1. Centripetal Acceleration
12 Examples with full solutions

2. Example 1
A 1500 kg car is moving on a flat road and negotiates a curve whose radius is 35m. If the coefficient of static friction between the tires and the road is 0.5, determine the maximum speed the car can have in order to successfully make the turn.
35m

3. Example 1 – Step 1 (Free Body Diagram)
This static friction is the only horizontal force keeping the car moving toward the centre of the arc (else the car will drive off the road).
Acceleration direction +y +x

4. Example 1 - Step 2 (Sum of Vector Components)+y +x
Vertical Components
Horizontal Components
We have an acceleration in x-direction
Static Friction
From Vertical Component

5. Example 1 - Step 3 (Insert values)+y +x

6. Example 2
A car is travelling at 25m/s around a level curve of radius 120m. What is the minimum value of the coefficient of static friction between the tires and the road to prevent the car from skidding?
120 m

7. Example 2 – Step 1 (Free Body Diagram)
This static friction is the only horizontal force keeping the car moving toward the centre of the arc (else the car will drive off the road).
Acceleration direction +y +x

8. Example 2 - Step 2 (Sum of Vector Components)+y +x
Vertical Components
Horizontal Components
We have an acceleration in x-direction
Static Friction
From Vertical Component

9. We require the minimum value
Example 2 - Step 3 (Insert values) +y +x
We require the minimum value

10. Example 3
An engineer has design a banked corner with a radius of 200m and an angle of 180. What should the maximum speed be so that any vehicle can manage the corner even if there is no friction?
180
200 m

11. Example 3 – Step 1 (Free Body Diagram)
Components of Normal force along axis (we ensured one axis was along acceleration direction
The normal to the road
Notice that we have no static friction force in this example (question did not require one)
First the car +y +x
Acceleration direction
Now for gravity

12. Example 3 - Step 2 (Sum of Vector Components)+y +x
Vertical Components
Horizontal Components
We have an acceleration in the x-direction
From Vertical Component

13. Example 3 - Step 3 (Insert values)+y +x

14. Example 4
An engineer has design a banked corner with a radius of 230m and the bank must handle speeds of 88 km/h. What bank angle should the engineer design to handle the road if it completely ices up? ?
230 m

15. Acceleration direction
Example 4 – Step 1 (Free Body Diagram)
Components of Normal force along axis (we ensured one axis was along acceleration direction
The normal to the road
Notice that we have no static friction force in this example (question did not require one)
First the car +y +x
Acceleration direction
Now for gravity

16. Example 4 - Step 2 (Sum of Vector Components)+y +x
Vertical Components
Horizontal Components
We have an acceleration in the x-direction
From Vertical Component

17. Don’t forget to place in metres per second
Example 4 - Step 3 (Insert values) +y +x
Don’t forget to place in metres per second

18. Example 5
A 2kg ball is rotated in a vertical direction. The ball is attached to a light string of length 3m and the ball is kept moving at a constant speed of 12 m/s. Determine the tension is the string at the highest and lowest points.

19. Example 5 – Step 1 (Free Body Diagram)
Note: any vertical motion problems that do not include a solid attachment to the centre, do not maintain a constant speed, v and thus (except at top and bottom) have an acceleration that does not point toward the centre. (it is better to use energy conservation techniques)
Bottom
Top
When the ball is at the bottom of the curve, the string is “pulling” up.
When the ball is at the top of the curve, the string is “pulling” down.
In both cases, gravity is pulling down

20. Note: acceleration is down (-)
Example 5 - Step 2 (Sum of Vector Components) +y +x
Top
Bottom
Note: acceleration is down (-)

21. Example 5 - Step 3 (Insert values)+y +x
Top
Bottom

22. Example 6
A conical pendulum consists of a mass (the pendulum bob) that travels in a circle on the end of a string tracing out a cone. If the mass of the bob is 1.7 kg, and the length of the string is 1.25 m, and the angle the string makes with the vertical is 25o.
Determine:
a) the speed of the bob
b) the frequency of the bob

23. It’s easier to make the x axis positive to the left
Example 6 – Step 1 (Free Body Diagram)
Let’s decompose our Tension Force into vertical and horizontal components +y +x
It’s easier to make the x axis positive to the left

