1. Mrs. Rivas Ch 4 Test Review 1. 𝑦=2(𝑥+2)²−3 𝒊𝒇𝒙=−𝟏, 𝒚=𝟐 −𝟏+𝟐 𝟐 −𝟑=−𝟏
Ida S. Baker H.S.
Ch 4 Test Review
(4-1) Graph the following functions; and identify the vertex, the axis of symmetry, the maximum or minimum value and the domain and range and describe the transformation of the graph of 𝑦=𝑥² to your graph.
𝒊𝒇𝒙=−𝟏, 𝒚=𝟐 −𝟏+𝟐 𝟐 −𝟑=−𝟏
(-1, -1)
1. 𝑦=2(𝑥+2)²−3
Vertex: (-2, -3)
Axis: x = -2
Min: y = -3
Domain: all real numbers
Range: all real numbers ≥−𝟑
Transformation: moved 2 units left and 3 units down.

2. Mrs. Rivas Ch 4 Test Review 2. 𝑦=−2(𝑥−2)²−4 𝒊𝒇𝒙=𝟏, 𝒚=−𝟐 𝟏−𝟐 𝟐 −𝟒=−𝟔
Ida S. Baker H.S.
Ch 4 Test Review
(4-1) Graph the following functions; and identify the vertex, the axis of symmetry, the maximum or minimum value and the domain and range and describe the transformation of the graph of 𝑦=𝑥² to your graph.
𝒊𝒇𝒙=𝟏, 𝒚=−𝟐 𝟏−𝟐 𝟐 −𝟒=−𝟔
(1, - 6)
2. 𝑦=−2(𝑥−2)²−4
Vertex: (2, -4)
Axis: x = 2
Max: y = -4
Domain: all real numbers
Range: all real numbers ≤−𝟒
Transformation: Reflected over the x-axis, and moved 2 units right and 4 units down.

3. Mrs. Rivas Ch 4 Test Review 𝒙= −𝒃 𝟐𝒂 𝒚=𝒙²−𝟐𝒙+𝟖 𝒚=(𝟏)²−𝟐(𝟏)+𝟖
Ida S. Baker H.S.
Ch 4 Test Review
(4-2)What is the vertex form of the equation? 𝑥= −𝑏 2𝑎
3. 𝑦=𝑥²−2𝑥+8
𝒙= −𝒃 𝟐𝒂
𝒚=𝒙²−𝟐𝒙+𝟖
a: 1
b: -2
𝒚=(𝟏)²−𝟐(𝟏)+𝟖
𝒙= −(−𝟐) 𝟐(𝟏)
𝒚=𝟏−𝟐+𝟖
𝒚=𝟕
𝒙= 𝟐 𝟐
𝒚= 𝒙−𝟏 +𝟕
𝒙=𝟏

4. Mrs. Rivas Ch 4 Test Review 𝒙= −𝒃 𝟐𝒂 𝒚=−𝒙²−𝟐𝒙+𝟖 𝒚=−(𝟏)²−𝟐(𝟏)+𝟖
Ida S. Baker H.S.
Ch 4 Test Review
(4-2)What is the vertex form of the equation? 𝑥= −𝑏 2𝑎
4. 𝑦=− 𝑥 2 +2𝑥−8
𝒙= −𝒃 𝟐𝒂
𝒚=−𝒙²−𝟐𝒙+𝟖
a: -1
b: 2
𝒚=−(𝟏)²−𝟐(𝟏)+𝟖
𝒙= −(𝟐) 𝟐(−𝟏)
𝒚=−𝟏−𝟐+𝟖
𝒙= −𝟐 −𝟐
𝒚=𝟓
𝒚= 𝒙−𝟏 +𝟓
𝒙=𝟏

