Chapter 6 Objectives Describe the electron-sea model of metallic bonding, and explain how the metallic bond accounts for the characteristics of metallic.

Chapter 6 Objectives Describe the electron-sea model of metallic bonding, and explain how the metallic bond accounts for the characteristics of metallic substances. List and describe the properties of metals. Explain why metals are malleable and ductile but ionic-crystalline compound are not. List and describe the types of Van der Waals Forces. Describe dipole-dipole forces, hydrogen bonding, induced dipoles, and London dispersion forces and their effects on properties such as boiling and melting points.

Chapter 6 Objectives Explain VSEPR theory.
Predict/Explain the shapes of molecules using VSEPR theory. Explain how the shapes of molecules are accounted for by hybridization theory.

Explain why scientists use resonance structures to represent some molecules.
Explain the relationships among potential energy, distance between approaching atoms, bond length, bond stability, and bond energy.

Chapter 6 Metallic Bonding Section 4 Metallic Bonding
Chemical bonding is different in metals than it is in ionic, molecular, or covalent-network compounds (network solids). The unique characteristics of metallic bonding gives metals their characteristic properties, as such electrical conductivity thermal conductivity malleability ductility Luster sectility

The Metallic-Bond Model
Section 4 Metallic Bonding Chapter 6 The Metallic-Bond Model In a metal, the vacant orbitals in the atoms’ outer energy levels overlap. This overlapping of orbitals allows the outer electrons of the atoms to roam freely throughout the entire metal (mobile valence electrons). The electrons are delocalized, which means that they do not belong to any one atom but move freely about the metal’s network of empty atomic orbitals. These mobile electrons form a sea of electrons around the metal atoms, which are packed together in a crystal lattice.

The Metallic-Bond Model, continued
Section 4 Metallic Bonding Chapter 6 The Metallic-Bond Model, continued The chemical bonding that results from the attraction between metal atoms kernel (which are positively charged) and the surrounding sea of shared valence electrons(which are negatively charged) is called metallic bonding. When metal atoms bond to other metal atoms, their valence electrons do not seem to belong to any individual atom but rather they are “group shared” and are free to roam from atom to atom throughout the entire metal crystal. The strength of the binding forces between the “sea of shared valence” and the kernels of the metal atoms directly impacts properties such as ductility, malleability , and sectility. The stronger the binding action, the harder the metal sample will be.

Visual Concepts Chapter 6 Metallic Bonding

Properties of Metals: Surface Appearance
Visual Concepts Chapter 6 Properties of Metals: Surface Appearance

Properties of Metals: Malleability and Ductility
Visual Concepts Chapter 6 Properties of Metals: Malleability and Ductility

Properties of Metals: Electrical and Thermal Conductivity
Visual Concepts Chapter 6 Properties of Metals: Electrical and Thermal Conductivity

Intermolecular Forces
Section 5 Van der Waals Chapter 6 Intermolecular Forces The forces of attraction between molecules are known as intermolecular forces ,aka, the Van der Waals Forces . The boiling point of a liquid is a good measure of the intermolecular forces between its molecules: the higher the boiling point, the stronger the forces between the molecules. Intermolecular forces vary in strength but are weaker than bonds between atoms within molecules, ions in ionic compounds, or metal atoms in solid metals. Boiling points for ionic compounds and metals tend to be much higher than those for molecular substances: forces between molecules are weaker than those between metal atoms or ions.

Categories of Intermolecular Forces (IMFs)
Section 5 Van der Waals Chapter 6 Categories of Intermolecular Forces (IMFs) The forces of attraction between molecules are known as intermolecular forces ,aka, the Van der Waals Forces . Hydrogen Bonds- formed between polar molecules that have hydrogen bonded directly to fluorine, oxygen, or nitrogen in the molecule. Dipole –Dipole Interactive Forces- formed between polar molecules that do not have hydrogen bonding ability. London Dispersion Forces- formed between nonpolar molecules

Intermolecular Forces, continued
Section 5 Van der Waals Chapter 6 Intermolecular Forces, continued The strongest intermolecular forces exist between polar molecules capable of hydrogen bonding. Because of their uneven charge distribution, polar molecules have dipoles. A dipole is created by equal but opposite charges that are separated by a short distance (i.e. an uneven distribution of charge).

