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Projectile Motion.

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Presentation on theme: "Projectile Motion."— Presentation transcript:

1 Projectile Motion

2 What is the rock’s velocity when it hits the ground?
vx=20 m/s Vy Vf2=vi2+2ad Vf = m/s Resultant=49 m/s

3 What is projectile? Projectile -Any object which projected by some means and continues to move due to its own inertia (mass).

4 Projectiles move in TWO dimensions
Since a projectile moves in 2-dimensions, it therefore has 2 components just like a resultant vector. Horizontal and Vertical

5 Horizontal “Velocity” Component
NEVER changes initial horizontal velocity equals the final horizontal velocity Gravity does not do work horizontally

6 Vertical “Velocity” Component
Changes (due to gravity) Constant acceleration m/s/s Both the MAGNITUDE and DIRECTION change. As the projectile moves up the MAGNITUDE DECREASES and its direction is UPWARD. As it moves down the MAGNITUDE INCREASES and the direction is DOWNWARD.

7 Combining the Components
Together, these components produce what is called a trajectory or path. This path is parabolic in nature. Component Magnitude Direction Horizontal Constant Vertical Changes

8 Horizontally Launched Projectiles
Projectiles which have NO upward trajectory and NO initial VERTICAL velocity.

9 Horizontally Launched Projectiles
To analyze a projectile in 2 dimensions we need 2 equations. One for the “x” direction and one for the “y” direction X Y

10 Horizontally Launched Projectiles
Example: A plane traveling with a horizontal velocity of 100 m/s is 500 m above the ground. At some point the pilot decides to drop some supplies to designated target below. (a) How long is the drop in the air? (b) How far away from point where it was launched will it land? X Y vi=100 m/s D = -500 m a = 0 m/s/s vi= 0 m/s D = ? a= -9.8 m/s/s T = ? T= ?

11 Horizontally Launched Projectiles
Example: A plane traveling with a horizontal velocity of 100 m/s is 500 m above the ground. At some point the pilot decides to drop some supplies to designated target below. (a) How long is the drop in the air? (b) How far away from point where it was launched will it land? X Y vi=100 m/s D = 500 m a = 0 m/s/s vi= 0 m/s D = ? a= -9.8 m/s/s T = ? T= ? 1010 m 10.1 seconds

12 Horizontally Launched Projectiles
Example: A group of kids are playing soccer on top of a cliff. Jill accidentally kicks the ball off the cliff. It lands 14.5 m away from the cliff after spending 2.11 seconds in the air. At what velocity did Jill kick the ball? How tall is the cliff? What do I know? What I want to know? x=14.5 m vox= t = 2.11 sec y= voy= 0 m/s g = m/s/s 14.5=vox(2.11) y= ½ (-9.8)(2.11)2 Vox = 6.87 m/s y = m

13 Warm Up Ned walks 30 m south, turns and goes 15 m east, turns again to go 10 m north, and back 5 m west. What is his displacement? How can you find the angle of Ned’s displacement from his starting point to end point? (Discuss with a friend.) What is it? What are the x and y components of the resultant vectors? 22.36 26.6 degrees (79.9, 60.2) (-86.6, 50) (-60.2, -79.9)

14 Another Example… A pool ball leaves a 0.60-meter high table with an initial horizontal velocity of 2.4 m/s. Predict the time required for the pool ball to fall to the ground and the horizontal distance between the table's edge and the ball's landing location.

15 Vertically Launched Projectiles
NO Vertical Velocity at the top of the trajectory. Vertical Velocity decreases on the way upward Vertical Velocity increases on the way down, Horizontal Velocity is constant Component Magnitude Direction Horizontal Constant Vertical Decreases up, top, Increases down Changes Notes for next day

16 Vertically Launched Projectiles
Since the projectile was launched at a angle, the velocity MUST be broken into components!!! vo voy q vox

17 Vertically Launched Projectiles
*Note* If a projectile begins and ends at ground level, the “y” displacement is ZERO: y = 0

18 Vertically Launched Projectiles
You will still use kinematic #2, but YOU MUST use COMPONENTS in the equation. vo voy q vox

19 Example A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees. (a) How long is the ball in the air? (b) How far away does it land? (c) How high does it travel? vo=20.0 m/s q = 53

20 Example What I know What I want to know vox=12.04 m/s t = ? voy=15.97 m/s x = ? y = 0 ymax=? g = m/s/s A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees. (a) How long is the ball in the air? 3.26 s

21 Example A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees. (b) How far away does it land? What I know What I want to know vox=12.04 m/s t = 3.26 s voy=15.97 m/s x = ? y = 0 ymax=? g = m/s/s 39.24 m

22 Example What I know What I want to know t = 3.26 s x = 39.24 m y = 0
vox=12.04 m/s t = 3.26 s voy=15.97 m/s x = m y = 0 ymax=? g = m/s/s A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees. (c) How high does it travel? CUT YOUR TIME IN HALF! 13.01 m


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