5. Mrs. Rivas Ch 4 Test Review 𝟔𝒙 𝒙 +𝟖 𝟖𝒙 𝒙 + 𝟔 𝟔𝒙+𝟖𝒙=𝟏𝟒𝒙 𝒙+𝟖 𝒙+𝟔
Ida S. Baker H.S.
Ch 4 Test Review
(4-4)What is the expression in factored form?
5. 𝑥²+14𝑥+48
𝒙 𝟐 +𝟏𝟒𝒙+𝟒𝟖 𝟔𝒙 𝒙 +𝟖 𝟖𝒙 𝒙
+ 𝟔
𝟔𝒙+𝟖𝒙=𝟏𝟒𝒙
𝒙+𝟖
𝒙+𝟔

6. Mrs. Rivas Ch 4 Test Review − 𝒙 𝟐 +𝒙−𝟒𝟐 𝟑𝒙 𝒙 +𝟕 −𝟔𝒙 𝒙 −𝟔 −𝟔𝒙+𝟕𝒙=𝒙
Ida S. Baker H.S.
Ch 4 Test Review
(4-4)What is the expression in factored form?
6. − 𝑥 2 −𝑥+42
− 𝒙 𝟐 +𝒙−𝟒𝟐 𝟑𝒙 𝒙 +𝟕
−𝟔𝒙 𝒙 −𝟔
−𝟔𝒙+𝟕𝒙=𝒙
− 𝒙+𝟕
𝒙−𝟔

7. Mrs. Rivas Ch 4 Test Review 𝟖𝒙(𝟐𝒙+𝟏) 7. 16𝑥²+8𝑥
Ida S. Baker H.S.
Ch 4 Test Review
(4-4)What is the expression in factored form?
7. 16𝑥²+8𝑥
Since c = 0 we have to factor out.
𝟖𝒙(𝟐𝒙+𝟏)

8. Mrs. Rivas Ch 4 Test Review 𝟏𝟎𝒙 𝟔𝒙 𝟐𝒙 +𝟔 𝒙 + 𝟓 𝟏𝟎𝒙+𝟔𝒙=𝟏𝟔𝒙 𝟐𝒙+𝟔 𝒙+𝟓
Ida S. Baker H.S.
Ch 4 Test Review
(4-4)What is the expression in factored form?
8. 2𝑥²+16𝑥+30
𝟐𝒙 𝟐 +𝟏𝟔𝒙+𝟑𝟎
𝟏𝟎𝒙 𝟐𝒙 +𝟔 𝟔𝒙 𝒙
+ 𝟓
𝟏𝟎𝒙+𝟔𝒙=𝟏𝟔𝒙
𝟐𝒙+𝟔
𝒙+𝟓

9. Mrs. Rivas Ch 4 Test Review − 𝟒𝒙 𝟐 −𝟏𝟔𝒙−𝟒𝟖 −𝟐𝟒𝒙 𝟒𝒙 +𝟖 𝟖𝒙 𝒙 −𝟔
Ida S. Baker H.S.
Ch 4 Test Review
(4-4)What is the expression in factored form?
9. −4𝑥²+16𝑥+48
− 𝟒𝒙 𝟐 −𝟏𝟔𝒙−𝟒𝟖
−𝟐𝟒𝒙 𝟒𝒙 +𝟖 𝟖𝒙 𝒙 −𝟔
−𝟐𝟒𝒙+𝟖𝒙=−𝟏𝟔𝒙
− 𝟒𝒙+𝟖
𝒙−𝟔

10. Mrs. Rivas Ch 4 Test Review 𝑨𝒏𝒔𝒘𝒆𝒓: (𝒙+𝟖)(𝒙−𝟖) 10. 𝑥²−64
Ida S. Baker H.S.
Ch 4 Test Review
(4-4)What is the expression in factored form?
𝒙 𝟐 =𝒙
𝟒 =𝟐
10. 𝑥²−64
𝑨 𝟐 − 𝑩 𝟐 = 𝑨−𝑩 𝑨+𝑩
𝑨𝒏𝒔𝒘𝒆𝒓: (𝒙+𝟖)(𝒙−𝟖)

