1. Plant Biology Plant Cell Evolution Life Cycles Structures Transport
Hormones
Tropisms
Photoperiodism

2. A botanist discovers a new species of plant in a tropical rain forest
A botanist discovers a new species of plant in a tropical rain forest. After observing its anatomy and life cycle, the following characteristics are noted: flagellated sperm, xylem with tracheids, separate gametophyte and sporophyte phases, and no seeds. This plant is probably most closely related to *
mosses.
Chara.
ferns.
liverworts.
flowering plants.
Answer: 3
Source: Taylor - Student Study Guide for Biology, Sixth Edition, Test Your Knowledge Question #35.
Discussion Notes for the Instructor
This question would be very useful for helping students understand how to apply the diversity information to new situations. The discussion centers on how particular characteristics allow the students to eliminate choices, resulting in the best choice remaining.

3. A botanist discovers a new species of plant with a dominant sporophyte, chlorophyll a and b, and a cell wall made of cellulose. In assigning this plant to a division, all of the following would provide useful information except whether or not the plant has *
endosperm.
seeds.
flagellated sperm.
flowers.
starch.
Answer: e
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #50.
Discussion Notes for the Instructor
This question would be very useful for helping students understand how to apply the diversity information to new situations. The discussion would center on how the choices relate to important characteristics of different plant groups. Choice E is the exception because all plants contain starch.

4. Assume that a botanist was visiting a tropical region for the purpose of discovering plants with medicinal properties. All of the following might be ways of identifying potentially useful plants except
observing which plants sick animals seek out.
observing which plants are the most used food plants.
observing which plants animals do not eat.
collecting plants and subjecting them to chemical analysis.
asking local people which plants they use as medicine.
Answer: b
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #52.

5. What is one result of an organism having meristems?
a rapid change from juvenile to adult state
a seasonal change in leaf morphology
a rapid change from a vegetative state to a reproductive state
indeterminate, life-long growth
production of a fixed number of segments during growth
Answer: 4
Source: Barstow - Test Bank for Biology, Sixth Edition, Question 20 .

6. One important difference between the anatomy of roots and the anatomy of leaves is that
only leaves have phloem and only roots have xylem.
the cells of roots have cell walls that are lacking in leaf cells.
a waxy cuticle covers leaves but is absent in roots.
vascular tissue is found in roots but is absent from leaves.
leaves have epidermal tissue but roots do not.
Answer: 3
Source: Taylor - Student Study Guide for Biology, Sixth Edition, Test Your Knowledge Question #33.

7. While studying the plant Arabidopsis, a botanist finds that an RNA probe produces colored spots in the sepals of the plant. From this information, which information can be inferred?
The differently colored plants will attract different pollinating insects.
The RNA probe is transported only to certain tissues.
The colored regions were caused by mutations that took place in the sepals.
The RNA probe is specific to a gene active in sepals.
More research needs to be done on the sepals of Arabidopsis.
Answer: 4
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #52.

8. Which of these statements about human evolution is true?
The ancestors of Homo sapiens were chimpanzees and other apes.
Human evolution has proceeded in an orderly fashion from an ancestral anthropoid to Homo sapiens.
The evolution of upright posture and enlarged brain occurred simultaneously.
Different features have evolved at different rates.
Mitochondrial DNA analysis indicates that modern humans are genetically very similar to Neanderthals.
Answer: 4
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #71.

9. What mechanism explains the movement of sucrose from source to sink?
evaporation of water and active transport of sucrose from the sink
osmotic movement of water into the sucrose-loaded sieve-tube members creating a higher hydrostatic pressure in the source than in the sink
tension created by the differences in hydrostatic pressure in the source and sink
active transport of sucrose through the sieve-tube cells driven by proton pumps
the hydrolysis of starch to sucrose in the mesophyll cells that raises their water potential and drives the bulk flow of sap to the sink
Answer: b
Source: Taylor - Student Study Guide for Biology, Sixth Edition, Test Your Knowledge Question #18 .

10. The main mechanism(s) determining the direction of short-distance transport within a potato tuber is (are)
diffusion due to concentration differences and bulk flow due to pressure differences.
pressure flow through the phloem.
active transport due to the hydrolysis of ATP and ion transport into the tuber cells.
determined by the structure and function of the tonoplast of the tuber cells.
not affected by temperature and pressure.
Answer: a
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #10.

