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Dr J Frost (jfrost@tiffin.kingston.sch.uk) www.drfrostmaths.com
GCSE: Vectors Dr J Frost Last modified: 31st August 2015
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( ) ( ) ( ) ( ) ( ) ( ) Starter a = b = c = d = f = e = 1 3 5 1 ? ? 2
( ) a = 1 3 ( ) b = 5 1 ? ? a d ( ) c = 2 -3 ( ) d = -4 2 ? ? f e ( ) f = -1 1 ( ) e = -4 ? ? c Bro Tip: Ensure you can distinguish between coordinates and vectors. (π₯,π¦) Coordinates represent positions. π₯ π¦ Vectors represent movement.
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What is a vector? ? ? ? Direction Magnitude (the length)
A vector is an entity with 2 properties: Direction Magnitude (the length) ? ? Vectors are equal if: Same direction & magnitude ?
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Writing Vectors Just like conventional algebra, we can represent vectors as variables. Thereβs 3 ways in which can represent the vector from point X to Z: π (in bold) π (with an βunderbarβ) ππ Y b Z a X
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Click to Start Bromanimation
Adding/Subtracting/Scaling Vectors Determine: XY = a + b ? XZ = 2a ? XR = 2a + 2b Click to Start Bromanimation T R a a XQ = 2a + b ? b b b M 3 2 XM = a + b ? Y a a Q b b b YZ = a β b ? RS = -2b β a ? a a 1 2 X S Z ? MQ = - b + a (M is the midpoint of the line YT)
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Combining Portions of Vectors
πΆ π π π΄ π π π΅ π Let π΄π΅ =π and π΅πΆ =π Let π be the midpoint of π΄π΅, π be a point on π΅πΆ such that π΅π:ππΆ=1:3 and π be a point on π΄πΆ such that π΄π:ππΆ=2:1 Find: ? π΄π = π π π π΄π =π+ π π π πΆπ =β π π π ? π΄πΆ =π+π π΄π = π π π¨πͺ = π π π+ π π π ? ? ?
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Exercise 1 (on your sheet)
3 π΅π΄ =βπ π΄πΆ =π+π π·π΅ =2πβπ π΄π· =βπ+π ? ππ =π+π ππ =πβ2π ππ βπ+π ππ =βπβπ ? ? ? ? ? ? ? 2 4 ππΎ =βπβπ ππΏ =3πβπ ππΎ =2πβπ πΎπ =β2π+π ? ? π΄π΅ =βπ+π πΉπ =βπ+π π΄π =β2π+π πΉπ· =β3π+2π ? ? ? ? ? ?
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Quick fire ratio A P B z ? ? ? ? ? ? The vector π= π΄π΅
Find the following vectors given the specified ratios: π΄π π΅π ? 1 2 π β 1 2 π ? π΄π:ππ΅ = 1:1 ? 1 3 π ? β 2 3 π π΄π:ππ΅ =1:2 ? 3 7 π ? β 4 3 π π΄π:ππ΅ =3:4
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More Complex Paths ? ? π΄π΅ = π΄π + ππ΅ =βπ+π ππ =π+ 3 4 π΄π΅ =π+ 3 4 βπ+π
Bro Tip: GCSE vectors questions will almost always be in two parts: Part (b) will use your answer from part (a). π΄π΅ = π΄π + ππ΅ =βπ+π ? ππ =π π΄π΅ =π βπ+π = 1 4 π+ 3 4 π ? You MUST expand and simplify.
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Test Your Understanding
1 π΅ π΅ 2 ππ:ππ΅=1:3 π΄π:ππ΅=2:3 π π π π π π π΄ π π π΄ π΄π =βπ ππ΅ =βπ π+π =βπ+ 1 4 π+ 1 4 π =β 3 4 π+ 1 4 π First Step? ππ =π π΄π΅ =π βπ+π =πβ 2 5 π+ 2 5 π = 3 5 π+ 2 5 π First Step? ? ?
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TEST YOUR UNDERSTANDING (use the front for blue)
Vote with your diaries! (use the front for blue) A B C D
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Given that M is the midpoint of BC, determine AM.
3a + 2b 3a + b 2a + 3b a + b
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Exercise 2 (on your sheet)
3 1 π΄π΅ =βπ+π π΄π =β 1 5 π+ 1 5 π ππ = 4 5 π+ 1 5 π π΅π = 4 5 πβ 4 5 π ? ππ
=π βπ+π = 3 5 π+ 2 5 π π΅π = 1 4 π ππ = 1 4 π+π π
π = 3 5 βπ+π π =β 7 20 π+ 3 5 π ? ? ? ? ? ? ? 2 4 π΄π =β 1 3 π+ 1 3 π ππ = 2 3 π+ 1 3 π ππ =β 2 3 πβ 1 3 π ? ? π·πΆ =βπ§+π¦ π·π =β 1 2 π§+ 1 2 π¦ π΄π = π΄π· + π·π = 1 2 π§+ 1 2 π¦ π΅π = π΅π΄ + π΄π =βπ₯+ 1 2 π§+ 1 2 π¦ π΅π = 2 3 π΅π =β 2 3 π₯+ 1 3 π§+ 1 3 π¦ π΄π = π΄π΅ + π΅π = 1 3 π₯+ 1 3 π§+ 1 3 π¦ ? ? ? ? ? ? ?