11. Mrs. Rivas Ch 4 Test Review 𝒙²+𝟏𝟏𝒙+𝟐𝟖=𝟎 (𝒙+𝟕)(𝒙+𝟒)=𝟎 𝒙+𝟕=𝟎 𝒙+𝟒=𝟎 𝒙=−𝟕
Ida S. Baker H.S.
Ch 4 Test Review
(4-5)What are the solutions of the quadratic equation?
11. 𝑥²+11𝑥=−28
𝒙²+𝟏𝟏𝒙+𝟐𝟖=𝟎
Step # 1: Write the equation in standard form.
Step # 2: Factor the quadratic equation.
(𝒙+𝟕)(𝒙+𝟒)=𝟎
𝒙+𝟕=𝟎 𝒙+𝟒=𝟎
Step # 3: Set each answer equal to Zero.
𝒙=−𝟕
𝒙=−𝟒
Step # 4: Solve for x.
The solutions are 𝒙=−𝟕 and 𝒙=−𝟒.

12. Mrs. Rivas Ch 4 Test Review 𝒙²−𝟏𝟐𝒙+𝟑𝟐=𝟎 (𝒙−𝟖)(𝒙−𝟒)=𝟎 𝒙−𝟖=𝟎 𝒙−𝟒=𝟎 𝒙=𝟖
Ida S. Baker H.S.
Ch 4 Test Review
(4-5)What are the solutions of the quadratic equation?
12. 𝑥²−12𝑥+32=0
𝒙²−𝟏𝟐𝒙+𝟑𝟐=𝟎
Step # 1: Write the equation in standard form.
Step # 2: Factor the quadratic equation.
(𝒙−𝟖)(𝒙−𝟒)=𝟎
𝒙−𝟖=𝟎 𝒙−𝟒=𝟎
Step # 3: Set each answer equal to Zero.
𝒙=𝟖
𝒙=𝟒
Step # 4: Solve for x.
The solutions are 𝒙=𝟖 and 𝒙=𝟒.

13. Mrs. Rivas Ch 4 Test Review 𝟑𝒙²−𝟓𝒙+𝟐=𝟎 (𝟑𝒙−𝟐)(𝒙−𝟏)=𝟎 𝟑𝒙−𝟐=𝟎 𝒙−𝟏=𝟎
Ida S. Baker H.S.
Ch 4 Test Review
(4-5)What are the solutions of the quadratic equation?
13. 3 𝑥 2 −5𝑥+2=0
𝟑𝒙²−𝟓𝒙+𝟐=𝟎
Step # 1: Write the equation in standard form.
Step # 2: Factor the quadratic equation.
(𝟑𝒙−𝟐)(𝒙−𝟏)=𝟎
𝟑𝒙−𝟐=𝟎 𝒙−𝟏=𝟎
Step # 3: Set each answer equal to Zero.
𝒙= 𝟐 𝟑
𝒙=𝟏
Step # 4: Solve for x.
The solutions are 𝒙= 𝟐 𝟑 and 𝒙=𝟏.

14. Mrs. Rivas Ch 4 Test Review 𝟐 𝒙 2 +𝟓𝒙−𝟏𝟐=𝟎 (𝟐𝒙−𝟑)(𝒙+𝟒)=𝟎 𝟐𝒙−𝟑=𝟎 𝒙+𝟒=𝟎
Ida S. Baker H.S.
Ch 4 Test Review
(4-5)What are the solutions of the quadratic equation?
14. 2 𝑥 2 =−5𝑥+12
𝟐 𝒙 2 +𝟓𝒙−𝟏𝟐=𝟎
Step # 1: Write the equation in standard form.
Step # 2: Factor the quadratic equation.
(𝟐𝒙−𝟑)(𝒙+𝟒)=𝟎
𝟐𝒙−𝟑=𝟎 𝒙+𝟒=𝟎
Step # 3: Set each answer equal to Zero.
𝒙= 𝟑 𝟐
𝒙=−𝟒
Step # 4: Solve for x.
The solutions are 𝒙= 𝟑 𝟐 and 𝒙=−𝟒.