11. A water molecule could move all the way through a plant from soil to root to leaf to air and pass through a living cell only once. This living cell would be a part of which structure?
the Casparian strip
a guard cell
the root epidermis
the endodermis
the root cortex
Answer: d
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #24.

12. Photosynthesis begins to decline when leaves wilt because
flaccid cells are incapable of photosynthesis.
CO2 accumulates in the leaves and inhibits photosynthesis.
there is insufficient water for photolysis during light reactions.
stomata close, preventing CO2 entry into the leaf.
the chlorophyll of flaccid cells cannot absorb light.
Answer: d
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #43.

13. Water flows into the source end of a sieve tube because
sucrose has diffused into the sieve tube, making it hypertonic.
sucrose has been actively transported into the sieve tube, making it hypertonic.
water pressure outside the sieve tube forces in water.
the companion cell of a sieve tube actively pumps in water.
sucrose has been dumped from the sieve tube by active transport.
Answer: b
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #56.

14. In the pressure-flow hypothesis of translocation, what causes the pressure?
root pressure
the osmotic uptake of water by sieve tubes at the source
the accumulation of minerals and water by the stele in the root
the osmotic uptake of water by the sieve tubes of the sink
hydrostatic pressure in xylem vessels
Answer: b
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #61.

15. What does self-incompatibility provide for a plant?
means of transferring pollen to another plant
a means of coordinating the fertilization of an egg with the development of stored nutrients
a means of destroying foreign pollen before it fertilizes the egg cell
a biochemical block to self-fertilization so that cross-fertilization is assured
a means of producing seeds without the need for fertilization
Answer: d
Source: Taylor - Student Study Guide for Biology, Sixth Edition, Test Your Knowledge Question #15.

16. What is the relationship between pollination and fertilization in flowering plants? *
Fertilization precedes pollination.
Pollination easily occurs between plants of different species.
Pollen is formed within megasporangia so that male and female gametes are near each other.
Pollination brings gametophytes together so that fertilization can occur.
If fertilization occurs, pollination is unnecessary.
Answer: d
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #34.
Discussion Notes for the Instructor
This question focuses on the conceptual difference between pollination and fertilization.
The follow-up questions might include
• What is the difference between pollination and fertilization?
• Where does pollination take place?
• Where does fertilization take place?

17. The heavy line in this figure illustrates the relationship between auxin concentration and cell growth in stem tissues. If the same range of concentrations was applied to lateral buds, what curve would probably be produced? *
I only
II only
III only
II and III
either I or III
Answer: 1
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #29.
Discussion Notes for the Instructor
While this question provides for a good discussion of the function of auxin in plants it is even more useful as a reminder of the different impacts of a single hormone on different tissues This also leads to a broader discussion of signal transduction pathways and receptors.

18. The critical night length is 14 hours.
A botanist exposed two groups of plants (of the same species) to two photoperiods, one with 14 hours of light and 10 hours of dark and the other with 10 hours of light and 14 hours of dark. Under the first set of conditions, the plants flowered, but they failed to flower under the second set of conditions. Which of the following conclusions would be consistent with these results?
The critical night length is 14 hours.
The plants are short-day plants.
The critical day length is 10 hours.
The plants can convert phytochrome to florigen.
The plants flower in the spring.
Answer: 5
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #52.

19. AP Essays and labs
AP Lab 9
2005, # 3

20. Ecology Biomes Behavior Populations Community Ecosystems Symbiosis
Competition
Succession
Ecosystems

21. If a meteor impact or volcanic eruption injected a lot of dust into the atmosphere and reduced sunlight reaching Earth's surface by 70% for one year, all of the following marine communities would be greatly affected except a
deep-sea vent community.
coral reef community.
benthic community.
pelagic community.
estuary community.
Answer: a
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #42.

