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Explaining the Causes of Motion in a Different Way

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Presentation on theme: "Explaining the Causes of Motion in a Different Way"— Presentation transcript:

1 Explaining the Causes of Motion in a Different Way
Work, Power & Energy Explaining the Causes of Motion in a Different Way

2 Work The product of force and the amount of displacement along the line of action of that force. Units: ft . lbs (horsepower) Newton•meter (Joule) e

3 Work = F x d To calculate work done on an object, we need: The Force
The average magnitude of the force The direction of the force The Displacement The magnitude of the change of position The direction of the change of position

4 Calculate Work During the ascent phase of a rep of the bench press, the lifter exerts an average vertical force of 1000 N against a barbell while the barbell moves 0.8 m upward How much work did the lifter do to the barbell?

5 Calculate Work Table of Variables: Force = +1000 N
Displacement = +0.8 m Force is positive due to pushing upward Displacement is positive due to moving upward

6 Calculate Work Table of Variables: Force = +1000 N
Displacement = +0.8 m Select the equation and solve:

7 Work performed climbing stairs
Work = Fd Force Subject weight From mass, ie 65 kg Displacement Height of each step Typical 8 inches (20cm) Work per step 650N x 0.2 m = Nm Multiply by the number of steps

8 Simple machines and work-- Forces involved:
Input Force FI Force applied to a machine Output Force FO Force applied by a machine

9 Two forces, thus two types of work
Work Input work done on a machine =Input force x the distance through which that force acts (input distance) Work Output Work done by a machine =Output force x the distance through which the resistance moves (output distance)

10 Mechanical Advantage (MA) – expressed in a ratio WITH NO UNITS!!
The number of times a machine multiplies the input force. MA = output force/input force

11 Efficiency Efficiency can never be greater than 100 %. Why?
Some work is always needed to overcome friction. A percentage comparison of work output to work input. work output (WO) / work input (WI)

12 Mechanical advantage of levers.
Ideal = input arm length/output arm length input arm = distance from input force to the fulcrum output arm = distance from output force to the fulcrum

13 2. The Wheel and Axle A lever that rotates in a circle.
A combination of two wheels of different sizes. Smaller wheel is termed the axle. IMA = radius of wheel/radius of axle.

14 3. The Inclined Plane A slanted surface used to raise an object.
Examples: ramps, stairs, ladders IMA = length of ramp/height of ramp Can never be less than one.

15 Energy Energy (E) is defined as the capacity to do work (scalar)
Many forms No more created, only converted chemical, sound, heat, nuclear, mechanical Kinetic Energy (KE): energy due to motion Potential Energy (PE): energy due to position or deformation

16 KE = 1/2 mv2 Kinetic Energy Energy due to motion reflects
the mass the velocity of the object KE = 1/2 mv2

17 Kinetic Energy Units: reflect the units of mass * v2
Units KE = Units work

18 Calculate Kinetic Energy
How much KE in a 5 ounce baseball (145 g) thrown at 80 miles/hr (35.8 m/s)?

19 Calculate Kinetic Energy
Table of Variables Mass = 145 g  kg Velocity = 35.8 m/s

20 Calculate Kinetic Energy
Table of Variables Mass = 145 g  kg Velocity = 35.8 m/s Select the equation and solve: KE = ½ m v2 KE = ½ (0.145 kg)(35.8 m/s)2 KE = ½ (0.145 kg)( m/s/s) KE = ½ (185.8 kg m/s/s) KE = 92.9 kg m/s/s, or 92.9 Nm, or 92.9J

21 Calculate Kinetic Energy
How much KE possessed by a 150 pound female volleyball player moving downward at 3.2 m/s after a block?