15. Mrs. Rivas Ch 4 Test Review 15. 𝑥 2 +10𝑥=1
Ida S. Baker H.S.
Ch 4 Test Review
(4-6) Solve each quadratic equation by completing the square.
15. 𝑥 2 +10𝑥=1
𝑥 2 +10𝑥+ 𝒃 𝟐 𝟐 =1+ 𝒃 𝟐 𝟐
𝑥 2 +10𝑥 =
𝑥 2 +10𝑥+25=1+25
𝑥+5 2 =26
𝑥 =± 26
𝑥+5=± 26
𝑥=−𝟓± 𝟐𝟔

16. Mrs. Rivas Ch 4 Test Review 16. 𝑥 2 −12𝑥+32=0
Ida S. Baker H.S.
Ch 4 Test Review
(4-6) Solve each quadratic equation by completing the square.
16. 𝑥 2 −12𝑥+32=0
𝑥 2 −12𝑥+ 𝒃 𝟐 𝟐 =− 𝒃 𝟐 𝟐
𝑥 2 −12𝑥+ − =− −
𝑥 2 −12𝑥+36=−32+36
𝑥−6 2 =4
𝑥−6 2 =± 4
𝑥−6=±2
𝑥=6+2
𝑥=6−2
𝒙=𝟒
𝒙=𝟖

17. Mrs. Rivas Ch 4 Test Review 17. 9 𝑥 2 −12𝑥+4=49
Ida S. Baker H.S.
Ch 4 Test Review
(4-6) Solve each quadratic equation by completing the square.
17. 9 𝑥 2 −12𝑥+4=49
9𝑥 2 −12𝑥=49−4
9𝑥 2 −12𝑥=45
Find the real b.
9𝑥 2 −12𝑥+ 𝟒 = 𝟒
3 3𝑥 2 −𝟒𝑥
9𝑥 2 −12𝑥+4=45+4
3𝑥+2 2 =49
3𝑥 =± 49
3𝑥+2=±7
3𝑥+2=7
3𝑥+2=−7
3𝑥=5
3𝑥=−9
𝑥=−𝟑
𝑥= 𝟓 𝟑

18. Mrs. Rivas Ch 4 Test Review 18. 3 𝑥 2 −42𝑥+78=0
Ida S. Baker H.S.
Ch 4 Test Review
(4-6) Solve each quadratic equation by completing the square.
18. 3 𝑥 2 −42𝑥+78=0
3 𝑥 2 −14𝑥+26
𝑥 2 −14𝑥=−26
𝑥 2 −14𝑥+ − =− −
𝑥 2 −14𝑥+49=−26+49
𝑥−7 2 =23
𝑥−7 2 =± 23
𝑥−7=± 23
𝒙=𝟕± 𝟐𝟑

19. Mrs. Rivas Ch 4 Test Review 19. 2 𝑥 2 +11𝑥−23=−𝑥+3 2 𝑥 2 +12𝑥−26=0
Ida S. Baker H.S.
Ch 4 Test Review
(4-6) Solve each quadratic equation by completing the square.
19. 2 𝑥 2 +11𝑥−23=−𝑥+3
Take out a.
+ 𝒙−𝟑
+ 𝒙−𝟑
2 𝑥 2 +6𝑥−13
2 𝑥 2 +12𝑥−26=0
𝑥 2 +6𝑥−13=0
𝑥 2 +6𝑥 =
𝑥 2 +6𝑥+9=13+9
𝑥+3 2 =22
𝑥 =± 22
𝑥+3=± 22
𝒙=−𝟑± 𝟐𝟐