22. When, during a field trip, the instructor touched the body of a moth that was sitting on a tree trunk, the moth raised its forewings to reveal large eye-spots on its hind wings. The instructor asked the class why the moth lifted its wings. One student said that certain sensory receptors had fired and triggered a neuronal reflex culminating in the contraction of certain muscles. A second student responded that the behavior might frighten would-be predators.
Answer: 2
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #1.
Discussion Notes for the Instructor
This question can be used to introduce students to the material on behavior by asking them to think about proximate versus ultimate causes for the behaviors that we observe. This question can then be extended to discuss different approaches to behavioral science, some investigating proximate questions and some ultimate questions. A complete understanding of behavior is only achieved when we understand both the proximate and ultimate questions.

23. (cont.) What can you say about the explanations of these two students? *
The first response is correct, while the second is incorrect.
The first response answers a proximate question, while the second answers an ultimate question.
The first response is biological, while the second is philosophical.
The first explanation is testable as a scientific hypothesis, while the second is not.
Both explanations are reasonable and simply represent a difference of opinion.
Answer: 2
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #1.
Discussion Notes for the Instructor
This question can be used to introduce students to the material on behavior by asking them to think about proximate versus ultimate causes for the behaviors that we observe. This question can then be extended to discuss different approaches to behavioral science, some investigating proximate questions and some ultimate questions. A complete understanding of behavior is only achieved when we understand both the proximate and ultimate questions.

24. A cage with male mosquitoes in it has a small earphone placed on top, through which the sound of a female mosquito is played. All the males immediately fly to the earphone and thrust their abdomens through the fabric of the cage.
Answer: 2
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #8.

25. (cont.) Which of the following best describes this?
The males learn to associate the sound with a female and are thus attracted to it.
Copulation is a fixed action pattern, and the female flight sound is a sign stimulus that initiates it.
The sound from the earphone irritated the male mosquitoes, causing them to attempt to sting it.
The reproductive drive is so strong that when males are deprived of females, they will attempt to mate with anything that has even the slightest female characteristic.
Through classical conditioning, the male mosquitoes have associated the inappropriate stimulus from the earphone with the normal response of copulation.
Answer: 2
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #8.

26. Which of the following is true about imprinting?
It may be triggered by visual or chemical stimuli.
It happens to many adult animals, but not to their young.
It is a type of learning involving no innate behavior.
It occurs only in birds.
It causes behaviors that last for only a short time (the critical period).
Answer: 1
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #20.

27. classical conditioning. operant conditioning. maturation.
Every morning at the same time John went into the den to feed his new tropical fish. After a few weeks John noticed that the fish would rise to the top of the tank as soon as he would enter the room. This is a good example of
habituation.
imprinting.
classical conditioning.
operant conditioning.
maturation.
Answer: 3
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #26.

28. A dog learns that it will get a treat when it barks
A dog learns that it will get a treat when it barks. Which of the following might you use to describe this behavior?
The dog is displaying an instinctive fixed action pattern.
The dog is performing a social behavior.
The dog is trying to protect its territory.
The dog has been classically conditioned.
The dog's behavior is a result of operant conditioning.
Answer: 5
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #29.

29. As N approaches K for a certain population, which of the following is predicted by the logistic equation?
The growth rate will not change.
The growth rate will approach zero.
The population will show an Allee effect.
The population will increase exponentially.
The carrying capacity of the environment will increase.
Answer: b
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #29.

30. an abandoned field in Ohio the sand dunes south of Lake Michigan
In which of the following habitats would you expect to find the largest number of K-selected individuals?
an abandoned field in Ohio
the sand dunes south of Lake Michigan
the rain forests of Brazil
south Florida after a hurricane
a newly emergent volcanic island
Answer: c
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #43.

31. The following question refers to the figure below, which depicts the age structure of three populations
Answer: a
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #56.

32. Assuming these age structure diagrams describe human populations, in which population is unemployment likely to be most severe in the future? I II
III
No differences in the magnitude of future unemployment would be expected among these populations.
It is not possible to infer anything about future social conditions from age structure diagrams.
Answer: a
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #56.

33. the high percentage of young people
Which of the following variables is (are) important in contributing to the rapid growth of human populations?
the high percentage of young people
the average age to first give birth
carrying capacity of the environment
only A and B
A, B, and C
Answer: d
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #62.