Intermolecular Forces, continued
Van der Waals Chapter 6 Intermolecular Forces, continued A dipole is represented by an arrow with its head pointing toward the negative pole and a crossed tail at the positive pole. The dipole created by a hydrogen chloride molecule is indicated as follows: d+ d-

Chapter 6 Hydrogen Bonding
Section 5 Van der Waals Chapter 6 Hydrogen Bonding Some hydrogen-containing compounds have unusually high boiling points. This is explained by a particularly strong type of dipole-dipole force. In compounds containing H–F, H–O, or H–N bonds, the large electronegativity differences between hydrogen atoms and the atoms they are bonded to make their bonds highly polar. This gives the hydrogen atom a positive charge that is almost half as large as that of a bare proton.

Section 5 Van der Waals Chapter 6 Hydrogen Bonding The small size of the hydrogen atom allows the atom to come very close to an unshared pair of electrons in an adjacent molecule. The intermolecular force in which a hydrogen atom that is bonded to a highly electronegative atom is attracted to an unshared pair of electrons of an electronegative atom in a nearby molecule is known as hydrogen bonding.

Section 5 Van der Waals Chapter 6 Hydrogen Bonding Hydrogen bonds are represented by dotted lines connecting the hydrogen-bonded hydrogen to the unshared electron pair of the electronegative atom to which it is attracted. An excellent example of hydrogen bonding is that which occurs between water molecules. The strong hydrogen bonding between water molecules accounts for many of water’s characteristic properties.

Visual Concepts Chapter 6 Hydrogen Bonding

Impacts of Hydrogen Bonding
Section 5 Van der Waals Chapter 6 Impacts of Hydrogen Bonding molecules capable of Hydrogen Bonding generally have…. Higher boiling points Higher melting points Decreased vapor pressures Higher heat of vaporization Lower density in solid state than in liquid state compared to other molecules.

Dipole-Dipole Interactive Forces
Section 5 Molecular Geometry Chapter 6 Dipole-Dipole Interactive Forces The negative region in one polar molecule attracts the positive region in adjacent molecules. So the molecules all attract each other from opposite sides. Such forces of attraction between polar molecules are known as dipole-dipole forces. Dipole-dipole forces , like in all IMFs, act at short range, only between nearby molecules. In general, dipole-dipole forces are weaker than hydrogen bonds but stronger than London bonds. Dipole-dipole forces explain, for example the difference between the boiling points of iodine chloride, I–Cl (97°C), and bromine, Br–Br (59°C).

Visual Concepts Chapter 6 Dipole-Dipole Forces

Comparing Dipole-Dipole Forces
Section 5 Van der Waals Chapter 6 Comparing Dipole-Dipole Forces

Chapter 6 Induced Dipoles
Section 5 Van der Waals Chapter 6 Induced Dipoles A polar molecule can induce a dipole in a nonpolar molecule by temporarily attracting its electrons. The result is a short-range intermolecular force that is somewhat weaker than the dipole-dipole force. Induced dipoles account for the fact that a nonpolar molecule, oxygen, O2, is able to dissolve in water, a polar molecule.

Dipole-Induced Dipole Interaction
Visual Concepts Chapter 6 Dipole-Induced Dipole Interaction

London Dispersion Forces
Section 5 Van der Waals Chapter 6 London Dispersion Forces Even noble gas atoms and nonpolar molecules can experience weak intermolecular attraction. In any atom or molecule—polar or nonpolar—the electrons are in continuous motion. As a result, at any instant the electron distribution may be uneven. A momentary uneven charge can create a positive pole at one end of an atom of molecule and a negative pole at the other. This phenomenon is known as a momentary or temporary dipole.