20. Mrs. Rivas Ch 4 Test Review 𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂
Ida S. Baker H.S.
Ch 4 Test Review
(4-7)Use the Quadratic Formula to solve the equation.
20. −2 𝑥 2 −5𝑥+5=0
𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂
− 𝟐 𝒙 𝟐 +𝟓𝒙−𝟓=𝟎
𝒂=𝟐
𝒙= −(𝟓)± (𝟓)²−𝟒(𝟐)(−𝟓) 𝟐(𝟐)
𝒃=𝟓
𝒄=−𝟓
𝒙=− 𝟓± 𝟐𝟓+𝟒𝟎 𝟒
𝒙= −𝟓± 𝟔𝟓 𝟒

21. Mrs. Rivas Ch 4 Test Review 21. −16 𝑥 2 −56𝑥=−49
Ida S. Baker H.S.
Ch 4 Test Review
(4-7)Use the Quadratic Formula to solve the equation.
21. −16 𝑥 2 −56𝑥=−49
𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂
− 𝟏𝟔 𝒙 𝟐 +𝟓𝟔𝒙−𝟒𝟗=𝟎
𝒂=𝟏𝟔
𝒙= −(𝟓𝟔)± (𝟓𝟔)²−𝟒(𝟏𝟔)(−𝟒𝟗) 𝟐(𝟏𝟔)
𝒃=𝟓𝟔
𝒄=−𝟒𝟗
𝒙= −𝟓𝟔± 𝟑𝟏𝟑𝟔+𝟑𝟏𝟑𝟔 𝟑𝟐
𝒙= −𝟓𝟔±𝟓𝟔 𝟐 𝟑𝟐
= −𝟓𝟔 𝟏± 𝟐 𝟑𝟐
= −𝟓𝟔 𝟏± 𝟐 𝟑𝟐
= −𝟕 𝟏± 𝟐 𝟒

22. Mrs. Rivas Ch 4 Test Review 22. 6 𝑥 2 =𝑥+2
Ida S. Baker H.S.
Ch 4 Test Review
(4-7)Use the Quadratic Formula to solve the equation.
22. 6 𝑥 2 =𝑥+2
𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂
𝟔 𝒙 𝟐 −𝒙−𝟐=𝟎
𝒂=𝟔
𝒙= −(−𝟏)± (−𝟏)²−𝟒(𝟔)(−𝟐) 𝟐(𝟔)
𝒃=−𝟏
𝒄=−𝟐
𝒙= 𝟏± 𝟏+𝟒𝟖 𝟏𝟐
= 𝟏± 𝟒𝟗 𝟏𝟐
𝒙= 𝟏+𝟕 𝟏𝟐
𝒙= 𝟏−𝟕 𝟏𝟐
𝒙= 𝟐 𝟑
𝒙=− 𝟏 𝟐

23. Mrs. Rivas Ch 4 Test Review 23. −5 𝑥 2 =3𝑥−2
Ida S. Baker H.S.
Ch 4 Test Review
(4-7)Use the Quadratic Formula to solve the equation.
23. −5 𝑥 2 =3𝑥−2
𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂
−𝟓 𝒙 𝟐 −𝟑𝒙+𝟐=𝟎
− 𝟓 𝒙 𝟐 +𝟑𝒙−𝟐=𝟎
𝒙= −(𝟑)± (𝟑)²−𝟒(𝟓)(−𝟐) 𝟐(𝟓)
𝒂=𝟓
𝒃=𝟑
𝒙= −𝟑± 𝟗+𝟒𝟎 𝟏𝟎
= −𝟑± 𝟒𝟗 𝟏𝟎
𝒄=−𝟐
𝒙= −𝟑+𝟕 𝟏𝟎
𝒙= −𝟑−𝟕 𝟏𝟎
𝒙= 𝟐 𝟓
𝒙=−𝟏