34. it is too hot in the tropics for most food crops.
Clear-cutting tropical forests yields agricultural land with limited productivity because
it is too hot in the tropics for most food crops.
the tropical forest regrows rapidly and chokes out agricultural crops.
few of the ecosystem’s nutrients are stored in the soil; most are in the forest trees.
phosphorus, not nitrogen, is the limiting nutrient in those soils.
decomposition rates are high but primary production is low in the tropics.
Answer: c
Source: Taylor - Student Study Guide for Biology, Sixth Edition, Test Your Knowledge Question #12.

35. Which species is autotrophic? A B C D E
Use the figure below to answer the following questions (2 and 3). Examine this food web for a particular terrestrial ecosystem. Each letter is a species. The arrows represent energy flow.
Which species is autotrophic? A B C D E
Answer: a
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #6.

36. Species C makes its predators sick
Species C makes its predators sick. Which species is most likely to benefit from being a mimic of C? * A B C D E
Answer: b
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #9.
Discussion Notes for the Instructor
This question could be used as an introduction to the topic of food webs, but can also be used discuss trophic levels or mimicry. It integrates several topics in a fairly simple question and provides for follow-up questions to help with the discussion. Follow-up questions might include: identifying specific trophic levels in the figure, identifying which organisms are the consumers vs. which are the producers.

37. Polar bears can provide more food for Eskimos than seals can.
If the flow of energy in an Arctic ecosystem goes through a simple food chain from seaweeds to fish to seals to polar bears, then which of the following is true?
Polar bears can provide more food for Eskimos than seals can.
The total energy content of the seaweeds is lower than that of the seals.
Polar bear meat probably contains the highest concentrations of fat-soluble toxins.
Seals are more numerous than fish.
The carnivores can provide more food for the Eskimos than the herbivores can.
Answer: C
Source: Barstow - Test Bank for Biology, Sixth Edition, Question #54.

38. AP Labs and Essays
Lab 12
Lab 11
1997, # 1
1997, # 3 (lab)
1998, # 4
2002, # 2
2003, # 3

39. Cell Parts Prokaryote Animal / Plant Cells Endosymbiotic Hypothesis,
Structures and Functions

40. Evolution Lamarck/ vs. Darwin Evidence Homologous vs. Analogous
Mechanisms
Natural Selection
Genetic drift
Gene Flow
Mutations
Non-Random Mating

41. Homozygous recessive mice have a reproductive advantage.
Mice that are homozygous for a lethal recessive allele die shortly after birth. In a large breeding colony of mice, you find that a surprising 5% of all newborns die from this trait. In checking lab records, you discover that the same proportion of offspring have been dying from this trait in this colony for the past three years. (Mice breed several times a year and have large litters.) How might you explain the persistence of this lethal allele at such a high frequency?
Homozygous recessive mice have a reproductive advantage.
A large mutation rate keeps producing this lethal allele.
There is some sort of heterozygote advantage and perhaps selection against the homozygous dominant trait.
Genetic drift has kept the recessive allele at this high frequency in the population.
Since this is a diploid species, the recessive allele cannot be selected against when it is in the heterozygote.
Answer: c
Source: Taylor - Student Study Guide for Biology, Seventh Edition, Test Your Knowledge Question #17

42. Genetic analysis of a large population of mink inhabiting an island in Michigan revealed an unusual number of loci where one allele was fixed. Which of the following is the most probable explanation for this genetic homogeneity? *
The population exhibited nonrandom mating, producing homozygous genotypes.
The gene pool of this population never experienced mutation or gene flow.
A very small number of mink may have colonized this island, and this founder effect and subsequent genetic drift could have fixed many alleles.
Natural selection has selected for and fixed the best adapted alleles at these loci.
The colonizing population may have had much more genetic diversity, but genetic drift in the last year or two may have fixed these alleles by chance.
Answer: c
Source: Taylor - Student Study Guide for Biology, Seventh Edition, Test Your Knowledge Question #20
Discussion Notes for the Instructor
The main discussion revolves around the causes of gene fixation. While many of the choices are possible, several are very unlikely. It is also a good question for pointing out that selection rarely leads to allele fixation in a large population
• Choice A: while this is possible the non-random mating would have to be very extreme to produce this result.
• Choice B: this by itself will not produce the results listed
• Choice C: given this is an island in Lake Michigan, this is the best choice
• Choice D: selection generally will not result in fixation.
• Choice E: this assumes that the initial population was large and then became smaller. Given the island location this is not the best explanation.

