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Warm–up #5 1. Simplify 3 108 (

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1 Warm–up #5 1. Simplify (π‘₯+𝑦) 7 2. Multiply βˆ’1

2 Warm–up #5 Solutions 1. Simplify (π‘₯+𝑦) 7 3 2βˆ™2βˆ™3βˆ™3βˆ™3 3 (π‘₯+𝑦)(π‘₯+𝑦)(π‘₯+𝑦)(π‘₯+𝑦)(π‘₯+𝑦)(π‘₯+𝑦)(π‘₯+𝑦) =3 (π‘₯+𝑦) 2 3 4(π‘₯+𝑦)

3 Warm–up #5 Solutions 2. Multiply βˆ’1 = βˆ’ βˆ’1 3 =2 7βˆ™7βˆ™3 βˆ’ βˆ™3βˆ™7 βˆ’ 3 =2 7 3 βˆ’ βˆ’ 3 =14 3 βˆ’ βˆ’ 3 =

4 Homework Log Wed 9/23 Lesson 1 – 8 Learning Objective:
To simplify radical expressions into simplest radical form Hw: #113 Pg. 77 #47 – 99 odd

5 9/23/15 Lesson 1 – 8 Simplest Radical Form Day 2
Advanced Math/Trig

6 Learning Objective To simplify radical expressions into simplest form

7 Simplest Radical Form 1. No negative or zero exponents 2. Radicand doesn’t have power β‰₯ index 3. No in denom 4. No fractions in 5. Index as small as possible index radicand

8 Rationalizing Denominator
No radicals in the denominators! = βˆ™7 = = βˆ™2 = 3 3βˆ™ βˆ™2βˆ™2 = = Need a group of 3 βˆ™ βˆ™

9 Rationalizing Denominator
βˆ™ (3+ 5 ) (3+ 5 ) π‘₯ 9 𝑦 2 = 3 2π‘₯ 3βˆ™3βˆ™π‘¦βˆ™π‘¦ = 3 6π‘₯𝑦 3𝑦 4. 3 3βˆ’ 5 Use difference of squares (a + b)(a – b) = π‘Ž 2 βˆ’ 𝑏 2 = 3(3+ 5 ) (3) 2 βˆ’ ( 5 ) 2 = βˆ’5 = βˆ™ 3 3𝑦 3 3𝑦

10 Simplify π‘₯ 2 9 𝑦 10 Need groups of 6 = 6 π‘₯ 𝑦 10 = π‘₯ 2 𝑦 𝑦 12 = π‘₯ 2 𝑦 𝑦 2 𝑦 3 𝑧 𝑦 4 𝑧 3 Same index, reduce first! = 1 2𝑦 𝑧 2 = 2𝑦 2𝑦𝑧 βˆ™ 𝑦 𝑦 2 βˆ™ 2𝑦 2𝑦 = 3 9π‘₯𝑦 3 𝑦 2

11 Simplify 7. 3 2βˆ’3 2 βˆ™ 2 βˆ’1 2 = βˆ’3 2 2 βˆ’3(6) (2 2 ) 2 βˆ’ (6) 2 = βˆ’6 2 βˆ’ βˆ’36 = βˆ’ βˆ’28 = 3 2 βˆ’ βˆ’3(2) βˆ™ = βˆ’18 8βˆ’36 = 3βˆ’ Can all be divided by βˆ’2

12 Simplify = = (3) = = 1 3 3βˆ™3 = 3 3 3 βˆ™ = βˆ™

13 Simplify βˆ™ βˆ’ 3 = (2 5 ) 2 βˆ’ ( 3 ) 2 = βˆ’3 =

14 Simplify 11. 3 π‘₯ 3 + π‘₯ π‘₯+4 = π‘₯ 2 (3π‘₯+1) + 4(3π‘₯+1) = x 3π‘₯ π‘₯+1 =(x+2) 3π‘₯+1

15 Simplify 12. (2βˆ’ 3 ) βˆ’2 = 1 (2βˆ’ 3 ) 2 = (7) 2 βˆ’ (4 3 ) 2 = = 7+4 3 = 1 4βˆ’ βˆ™ = 1 7βˆ’4 3 = βˆ’16(3)

16 Ticket Out the Door Simplify π‘₯ 3 π‘₯ 6 Explain what you did to simplify.

17 Homework #113 Pg. 77 #47 – 99 odd


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