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Gases Physical Properties
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Kinetic Molecular Theory
Particles in an ideal gas… have no volume. The particles in a gas are very far apart. have elastic collisions. are in constant, random, straight-line motion. don’t attract or repel each other. have an avg. KE directly related to Kelvin temperature.
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Real Gases Particles in a REAL gas… have their own volume
attract each other Gas behavior is most ideal… at low pressures at high temperatures
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Characteristics of Gases
Gases expand to fill any container. Gases have very low densities. no volume = lots of empty space Gases can be compressed Compressibility—a measure of how much the volume of matter decreases under pressure
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Characteristics of Gases
Gases undergo diffusion & effusion. Diffusion –the tendency of molecules to go from areas of high concentration to area of low concentration Effusion – the process when a gas escapes through a tiny hole in a container
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Temperature Always use the Kelvin scale when working with gases. ºF ºC K -459 32 212 -273 100 273 373 K = ºC + 273
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Pressure Which shoes create the most pressure?
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Pressure KEY UNITS AT SEA LEVEL 101.325 kPa (kilopascal) 1 atm
760 mm Hg 760 torr 14.7 psi
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Standard Temperature & Pressure
STP STP Standard Temperature & Pressure 0°C K 1 atm kPa -OR-
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Temperature Conversions
Convert each of the following to Kelvin temperatures 27 °C -50 °C -273 °C
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Answers 300 K 223 K 0 K
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Temperature Conversions
Convert each of the following to degrees Celsius 273 K 350. K 100. K 20. K
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Answers 0 °C 77 °C -173 °C -253 °C
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Pressure Conversions Convert 109 kPa to atm Convert 0.62 atm to mm Hg
Convert atm to kPa Convert mmHg to kPa
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Answers 1.08 atm 470 mm Hg kPa 3.91 kPa
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Gases The Gas Laws P V T
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Boyle’s Law The pressure and volume of a gas are inversely related
at constant mass & temp P V
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Charles’ Law The volume and absolute temperature (K) of a gas are directly related at constant mass & pressure V T
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Gay-Lussac’s Law The pressure and absolute temperature (K) of a gas are directly related at constant mass & volume P T
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Combined Gas Law P1V1 T1 = P2V2 T2 P1V1T2 = P2V2T1
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Gas Law Problems A gas occupies 473 cm3 at 36°C. Find its volume at 94°C. GIVEN: V1 = 473 cm3 T1 = 36°C = 309K V2 = ? T2 = 94°C = 367K T V WORK: P1V1T2 = P2V2T1 (473 cm3)(367 K)=V2(309 K) V2 = 562 cm3
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Gas Law Problems A gas occupies 100. mL at kPa. Find its volume at 200. kPa. GIVEN: V1 = 100. mL P1 = 150. kPa V2 = ? P2 = 200. kPa P V WORK: P1V1T2 = P2V2T1 (150.kPa)(100.mL)=(200.kPa)V2 V2 = 75.0 mL
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Gas Law Problems P T V V1 = 7.84 cm3 P1 = 71.8 kPa
A gas occupies 7.84 cm3 at 71.8 kPa & 25°C. Find its volume at STP. GIVEN: V1 = 7.84 cm3 P1 = 71.8 kPa T1 = 25°C = 298 K V2 = ? P2 = kPa T2 = 273 K P T V WORK: P1V1T2 = P2V2T1 (71.8 kPa)(7.84 cm3)(273 K) =( kPa) V2 (298 K) V2 = 5.09 cm3
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Gas Law Problems A gas’ pressure is 765 torr at 23°C. At what temperature will the pressure be 560. torr? GIVEN: P1 = 765 torr T1 = 23°C = 296K P2 = 560. torr T2 = ? P T WORK: P1V1T2 = P2V2T1 (765 torr)T2 = (560. torr)(296K) T2 = 217 K = -56°C
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