London Dispersion Forces, continued
Section 5 Van der Waals Chapter 6 London Dispersion Forces, continued This temporary dipole can then induce a dipole in an adjacent atom or molecule. The two are held together for an instant by the weak attraction between temporary dipoles. The intermolecular attractions resulting from the constant motion of electrons and the creation of momentary dipoles are called London dispersion forces. London Bonds are the weakest of the IMFs and all bonds. Fritz London first proposed their existence in 1930.

London Dispersion Force
Visual Concepts Chapter 6 London Dispersion Force

Comparing Strengths of IMFs
Section 5 Van der Waals Chapter 6 Comparing Strengths of IMFs Hydrogen bonds are the strongest of the IMFs. The strength of the hydrogen bond increases as the electronegativity of the atom to which hydrogen is covalently bonded to in a molecule increases. The strength of the hydrogen bond decreases as the size of the atom to which hydrogen is covalently bonded increases. Dipole –dipole forces are, in general, weaker than hydrogen bonds but stronger than London Bonds. London Bonds are the weakest of the IMFs and all bonds.

Comparing Strengths of IMFs
Section 5 Van der Waals Chapter 6 Comparing Strengths of IMFs In a group of related molecules ( polar or nonpolar) the strength of the Van der Waals forces increases as molecular mass increases. This is due to more electrons being available to increase the intensity of any dipoles present in a molecule. The strength of any Van der Waals Force increases as the distance between bonding molecules decreases.

Chapter 6 Molecular Geometry Section 5 Molecular Geometry
The properties or behaviors of molecules depend not only on the bonding of atoms but also on molecular geometry: the three-dimensional arrangement of a molecule’s atoms. The polarity of each bond, along with the geometry of the molecule, determines molecular polarity, or the uneven distribution of charges due to molecular shape. Molecular polarity strongly influences the forces that act between molecules in liquids and solids. A chemical formula, by itself, reveals little information about a molecule’s geometry.

Chapter 6 Molecular Geometry
Section 5 Molecular Geometry Chapter 6 Molecular Geometry 2 methods are used to make determinations of molecular geometry VSEPR Theory Central atom bonding character (Hybridization Theory) Either of these methods can be used, in conjunction or independently, to correctly determine a molecule’s 3-dimensional shape.

Section 5 Molecular Geometry
Chapter 6 VSEPR Theory As shown at right, diatomic molecules, like those of (a) hydrogen, H2, and (b) hydrogen chloride, HCl, can only be linear because they consist of only two atoms. To predict the geometries of more-complicated molecules, one must consider the locations of all electron pairs surrounding the bonding atoms. This is the basis of VSEPR theory.

Section 5 Molecular Geometry
Chapter 6 VSEPR Theory The abbreviation VSEPR (say it “VES-pur”) stands for “valence-shell electron-pair repulsion.” VSEPR theory states that repulsion between the sets of valence-level electrons surrounding a “central” atom causes these sets to be oriented as far apart as possible. (Repelled to maximum distance) example: BeH2 The central beryllium atom is surrounded by only the two electron pairs it shares with the hydrogen atoms. According to VSEPR, the shared pairs will be as far away from each other as possible, so the bonds to hydrogen will be 180° apart from each other. The molecule will therefore be linear: H-Be-H

Chapter 6 VSEPR Theory Section 5 Molecular Geometry
VSEPR “combos” ( # of Atoms bonded to central atom / # of lone pairs on central Atom) 2/0 = linear 2/1= bent or angular 2/2= bent or angular 3/0= trigonal planar (triangular) 3/1= trigonal pyramidal (pyramid) 4/0= tetrahedral 5/0= trigonal bipyramidal ****** 6/0= octahedral ****** *****Note- These geometries involve the expanded valence shell ( expanded “octet” ).

Visual Concepts Chapter 6 Lone Pair of Electrons

VSEPR and Basic Molecular Shapes
Visual Concepts Chapter 6 VSEPR and Basic Molecular Shapes

VSEPR and Lone Electron Pairs
Visual Concepts Chapter 6 VSEPR and Lone Electron Pairs

VSEPR Theory, continued
Section 5 Molecular Geometry Chapter 6 VSEPR Theory, continued Sample Problem E Use VSEPR theory to predict the molecular geometry of boron trichloride, BCl3. Boron trichloride has a 3/0 VSEPR combo. Its geometry therefore is trigonal planar.