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Recap ?
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Dealing with more complicated βroutesβ
The ratio of the lengths ππ to ππ is 3:2. The ratio of the lengths ππ to ππ
is 4:1. Find π΄π΅ P a N R O b c ? M Q The key is to choose a suitable βrouteβ and work out each part separately before adding. Sometimes there are multiple possible routes. But try to use vectors you have found in previous parts of the question.
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Test Your Understanding
π¨ πͺ π π΄ πΏ πΆ π© π Given that π is a point such that π΄π:ππ΅=3:1 and π is the midpoint of π΅πΆ, find: π΄π΅ =βπ+π ππ = π π βπ+π + π π π = π π π+ π π π ? ?
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Exercise 3 (on sheet) ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ππ΅ =π+2π 1
π΅πΆ =πβπ π΄π = 1 2 π+π ππ = 3 2 π+π 4 ? ? π΄π΅ =βπ+π π΅πΆ =π ππ΅ =β 1 2 π+ 1 2 π ππ =β 1 6 π+ 1 2 π ππ΄ = 2 3 πβπ πΆπ =β 1 2 πβ 1 2 π ππ =β 1 3 πβπ ? ? ? ππΆ =βπ+π ππΆ =β 3 4 π+ 1 2 π π΄π =β 5 4 π+ 1 2 π ? ? 3 ? ? ? ? ππ = 1 2 π+ 1 3 π ππ = 2 3 π+ 1 4 π ππ = 1 2 π+π+ 1 4 π ππ =π+π+ 1 4 π πΆπ =βπβπβ 1 2 π ? ? ? ? ? 2 ? ?
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What do you notice? ? π+2π π 2π 2π+4π
! Vectors are parallel if they have the same direction (but possibly different magnitudes). π β 3 2 π
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Parallel or not parallel?
Vector 1 Vector 2 Parallel? (in general) π+π π+2π 3π+3π β3πβ6π πβπ βπ+π No οΌ Yes ο ο» ο ο» No Yes οΌ ο ο» No Yes οΌ No ο ο» οΌ Yes For ones which are parallel, show it diagrammatically.
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How to show two vectors are parallel
π¨ πͺ π π΄ πΏ πΆ π© π We earlier found that ππ = π π π+ π π π How do we show this is parallel to OC ? ? ! To show parallel, factor out scalars so same vector in brackets: ππ = 1 4 π+π Then write β ππ is a multiple of ππΆ β
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Test Your Understanding
? ?
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Proving three points form a straight line
Points A, B and C form a straight line if: π¨π© and π©πͺ are parallel (and B is a common point). Alternatively, we could show π¨π© and π¨πͺ are parallel. ? C B A C B A
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Test Your Understanding
ππ =π πβ3π ππΆ = 1 2 πβ3π +π Simplify to πβπ and πβπ βNM is a multiple of MCβ (+ they have a common point M) 1 mark? b 1 mark? 1 mark? 1 mark? β3π+π 1 mark? a
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Exercise 4 1 πΆπΈ =π+π πΉπΈ =πβπ+π+π=2π, πΆπ·=π. πΉπΈ is a multiple of πΆπ·. πΉπ =πβπ+π+ 1 2 π=2πβ 1 2 π πΆπ = πΆπΉ + πΉπ =πβπ πβ 1 2 π = 3 5 π+ 3 5 π= π+π ππΈ = ππ + ππΈ = πβ 1 2 π π= 2 5 π π= 2 5 (π+π) πΆπ is a multiple of ππΈ , so parallel. They share a common point π. i) ππ = ππ΄ + π΄π =6π β6π+6π =2π+4π =2(π+2π) ii) ππ = ππΆ πΆπ΅ = 1 3 β6π+6π +3π=π+2π ππ is a multiple of ππ , so they are parallel. They also share a common point π. ? 3 ? π΄π =π β4π+π =βπ+ 1 2 π ππΆ = 1 2 β4π+π π =β2π+π =2 βπ+ 1 2 π π΄π is a multiple of ππΆ (and π is a common point). ? ? ? 2 ? ?
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Answers on next slides. GCSE Questions
File Ref: GCSERevision-Vectors.docx
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<< Return to Index
Vectors << Return to Index ? ?
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<< Return to Index
Vectors << Return to Index ? ?
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<< Return to Index
Vectors << Return to Index ? ?
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<< Return to Index
Vectors << Return to Index ? ?
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<< Return to Index
Vectors << Return to Index ? ?
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<< Return to Index
Vectors << Return to Index ? ?
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<< Return to Index
Vectors << Return to Index ? ?
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<< Return to Index
Vectors << Return to Index ? ?
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