24. Example 6 - Step 2 (Sum of Vector Components)+y +x
Horizontal
Vertical

25. Example 6 - Step 3 (Insert values for velocity)
The speed of the bob is about 1.55 m/s

26. Example 6 - Step 3 (Insert values for frequency)
The frequency of the bob is about 0.468Hz

27. Example 7
A swing at an amusement park consists of a vertical central shaft with a number of horizontal arms. Each arm supports a seat suspended from a cable 5.00m long. The upper end of the cable is attached to the arm 3.00 m from the central shaft.
Determine the time for one revolution of the swing if the cable makes an angle of 300 with the vertical

28. Example 7 – Step 1 (Free Body Diagram)

29. Example 7 - Step 2 (Sum of Vector Components)+y +x
Horizontal
Vertical

30. Example 7 - Step 2 (Sum of Vector Components)+y +x
The period is 6.19s

31. Example 8
A toy car with a mass of 1.60 kg moves at a constant speed of 12.0 m/s in a vertical circle inside a metal cylinder that has a radius of 5.00 m. What is the magnitude of the normal force exerted by the walls of the cylinder at A the bottom of the circle and at B the top of the circle

32. Example 8 – Step 1 (Free Body Diagram)
Note: any vertical motion problems that do not include a solid attachment to the centre, do not maintain a constant speed, v and thus (except at top and bottom) have an acceleration that does not point toward the centre. (it is better to use energy conservation techniques)
Bottom
Top
When the ball is at the bottom of the curve, the normal force is “pushing” up.
When the car is at the top of the curve, the normal force is “pushing” down.
In both cases, gravity is pulling down

33. Note: acceleration is down (-)
Example 8 - Step 2 (Sum of Vector Components) +y +x
Top
Bottom
Note: acceleration is down (-)

34. Example 8 - Step 3 (Insert values)+y +x
Top
Bottom

35. Example 9
A 0.20g fly sits 12cm from the centre of a phonograph record revolving at rpm.
a) What is the magnitude of the centripetal force on the fly?
b) What is the minimum static friction between the fly and the record to prevent the fly from sliding off?

36. Example 8 – Step 1 (Free Body Diagram)

37. Convert to correct units
Example 9 - Step 2 (Sum of Vector Components) a.
Convert to correct units

38. Example 9 - Step 2 (Sum of Vector Components)b.

39. Example 10
A 4.00 kg mass is attached to a vertical rod by the means of two 1.25 m strings which are 2.00 m apart. The mass rotates about the vertical shaft producing a tension of 80.0 N in the top string.
What is the tension on the lower string?
How many revolutions per minute does the system make?

40. Example 10 – Step 1 (Free Body Diagram)

41. Example 10 - Step 2 (Sum of Vector Components)+y +
Horizontal
Vertical

42. Example 10 - Step 2 (Sum of Vector Components)+y + a)

43. Example 10 - Step 2 (Sum of Vector Components)+y + b)

44. Example 11
The moon orbits the Earth in an approximately circular path of radius 3.8 x 108 m. It takes about 27 days to complete one orbit. What is the mass of the Earth as obtained by this data?

45. Example 11 – Step 1 (Free Body Diagram)

46. Example 11 - Step 2 (Sum of Vector Components)
Horizontal
The mass of the Earth is about 6.0x1024 kg

47. Example 12 (Hard Question)
An engineer has design a banked corner with a radius of R and an angle of β. What is the equation that determines the velocity of the car given that the coefficient of friction is µ ?

48. Acceleration direction
Example 12 – Step 1 (Free Body Diagram)
Components of Normal force along axis (we ensured one axis was along acceleration direction
The normal to the road
First the car +y +x
Acceleration direction
We have friction going down by assuming car wants to slide up. This will provide an equations for the maximum velocity
Friction
Now for gravity

49. Example 12 – Step 2 (Components)+y +x
Vertical Components
Horizontal Components
From Vertical

50. Example 12 – Step 2 (Components)+y +x
From Vertical
Sub into Horizontal
Solve for v
Minimum velocity (slides down) π

51. Flash