Section 5 Molecular Geometry Chapter 6 VSEPR Theory, continued VSEPR theory can also account for the geometries of molecules with unshared electron pairs. examples: ammonia, NH3, and water, H2O. The Lewis structure of ammonia shows that the central nitrogen atom has an unshared electron pair: Ammonia’s VSEPR combo is 3/1 and therefore its geometry is trigonal pyramidal.

Section 5 Molecular Geometry Chapter 6 VSEPR Theory, continued The shape of a molecule refers to the positions of atoms only (lone pairs are NOT included in the geometry). H2O has a 2/2 VSEPR combo, and therefore its molecular geometry is “bent,” or angular.

Section 5 Molecular Geometry Chapter 6 VSEPR Theory, continued Sample Problem F Use VSEPR theory to predict the shape of a molecule of carbon dioxide, CO2. The VSEPR combo is 2/0 therefore the geometry is linear.

Chapter 6 Molecular Polarity Molecular Polarity
In terms of their overall electron distribution (negative charge), molecules are considered to be either polar (uneven distribution) or nonpolar ( even distribution). Diatomic Molecules (molecules consisting of only two atoms) In any diatomic molecule , the polarity of the bond between the two atoms will determine the polarity of the molecule. If the bond is polar, the molecule will be polar. If the bond is nonpolar, the molecule will be nonpolar.

Molecules consisting of more than 2 atoms In these molecules, the type(s) of covalent bonds within the molecule along with the molecular geometry (in most cases) must be taken into consideration in determining the polarity of the molecule. If all the bonds within a molecule are nonpolar, the molecule will be nonpolar. (Molecular shape plays no role in determining polarity.) If only one of the bonds in a molecule is polar, the molecule will be polar. (Molecular shape plays no role in determining polarity.)

When 2 or more of the bonds in a molecule are polar, the molecule’s geometry or shape plays a major role in determining the molecule’s polarity. Symmetrical Geometries that generally lead to nonpolarity in molecules: Linear, trigonal planar, tetrahedral, trigonal bipyramidal octahedral. These shapes allow the dipoles in a molecule to cancel each other out as long as the molecule retains its symmetry. ***Note- If all of the bonds in the molecule are not exactly the same then the shape will become distorted and no longer allow polar bonds to cancel resulting in the molecule being polar.

Asymmetrical Geometries that generally lead to polarity in molecules: Bent/Angular, trigonal pyramidal . These shapes will NOT allow any dipoles in a molecule to cancel each other. ***Note- Distortion effects are inconsequential as these shapes are already inherently asymmetrical. REMEMBER molecular polarity must originate with polar bonds!!!!! In other words, NO polar bonds in a molecule = nonpolar molecule

Chapter 6 Hybridization
Hybridization Theory is used to explain how the valence shell orbitals of an atom are rearranged when some atoms form covalent bonds. Hybridization involves the blending of two or more valence shell orbitals of similar energies to produce new hybrid atomic orbitals of equal energies. Hybridization involves two events: promotion followed immediately by hybridization.

Chapter 6 Hybridization (cont.)
Promotion involves the “unpairing “ of any valence shell orbitals that contain an orbital pairing as one of the electrons is sent to an empty orbital in the same valence shell. Hybridization immediately follows promotion as the valence shell orbitals are rearranged (blended) to create new equal energy hybrid orbitals. The new hybrid orbitals are named after the types and numbers of valence shell orbitals that were directly involved in the hybridization. ex. Carbon is sp3 hybridized in covalent bondings. One s orbital and three p orbitals are involved in creating the four equal energy sp3 hybrid orbitals.

Central Atom “Bonding Character”
Chapter 6 Central Atom “Bonding Character” The bonding character of any central atom in a molecule can be used to predict molecular geometries of molecules. This method of predicting the shape of molecules involves describing the kinds of orbitals directly involved in the formation of covalent bonds. Because many of the central atoms involve hybrid orbitals in covalent bond formation, it is also known as hybridization theory. s bonding= linear ex: hydrogen p bonding= linear ex: group 17 elements ***Please note that these are not playing role of central atom.