24. Mrs. Rivas Ch 4 Test Review −𝟑𝟔𝟎 = −𝟏 ∙ 𝟑𝟔𝟎 =𝒊∙ 𝟑𝟔 ∙ 𝟏𝟎 =𝒊∙𝟔∙ 𝟏𝟎
Ida S. Baker H.S.
Ch 4 Test Review
(4-8)Simplify the expression.
24. −360
−𝟑𝟔𝟎 = −𝟏 ∙ 𝟑𝟔𝟎
=𝒊∙ 𝟑𝟔 ∙ 𝟏𝟎
=𝒊∙𝟔∙ 𝟏𝟎
=𝟔𝒊 𝟏𝟎

25. Mrs. Rivas Ch 4 Test Review −𝟏−𝟒+𝟔𝒊+𝟐𝒊 −𝟓+𝟖𝒊 25. −1+6𝑖 +(−4+2𝑖)
Ida S. Baker H.S.
Ch 4 Test Review
(4-8)Simplify the expression.
25. −1+6𝑖 +(−4+2𝑖)
−𝟏−𝟒+𝟔𝒊+𝟐𝒊
−𝟓+𝟖𝒊

26. Mrs. Rivas Ch 4 Test Review 𝟐−𝟓𝒊−𝟑−𝟒𝒊 𝟐−𝟑−𝟓𝒊−𝟒𝒊 −𝟏−𝟗𝒊 26. 2−5𝑖 −(3+4𝑖)
Ida S. Baker H.S.
Ch 4 Test Review
(4-8)Simplify the expression.
26. 2−5𝑖 −(3+4𝑖)
𝟐−𝟓𝒊−𝟑−𝟒𝒊
𝟐−𝟑−𝟓𝒊−𝟒𝒊
−𝟏−𝟗𝒊

27. Mrs. Rivas Ch 4 Test Review −𝟓+𝟖+𝟑𝒊−𝟐𝒊 𝟑+𝒊 27. −5+3𝑖 −(−8+2𝑖)
Ida S. Baker H.S.
Ch 4 Test Review
(4-8)Simplify the expression.
27. −5+3𝑖 −(−8+2𝑖)
−𝟓+𝟖+𝟑𝒊−𝟐𝒊
𝟑+𝒊

28. Mrs. Rivas Ch 4 Test Review −𝟔+𝟑𝟔𝒊 + 𝟒𝒊−𝟐𝟒𝒊² −𝟔+𝟒𝟎𝒊−𝟐𝟒(−𝟏) −𝟔+𝟒𝟎𝒊+𝟐𝟒
Ida S. Baker H.S.
Ch 4 Test Review
(4-8)Simplify the expression.
28. (6−4𝑖)(−1+6𝑖)
−𝟔+𝟑𝟔𝒊
+ 𝟒𝒊−𝟐𝟒𝒊²
−𝟔+𝟒𝟎𝒊−𝟐𝟒(−𝟏)
−𝟔+𝟒𝟎𝒊+𝟐𝟒
−𝟔+𝟐𝟒+𝟒𝟎𝒊
𝟏𝟖+𝟒𝟎𝒊

29. Mrs. Rivas Ch 4 Test Review 𝟏𝟔−𝟒𝒊 − 𝟒𝒊+𝒊² 𝟏𝟔−𝟖𝒊+(−𝟏) 𝟏𝟔−𝟏−𝟖𝒊 𝟏𝟓−𝟖𝒊
Ida S. Baker H.S.
Ch 4 Test Review
(4-8)Simplify the expression.
−𝑖 2
=(4−𝑖)(4−𝑖)
𝟏𝟔−𝟒𝒊
− 𝟒𝒊+𝒊²
𝟏𝟔−𝟖𝒊+(−𝟏)
𝟏𝟔−𝟏−𝟖𝒊
𝟏𝟓−𝟖𝒊

