): CS682, Jana Kosecka
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Additive Noise Models Noise Amount: SNR = s/ n
Gaussian - Usually, zero-mean, uncorrelated Uniform CS682, Jana Kosecka
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Example CS682, Jana Kosecka
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How can we reduce noise? Image acquisition noise due to light fluctuations and sensor noise can be reduced by acquiring a sequence of images and averaging them. Solution – filtering the image CS682, Jana Kosecka
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Image Processing 1D signal and its sampled version
f = { f(1), f(2), f(3), …, f(n)} f = {0, 1, 2, 3, 4, 5, 5, 6, 10 } CS682, Jana Kosecka
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Discrete time system maps 1 discrete time signal to another
f[x] g[x] h Special class of systems – linear , time-invariant systems Superposition principle Shift (time) invariant – shift in input causes shift in output Examples CS682, Jana Kosecka
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unit impluse – if x = 0 it’s 1 and zero everywhere else
Convolution sum: unit impluse – if x = 0 it’s 1 and zero everywhere else Every discrete time signal can be written as a sum of scaled and shifted impulses The output the linear system is related to the input and the transfer function via convolution h f g filter f g Convolution sum: Notation: CS682, Jana Kosecka
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Averaging filter Original image Smoothed image CS682, Jana Kosecka
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Center pixel weighted more
Averaging filter Averaging box filter Averaging filter Center pixel weighted more 2D convolution - next CS682, Jana Kosecka
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Convolution in 2D X 10 10 11 9 1 2 99 f g h 1 1 1 1 1 1 1/9 1 1 1 1/9.(10x1 + 11x1 + 10x1 + 9x1 + 10x1 + 11x1 + 10x1 + 9x1 + 10x1) = 1/9.( 90) = 10 CS682, Jana Kosecka
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Example: X X X X X X 10 11 10 1 10 7 4 1 X X 9 10 11 1 1 O X X 10 9 10 I 2 1 X X 11 10 9 9 11 10 1 F X X 9 10 11 9 99 11 X X X X X X 10 9 9 11 10 10 1/9 1/9.(10x1 + 0x1 + 0x1 + 11x1 + 1x1 + 0x1 + 10x1 + 0x1 + 2x1) = 1/9.( 34) = CS682, Jana Kosecka
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Example: X X X X X X 10 11 10 1 10 7 4 1 X X 9 10 11 1 1 O X X I 10 9
1 10 7 4 1 X X 9 10 11 1 1 O X X I 10 9 10 2 1 X X 11 10 9 9 11 10 1 F X 20 X 9 10 11 9 99 11 X X X X X X 10 9 9 11 10 10 1/9 1/9.(10x1 + 9x1 + 11x1 + 9x1 + 99x1 + 11x1 + 11x1 + 10x1 + 10x1) = 1/9.( 180) = 20 CS682, Jana Kosecka
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Example: X X X X X X 10 11 10 1 10 7 4 1 X X 9 10 11 1 1 O X X 10 9 10 I 2 1 X 18 X 11 10 9 9 11 10 1 F X 20 X 9 10 11 9 99 11 X X X X X X 10 9 9 11 10 10 1/9 1/9.(10x1 + 0x1 + 2x1 + 9x1 + 10x1 + 9x1 + 11x1 + 9x1 + 99x1) = 1/9.( 159) = CS682, Jana Kosecka
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How big should the mask be?
The bigger the mask, more neighbors contribute. smaller noise variance of the output. bigger noise spread. more blurring. more expensive to compute. CS682, Jana Kosecka
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Gaussian Filter A particular case of averaging
The coefficients are samples of a 1D Gaussian. Gives more weight at the central pixel and less weights to the neighbors. The further away the neighbors, the smaller the weight. Sample from the continuous Gaussian CS682, Jana Kosecka
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How big should the mask be?
The std. dev of the Gaussian determines the amount of smoothing. The samples should adequately represent a Gaussian For a 98.76% of the area, we need m = 5 5.(1/) 2 0.796, m 5 5-tap filter g[x] = [0.136, , 1.00, 0.606, 0.136] CS682, Jana Kosecka
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Image Smoothing Convolution with a 2D Gaussian filter
Gaussian filter is separable, convolution can be accomplished as two 1-D convolutions CS682, Jana Kosecka
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Non-linear Filtering Replace each pixel with the MEDIAN value of all the pixels in the neighborhood. Non-linear Does not spread the noise Can remove spike noise Expensive to run CS682, Jana Kosecka
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Example: 10 11 9 1 2 99 I X 10 O median sort 10,11,10,9,10,11,10,9,10
99 I X 10 O median sort 10,11,10,9,10,11,10,9,10 9,9,10,10,10,10,10,11,11 CS682, Jana Kosecka
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Example: 10 11 10 1 X X X X X X 9 10 11 1 1 10 1 1 X 10 X O 10 9 10 I 2 1 X X 11 10 9 9 11 X X 10 9 10 11 9 99 11 X X 10 9 9 11 10 10 X X X X X X median sort 11,10,0,10,11,1,9,10,0 0,0,1,9,10,10,10,11,11 CS682, Jana Kosecka
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Example: X X X X X X 10 11 10 1 10 X X 9 10 11 1 1 O X X 10 I 10 9 2 1
1 10 X X 9 10 11 1 1 O X X 10 I 10 9 2 1 X 9 X 11 10 9 9 11 10 X 10 X 9 10 11 9 99 11 X X X X X X 10 9 9 11 10 10 median sort 10,9,11,9,99,11,11,10,10 9,9,10,10,10,11,11,11,99 CS682, Jana Kosecka
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Pointwise Image Operations
Lookup table – match image intensity to the displayed brightness values Manipulation of the lookup table – different Visual effects – mapping is often non-linear CS682, Jana Kosecka
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Contrast gamma Contrast CS682, Jana Kosecka Brightness
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Quantization Thresholding Histogram
Histogram – frequency gray-level -> empirical distribution h[i] – number of pixels of intensity i Histogram equalization – making histogram flat CS682, Jana Kosecka
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