43. Increased UV irradiation causes the skin of humans to become more darkly pigmented over a period of days. The notion that the offspring of such tanned individuals should consequently inherit darkened skin from their parents is consistent with the ideas of
Charles Darwin.
Carolus Linnaeus.
Alfred Wallace.
Jean Baptiste Lamarck.
Charles Lyell.
Answer: d
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #8

44. A biologist studied a population of squirrels for 15 years
A biologist studied a population of squirrels for 15 years. Over that time, the population was never fewer than 30 squirrels and never more than 45. Her data showed that over half of the squirrels born did not survive to reproduce, because of competition for food and predation. Suddenly, the population increased to 80. In a single generation, 90% of the squirrels that were born lived to reproduce. What inferences might you make about that population?
The amount of available food probably increased.
The number of predators probably decreased.
The young squirrels in the next generation will show greater levels of variation than in the previous generations because squirrels that would not have survived in the past are now surviving.
All three of these are reasonable inferences.
Only B and C are reasonable inferences.
Answer: d
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #20

45. Coloration of the algae eaters may become drab.
In a hypothetical environment, fishes called pike-cichlids are visual predators of algae-eating fish, i.e., they locate their prey by sight. If a population of algae eaters experiences predation pressure from pike-cichlids, then which of the following should not be observed in the algae-eater population over the course of many generations?
Coloration of the algae eaters may become drab.
The algae eaters may become nocturnal (active only at night).
Female algae eaters may become larger, bearing broods composed of more, and larger, young.
The algae eaters may become sexually mature at smaller overall body sizes.
The algae eaters may become faster swimmers.
Answer: c
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #29

46. a large dose of a single chemical. a small dose of a single chemical.
When chemicals are used to control unwanted organisms, then the wisest application strategy, in light of natural selection and assuming that chemicals generally have negative effects on the environment, is to apply
a large dose of a single chemical.
a small dose of a single chemical.
a moderate dose of a single chemical.
large doses of several different chemicals.
moderate doses of several different chemicals.
Answer: e
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #30

47. all whales are the descendants of terrestrial mammals.
As adults, certain species of whales possess baleen instead of teeth. Baleen is used to filter the whales' diet of planktonic animals from seawater. As embryos, baleen whales possess teeth, which are later replaced by baleen. The teeth of embryonic baleen whales are evidence that
all whales are the descendants of terrestrial mammals.
baleen whale embryos pass through a stage when they resemble adult toothed whales.
baleen whales are descendants of toothed whales.
ontogeny recapitulates phylogeny.
among ancient whales, baleen evolved before teeth.
Answer: c
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #34

48. allopolyploidy, a hybrid formed from species A and C.
A botanist identifies a new species of plant that has 32 chromosomes. It grows in the same habitat with three similar species: species A (2n 5 14), species B (2n 5 16), and species C (2n 5 18). Suggest a possible speciation mechanism for the new species.
allopatric divergence by development of a reproductive isolating mechanism.
change in a key developmental gene that causes the plants to flower at different times.
autopolyploidy, perhaps due to a nondisjunction in the formation of gametes of species B.
allopolyploidy, a hybrid formed from species A and C.
Either answer c or d could account for the formation of this new plant species
Answer: e
Source: Taylor - Student Study Guide for Biology, Seventh Edition, Test Your Knowledge Question #19

49. The following question refers to this information: In the year 2500, five male space colonists and five female space colonists from Earth settle on an uninhabited Earthlike planet in the Andromeda galaxy. The colonists and their offspring randomly mate for generations. All ten of the original colonists had free ear lobes, and two are heterozygous for that trait. The allele for free ear lobes is dominant to the allele for attached ear lobes

50. the inheritance of acquired characteristics. mutations.
After many generations, the population on this planet has an unusually high frequency for the incidence of retinitis pigmentosa, relative to Earth's population. This is most likely due to
the founder effect.
sexual selection.
the inheritance of acquired characteristics.
mutations.
the bottleneck effect.
Answer: a
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #16

51. The restriction enzymes of bacteria protect the bacteria from successful attack by bacteriophage, whose genomes can be degraded by the restriction enzymes. The bacterial genomes are not vulnerable to these restriction enzymes because bacterial DNA is methylated. This situation selects for bacteriophage whose genomes are also methylated. As new strains of resistant bacteriophage become more prevalent, this in turn selects for bacteria whose genomes are not methylated and whose restriction enzymes instead degrade methylated DNA.