Chapter 6 Central Atom “Bonding Character” p2 bonding= bent/angular ex: group 16 nonmetals p3 bonding, bonding 2 atoms = bent/angular ex: group 15 nonmetals p3 bonding, bonding 3 atoms = trigonal pyramidal ex: group 15 nonmetals ***Please note that these are not involving hybridized central atoms.

Chapter 6 Central Atom “Bonding Character” sp bonding= linear ex: Beryllium sp2 bonding, bonding 2 atoms = linear ex: Boron sp2 bonding, bonding 3 atoms = trigonal planar ex: Boron sp3 bonding, bonding 2 atoms = linear ex: group 14 nonmetals sp3 bonding, bonding 3 atoms = trigonal planar ex: group 14 nonmetals sp3 bonding, bonding 4 atoms = tetrahedral ex: group 14 nonmetals ***Please note that these are involving hybridized central atoms.

Chapter 6 Central Atom “Bonding Character” sp3d bonding, bonding 5 atoms = trigonal bipyramidal ex: select group 15 nonmetals sp3d2 bonding, bonding 6 atoms = octahedral ex: select group 16 nonmetals ***Please note that these are involving hybridized central atoms with an expanded valence shell.

Geometry of Hybrid Orbitals
Section 5 Molecular Geometry Chapter 6 Geometry of Hybrid Orbitals

Chapter 6 Hybrid Orbitals Visual Concepts
sp3d bonding, bonding 5 atoms = trigonal bipyramidal ex: select group 15 nonmetals

Chapter 6 The Octet Rule Exceptions to the Octet Rule
The octet rule can not be used to explain the bonding in all molecules. Some atoms are able to achieve stability by having fewer than 8 valence electrons or more than 8 valence electrons . Hydrogen forms bonds in which it is surrounded by only two electrons. Beryllium forms bonds in which it is surrounded by only four electrons. (Normally forms ionic bonds with nonmetals but forms covalent bonds with hydrogen.) Boron forms bonds in which it is surrounded by only six electrons.

Chapter 6 The Octet Rule Exceptions to the Octet Rule Resonance
Select elements in Groups 15, 16, & 17 and up can form bonds with expanded valence, involving more than eight electrons. Resonance Resonance Theory is used to explain the bonding in molecules that exist but the bonding cant be explained by normal means. Resonance theory is used to explain bonding under the following conditions: 1) Molecules with an odd number of valence electrons. 2) Molecules in which experimental evidence about the covalent bonds making the molecule conflicts with a reasonable Lewis diagram.

Visual Concepts Chapter 6 Atomic Resonance

Chapter 6 Bond Properties
Chemical bonds, like matter, have measureable characteristics or properties such as bond energy, bond length (distance), bond strength, or bond stability. Bond Energy – the amount of energy released by atoms when they form a chemical bond with one another. Bond energy can also be viewed as the amount of energy required to break a chemical bond. Bond energy can be related to other bond properties such as bond length, bond strength, and bond stability.

Bond Length (distance)- the actual distance between the nuclei of any two bonded atoms Bond strength- a relative measure of how a bond resists being broken. Bond stability- a relative measure of how a bond resists chemical change (e.g. a measure of chemical reactivity)

Bond energy vs. bond length (inversely related) As bond energy increases, bond length decreases. As bond energy decreases, bond length increases. Bond energy vs. bond strength (directly related) As bond energy increases, bond strength increases. As bond energy decreases, bond strength decreases.

Bond energy vs. bond stability (directly related) As bond energy increases, bond stability increases. As bond energy decreases, bond stability decreases. ****Please note that these statements only hold true for comparisons of single bonds to one another Multiple bonds must be considered on a case by case scenario as each of the electron pairs form at different bond energies.

