1. 9.1 Torque 1

2. Chapter 9 Objectives Calculate the torque created by a force.
Solve problems by balancing two torques in rotational equilibrium.
Define the center of mass of an object.
Describe a technique for finding the center of mass of an irregularly shaped object.
Calculate the moment of inertia for a mass rotating on the end of a rod.
Describe the relationship between torque, angular acceleration, and rotational inertia. 2

3. Chapter 9 Vocabulary angular acceleration center of gravity
center of mass
center of rotation
lever arm
line of action
moment of inertia
rotational
equilibrium
rotational inertia
torque
translation

4. Inv 9.1 Torque Investigation Key Question:
How does force create rotation? 4

5. 9.1 Torque
Motion in which an entire object moves is called translation.
Motion in which an object spins is called rotation.
An object can both rotate and translate. 5

6. 9.1 Torque
A torque is an action resulting from a force that causes objects to rotate.
Torque is not the same thing as force.
Torque is created by force, but torque also depends on the point of application and the direction of the force.
A door pushed at its handle will easily turn and open, but a door pushed near its hinges will not move as easily. 6

7. 9.1 Torque
The point or line about which an object turns is its center of rotation.
A force applied far from the center of rotation produces a greater torque than a force applied close to the center of rotation.
Doorknobs are positioned far from the hinges to provide the greatest amount of torque for a given force. 7

8. 9.1 Torque
Torque is created when the line of action of a force does not pass through the center of rotation.
The line of action is an imaginary line that follows the direction of a force and passes though its point of application. 8

9. 9.1 Torque
To get the maximum torque, the force should be applied in a direction that creates the greatest lever arm.
The lever arm is the perpendicular distance between the line of action of the force and the center of rotation 9

11. 9.1 The torque created by force
The torque created by a force is equal to the lever arm length times the magnitude of the force.
Torque is usually represented by the lower case Greek letter “tau,” t.
When calculating torque, if the line of action passes through the center of rotation, the lever arm is zero, and so is the torque, no matter how large a force is applied.

13. t = r x F 9.1 Calculating Torque Lever arm length (m) Torque (N.m)
Force (N)

14. 9.1 Calculating torque
If more than one torque acts on an object, the torques are combined to determine the net torque.
If the torques make an object spin in the same direction, clockwise or counterclockwise, they are added together.

15. 9.1 Units of torque
The units of torque are force times distance, or newton-meters.
A torque of 1 N⋅m is created by a force of 1 newton acting with a lever arm of 1 meter.
Torque is always calculated around a particular center of rotation.

16. Calculating a torque
A force of 50 newtons is applied to a wrench that is 30 centimeters long. Calculate the torque if the force is applied perpendicular to the wrench so the lever arm is 30 cm.
You are asked to find the torque.
You are given the force and lever arm.
Use: t = r F.
4. Solve: t = (-50 N)(0.3 m) = -15 N⋅m

17. 9.1 Rotational Equilibrium
When an object is in rotational equilibrium, the net torque applied to it is zero.
Rotational equilibrium is often used to determine unknown forces.
What are the forces (FA, FB) holding the bridge up at either end? 17

18. 9.1 Rotational Equilibrium
For the bridge not to move up or down, the total upward force must equal the total downward force.
This means FA + FB = 1,250 N. 18

19. 9.1 Rotational Equilibrium
For the bridge to be in rotational equilibrium, the total torque around any point must also be zero.
If we choose the left end of the bridge, and set the total of the remaining torques to zero, the force on the right support (FB) is calculated to be 400 newtons.
Since the total of both forces must be 1,250 N, that means the force FA on the left must be 850 N. 19

20. Solve a rotational equilibrium problem
A boy and his cat sit on a seesaw. The cat has a mass of 4 kg and sits 2 m from the center of rotation. If the boy has a mass of 50 kg, where should he sit so that the see-saw will balance?
You are asked to find the boy’s lever arm.
You are given the two masses and the cat’s lever arm.
Use: t = r F, and F = mg
Solve for the cat: t = (2 m)(4 kg)(9.8 N/kg) = N⋅m
Solve for the boy: t = (d )(50 kg)(9.8 N/kg) = -490 d
For rotational equilibrium, the net torque must be zero.
0= 78.4 – 490d d = 0.16 m. The boy must sit 16 cm from center.

21. 9.1 When the force and lever arm are NOT perpendicular
When the force and lever arm are not perpendicular, an extra step is required to calculate the length of the lever arm.

22. Calculating a torque from an angled force
A 20-centimeter wrench is used to loosen a bolt.
The force is applied 0.20 m from the bolt.
It takes 50 newtons to loosen the bolt when the force is applied perpendicular to the wrench.
How much force would it take if the force was applied at a 30-degree angle from perpendicular?
You are asked to find the force.
You are given the force and lever arm for one condition.
Use:  = r F.
Solve for the torque required to loosen the bolt
 = (50 N)(0.2 m) = 10 N⋅m
Calculate the torque with a force applied at 30 degrees:
10 N⋅m = F × (0.2 m) cos 30o = F
F = 10 N⋅m ÷ = 58 N. It takes a larger force at 30o.