22 Calculate Kinetic Energy
Table of Variables 150 lbs = kg of mass -3.2 m/s Select the equation and solve: KE = ½ m v2 KE = ½ (68.18 kg)(-3.2 m/s)2 KE = ½ (68.18 kg)(10.24 m/s/s) KE = ½ ( kg m/s/s) KE = Nm or J

23 Calculate Kinetic Energy
Compare KE possessed by: a 220 pound (100 kg) running back moving forward at 4.0 m/s a 385 pound (175 kg) lineman moving forward at 3.75 m/s Bonus: calculate the momentum of each player

24 Calculate Kinetic Energy
Table of Variables m = 100 Kg v = 4.0 m/s Select the equation and solve: KE = ½ m v2 KE = ½ (100 kg)(4.0 m/s)2 KE = 800 Nm or J Table of Variables m = 175 kg v = 3.75 m/s Select the equation and solve: KE = ½ m v2 KE = ½ (175)(3.75)2 KE = 1230 Nm or J

25 Calculate Momentum Momentum = mass times velocity
Player 1 = 100 kg * 4.0 m/s Player 1 = 400 kg m/s Player 2 = 175 * 3.75 m/s Player 2 =

26 Potential Energy Two forms of PE: Gravitational PE: Strain PE:
energy due to an object’s position relative to the earth Strain PE: due to the deformation of an object

27 Gravitational PE Affected by the object’s GPE = mgh
weight mg elevation (height) above reference point ground or some other surface h GPE = mgh Units = Nm or J (why?)

28 Take a look at the energetics of a roller coaster
Calculate GPE How much gravitational potential energy in a 45 kg gymnast when she is 4m above the mat of the trampoline? Take a look at the energetics of a roller coaster

29 Calculate GPE Trampoline mat is 1.25 m above the ground
How much gravitational potential energy in a 45 kg gymnast when she is 4m above the mat of the trampoline? Trampoline mat is 1.25 m above the ground

30 Calculate GPE More on this GPE relative to mat Table of Variables
m = 45 kg g = m/s/s h = 4 m PE = mgh PE = 45kg * m/s/s * 4 m PE = J GPE relative to ground Table of Variables m = 45 kg g = m/s/s h = 5.25 m PE = mgh PE = 45m * m/s/s * 5.25 m PE = J

31 Conversion of KE to GPE and GPE to KE and KE to GPE and …

32 Work - Energy Relationship
The work done by an external force acting on an object causes a change in the mechanical energy of the object

33 Work - Energy Relationship
The work done by an external force acting on an object causes a change in the mechanical energy of the object Bench press ascent phase initial position = 0.75 m; velocity = 0 final position = 1.50 m; velocity = 0 m = 100 kg g = -10 m/s/s What work was performed on the bar by lifter? What is GPE at the start & end of the press?

34 Work - Energy Relationship
What work was performed on the bar by lifter? Fd =  KE +  PE Fd = ½ m(vf –vi)2 + mgh Fd = 100kg * - 10 m/s/s * 0.75 m Fd = 750 J W = Fd W = 100 kg * .75m W = 75 kg m W = 75 kg m (10) = 750 J

35 Work - Energy Relationship
What is GPE at the start & end of the press? End (ascent) PE = mgh PE = 100 kg * -10 m/s/s * 1.50 m PE = 1500 J Start (ascent) PE = 100 kg * -10 m/s/s * 0.75m PE = 750 J

36 Work - Energy Relationship
Of critical importance Sport and exercise =  velocity increasing and decreasing kinetic energy of a body similar to the impulse-momentum relationship Ft = m (vf-vi)

37 Work - Energy Relationship
If more work is done, greater energy greater average force greater displacement Ex. Shot put technique ( ). If displacement is restricted, average force is __________ ? (increased/decreased) “giving” with the ball landing hard vs soft

38 Power The rate of doing work Work = Fd Units: Fd/s = J/s = watt

39 Calculate & compare power
During the ascent phase of a rep of the bench press, two lifters each exert an average vertical force of 1000 N against a barbell while the barbell moves 0.8 m upward Lifter A: 0.50 seconds Lifter B: 0.75 seconds

40 Calculate & compare power
Lifter A Table of Variables F = 1000 N d = 0.8 m t = 0.50 s Lifter B


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