52. Over the course of evolutionary time, what should occur?
Methylated DNA should become fixed in the gene pools of bacterial species.
Nonmethylated DNA should become fixed in the gene pools of bacteriophage.
Methylated DNA should become fixed in the gene pools of bacteriophage.
Methylated and nonmethylated strains should be maintained among both bacteria and bacteriophage, with ratios that vary over time.
Both A and B are correct.
Answer: d
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #43

53. diversifying selection. directional selection stabilizing selection
A balanced polymorphism exists through diversifying selection in seedcracker finches from Cameroon in which small- and large-billed birds specialize in cracking soft and hard seeds, respectively. If long-term climatic change resulted in all seeds becoming hard, what type of selection would then operate on the finch population?
diversifying selection.
directional selection
stabilizing selection
sexual selection
No selection would operate because the population is in Hardy-Weinberg equilibrium.
Answer: b
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #58

54. A biologist discovers two populations of wolf spiders whose members appear identical. Members of one population are found in the leaf litter deep within the woods. Members of the other population are found in the grass at the edge of the woods. The biologist decides to designate the members of the two populations as two separate species. Which species concept is this biologist most closely utilizing?
Ecological
Biological
Morphological
Pluralistic
genealogical
Answer: a
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #28

55. I only II only III only I and II I and III
The formation of a land bridge between North and South America about three million years ago should have resulted in which of the following? I. allopatry of marine populations that were previously sympatric II. sympatry of marine populations that were previously allopatric III. sympatry of terrestrial populations that were previously allopatric
I only
II only
III only
I and II
I and III
Answer: e
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #33

56. they are groups that are endemic to isolated geographic regions.
If two subspecies, A and B, are not considered separate species even though they cannot interbreed, then
they are groups that are endemic to isolated geographic regions.
they have eliminated postzygotic barriers but not prezygotic barriers.
gene flow between A and B may exist through other related subspecies.
gene flow has ceased and genetic isolation is complete.
their diploid gametes are produced by nondisjunction.
Answer: c
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #35

57. Populations (Hardy Weinberg)
Speciation, Reproductive isolation
Adaptive Radiation
Modes of Natural Selection

58. AP Labs and Essays Lab 8 1992, # 4 1996, # 4 1997, # 4 2001, # 2
2004, # 3

59. Diversity of Life
5 Kingdoms vs. 3 Domains

60. The temperature at which hybrid DNA melts is indicative of the degree of homology between the DNA sequences. The more extensive the pairing, the higher the temperature required to separate the strands. You are trying to determine the phylogenetic relationships among species A, B, and C. You mix single-stranded DNA from all three species (in test groups of two) and measure the temperatures at which the hybrid DNA melts (separates). You find that hybrid BC has the highest melting temperature, AC the next highest, and AB the lowest.
Answer: c
Source: Taylor - Student Study Guide for Biology, Seventh Edition, Test Your Knowledge Question #10.

61. (cont.) From these data you conclude that *
(cont.) From these data you conclude that *
species A and B are most closely related, whereas B and C are least closely related.
B and C must be the same species, and A is more closely related to C than to B.
species B and C must have diverged most recently, and A is more closely related to C than to B.
A hybridizes most easily with B, and they must have a more recent common ancestor than do A and C.
these tests are inconclusive and you had better go back and check the fossil record.
Answer: c
Source: Taylor - Student Study Guide for Biology, Seventh Edition, Test Your Knowledge Question #10.
Discussion Notes for the Instructor
This question could be used to lead a discussion of phylogenetic relationships. It gets at many common student misconceptions about these relationships. One follow-up question would be to have the students draw a cladogram based on these data.
• Choice A: without more data the relative level of relatedness cannot be determined.
• Choice B: the data do not support this conclusion.
• Choice C: correct.
• Choice D; see answer A.
• Choice E: there are enough data to determine the basic pattern of relatedness.