Chapter 6 Bond Properties Bond energy and Chemical Change
In exergonic (exothermic ) reactions energy is released as the reactants decrease their potential energy to form more stable products. The products will be more stable and have higher bond energies than the reactants from which they were formed. In endergonic (endothermic ) reactions energy must be absorbed as the reactants increase their potential energy to form less stable products. The products will be less stable and have lower bond energies than the reactants from which they were formed.

Visual Concepts Chapter 6 Bond Energy

Bond Energies and Bond Lengths for Single Bonds
Properties of Bonds Chapter 6 Bond Energies and Bond Lengths for Single Bonds

Visual Concepts Chapter 6 Bond Length

Bond Length and Stability
Properties of Bonds Chapter 6 Bond Length and Stability

Chapter 6 Network Solids
Network solids are also known as covalent solids or covalent crystals. These substances are not composed of separate, distinct molecules. Instead ,they appear to be a single, giant molecule in which covalent bonds extend from one atom to another in a continuous network pattern throughout the entire substance. There is no involvement of Van der Waals Forces for these molecules.

Chapter 6 Network Solids Properties of Network Solids
Extremely high melting and boiling points. Poor heat and electrical conductors. Extreme hardness. Examples: Diamond and graphite (pure carbon) Silicon Carbide Silicon Dioxide (aka quartz)

Chapter 6 Multiple Choice
Standardized Test Preparation Chapter 6 Multiple Choice 4. According to VSEPR theory, the molecular geometry for is A. tetrahedral. B. trigonal-pyramidal. C. bent or angular. D. None of the above

Chapter 6 Multiple Choice 6. Which molecule is polar? A. CCl4 B. CO2
Standardized Test Preparation Chapter 6 Multiple Choice 6. Which molecule is polar? A. CCl4 B. CO2 C. SO3 D. none of these

Standardized Test Preparation Chapter 6 Multiple Choice 7. What is the hybridization of the carbon atoms in C2H2? A. sp B. sp2 C. sp3 D. The carbon atoms do not hybridize in C2H2.

Standardized Test Preparation Chapter 6 Multiple Choice 8. Which of the following compounds is predicted to have the highest boiling point? A. HCl B. CH3COOH (Note: the two oxygen atoms bond to the carbon) C. Cl2 D. SO2

Standardized Test Preparation Chapter 6 Multiple Choice 9. An unknown substance is an excellent electrical conductor in the solid state and is malleable. What type of chemical bonding does this substance exhibit? A. ionic bonding B. molecular bonding C. metallic bonding D. cannot determine from the information given

Standardized Test Preparation
Chapter 6 Short Answer 10. What does the hybridization model help explain?

Chapter 6 Extended Response Standardized Test Preparation
12. Naphthalene, C10H8, is a nonpolar molecule and has a boiling point of 218°C. Acetic acid, CH3CO2H, is a polar molecule and has a boiling point of 118°C. Which substance has the stronger intermolecular forces? Briefly explain your answer.

Chapter 6 Extended Response Standardized Test Preparation
12. Naphthalene, C10H8, is a nonpolar molecule and has a boiling point of 218°C. Acetic acid, CH3CO2H, is a polar molecule and has a boiling point of 118°C. Which substance has the stronger intermolecular forces? Briefly explain your answer. Answer: Naphthalene has the stronger intermolecular forces even though it is nonpolar, because its boiling point is higher than that of acetic acid. Boiling point is directly correlated to strength of intermolecular forces; the stronger the intermolecular forces, the more energy needed to break all the intermolecular forces, and therefore the higher the boiling point. Naphthalene is so large that its dispersion forces are greater than the sum of the dispersion forces and hydrogen bonding in acetic acid.

Chapter 6 Objectives Describe the electron-sea model of metallic bonding, and explain how the metallic bond accounts for the characteristics of metallic.

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Chapter 6 Objectives Describe the electron-sea model of metallic bonding, and explain how the metallic bond accounts for the characteristics of metallic.

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Presentation on theme: "Chapter 6 Objectives Describe the electron-sea model of metallic bonding, and explain how the metallic bond accounts for the characteristics of metallic."— Presentation transcript:

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