30. Mrs. Rivas Ch 4 Test Review ∙ 𝟒+𝒊 𝟒+𝒊 = (−𝟏+𝟑𝒊)(𝟒+𝒊) (𝟒−𝒊)(𝟒+𝒊)
Ida S. Baker H.S.
Ch 4 Test Review
(4-8)Simplify the expression.
30. −1+3𝑖 4−𝑖
∙ 𝟒+𝒊 𝟒+𝒊
= (−𝟏+𝟑𝒊)(𝟒+𝒊) (𝟒−𝒊)(𝟒+𝒊)
= −𝟒−𝒊+𝟏𝟐𝒊+𝟑𝒊² 𝟏𝟔+𝟒𝒊−𝟒𝒊−𝒊²
= −𝟒+𝟏𝟏𝒊+𝟑(−𝟏) 𝟏𝟔−(−𝟏)
= −𝟒+𝟏𝟏𝒊−𝟑 𝟏𝟕
= −𝟒−𝟑+𝟏𝟏𝒊 𝟏𝟕
= −𝟕+𝟏𝟏𝒊 𝟏𝟕

31. Mrs. Rivas Ch 4 Test Review 𝒙²+𝟑𝟔=𝟎 −𝟑𝟔 −𝟑𝟔 𝒙²=−𝟑𝟔 𝒙=± −𝟑𝟔 𝒙=±𝟔𝒊
Ida S. Baker H.S.
Ch 4 Test Review
Find the factors of each expression.
34. 𝑥 2 +36
𝒙²+𝟑𝟔=𝟎
−𝟑𝟔
−𝟑𝟔
𝒙²=−𝟑𝟔
𝒙=± −𝟑𝟔
𝒙=±𝟔𝒊

32. Mrs. Rivas Ch 4 Test Review −𝟒𝒙 2 −𝟒𝟗=𝟎 +𝟒𝟗 +𝟒𝟗 −𝟒𝒙²=𝟒𝟗 −𝟒 −𝟒
Ida S. Baker H.S.
Ch 4 Test Review
Find the factors of each expression.
35. −4𝑥 2 −49
−𝟒𝒙 2 −𝟒𝟗=𝟎
+𝟒𝟗
+𝟒𝟗
−𝟒𝒙²=𝟒𝟗 −𝟒 −𝟒
𝒙 2 = 𝟒𝟗 −𝟒
𝒙= 𝟒𝟗 −𝟒
= 𝟒𝟗 −𝟒
=± 𝟕 𝟐𝒊

33. Mrs. Rivas Ch 4 Test Review
Ida S. Baker H.S.
Ch 4 Test Review
Find all solutions to each quadratic equation.
36. 2 𝑥 2 −3𝑥+5
𝟐𝒙 𝟐 −𝟑𝒙+𝟓 𝟐𝒙 𝟐𝒙 −𝟓
−𝟓𝒙 𝒙
+ 𝟏
𝟐𝒙−𝟓𝒙=−𝟑𝒙
2𝑥−5
𝑥+1 =0
2𝑥−5=0
𝑥+1=0
𝑥= 𝟓 𝟐
𝑥= −𝟏

34. Mrs. Rivas Ch 4 Test Review
Ida S. Baker H.S.
Ch 4 Test Review
Find all solutions to each quadratic equation.
37. −𝑥 2 +2𝑥−10=0
𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂
− 𝒙 𝟐 −𝟐𝒙+𝟏𝟎=𝟎
𝒙= −(−𝟐)± (−𝟐)²−𝟒(𝟏)(𝟏𝟎) 𝟐(𝟏)
𝒂=𝟏
𝒃=−𝟐
𝒙= 𝟐± 𝟒−𝟒𝟎 𝟐
= 𝟐± −𝟑𝟔 𝟐
𝒄=𝟏𝟎
= 𝟐±𝟔𝒊 𝟐
= 𝟐 𝟐 ± 𝟔𝒊 𝟐
=𝟏±𝟑𝒊