62. According to this dichotomous phylogenetic tree created using cladistic analysis, C and D are most closely related because they
do not share a common ancestor with O, A, or B.
are monophyletic.
evolved from a common ancestor a long time ago.
have the most shared derived characters in common.
have the greatest number of anatomical similarities as shown by statistical analysis.
Answer: d
Source: Taylor - Student Study Guide for Biology, Seventh Edition, Test Your Knowledge Question #15

63. the history and timing of continental drift
A biologist discovers two new species of organisms, one in Africa and one in South America. The organisms resemble one another closely. Which type of evidence would probably be least useful in determining whether these organisms are closely related or are the products of convergent evolution?
the history and timing of continental drift
a comparison of DNA from the two species
the fossil record of the two species
analysis of the behavior of the two species
comparative embryology
Answer: d
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #10

64. A common ancestor for species C and E could be at position number
Use Figure 25.1 to answer the following questions.
A common ancestor for species C and E could be at position number 1. 2. 3. 4. 5.
Answer: d
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #21

65. The two extant species that are most closely related to each other are
A and B.
B and D.
C and B.
D and E.
E and A.
Answer: c
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #22

66. If this evolutionary tree is an accurate depiction of relatedness, then which of the following should be correct?
The entire tree depicts anagenesis.
If all species depicted here make up a taxon, this taxon is monophyletic.
The last common ancestor of species B and C occurred more recently than the last common ancestor of species D and E.
Species A is the ancestor of both species B and C.
The species present at position number three is ancestral to three extant species.
2 only
1 and 3
3 and 4
2, 3, and 4
2, 3, and 5
Answer: e
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #26

67. inheritance of acquired characteristics. sexual selection.
Some DNA-DNA hybridization data place the giant panda in the bear family (Ursidae), but place the lesser panda in the raccoon family (Procyonidae). The similarity of body morphology of these two animals must therefore be due to
inheritance of acquired characteristics.
sexual selection.
inheritance of shared derived characters.
convergent evolution.
possession of shared primitive characters.
Answer: d
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #39

68. A researcher compared the nucleotide sequences of a homologous gene from five different species of mammals. The sequence homology between each species' version of the gene and the human gene are presented as a percentage of similarity.
Species
Percentage
Chimpanzee
99.7
Orangutan
98.6
Baboon
97.2
Rhesus Monkey
96.9
Rabbit
93.7

69. What conclusion can be validly drawn from these data?
Humans and other primates evolved from rabbits.
All organisms have similar DNA.
Among the organisms listed, humans shared a common ancestor most recently with chimpanzees.
Humans evolved from chimpanzees.
Both A and D are correct.
Answer: c
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #44

70. Dogs and wolves have very similar morphologies.
Which statement represents the best explanation for the observation that the nuclear DNA of wolves and domestic dogs has a very high degree of homology?
Dogs and wolves have very similar morphologies.
Dogs and wolves belong to the same genus.
Dogs and wolves are both members of the family Canidae.
Dogs and wolves shared a common ancestor relatively recently.
Convergent evolution has occurred.
Answer: d
Source: Barstow - Test Bank for Biology, Seventh Edition, Question #55

74. Auxin – Cytokinens – Gibberillins – Ethylene – Abscisic acid –
Promotes plant cell growth, apical dominance and cell elongation
Cytokinens –
Cell growth in roots, removes axilary buds from apical dominance,
Gibberillins –
Cell elongation between nodes, seed germination, fruit development, seedless fruits
Ethylene –
Fruit ripening, leaf abscission, (gas)
Abscisic acid –
Closing of stomata, maintains seed dormancy

75. Heteroorphic – sporophyte and gametophyte have different morphologies

84. Steele is larger in the monocot
Pith only in monocot
Region between root and steele is called the cortex
Ground tissue mostly parenchyma fills this region
Endodermis foums bundary between cortex and steels

87. Root endodermis monocot

111. FAP seen in goose
Releaser/sign stimulus signals the pattern
Behavior is innate

115. The Prokaryotic Cell:

116. General Eukaryotic Cells:

124. In what way are these organisms displaying examples of convergent evolution?