1. Chapter 6 TRANSFORMATIONS OF FUNCTIONS AND THEIR GRAPHS
Section 6.1 Shifts, Reflections, and Symmetry
Section 6.2 Vertical Stretches and Compressions
Section 6.3 Horizontal Stretches and Combinations
of Transformations
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

2. SHIFTS, REFLECTIONS, AND SYMMETRY
6.1
SHIFTS, REFLECTIONS, AND SYMMETRY
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

3. Vertical Shift
If g(x) is a function and k is a positive constant, then the graph of • y = g(x) + k is the graph of y = g(x) shifted vertically upward by k units. • y = g(x) − k is the graph of y = g(x) shifted vertically downward by k units.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

4. Horizontal Shift
If g(x) is a function and k is a positive constant, then the graph of • y = g(x + k) is the graph of y = g(x) shifted horizontally to the left by k units. • y = g(x − k) is the graph of y = g(x) shifted horizontally to the right by k units.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

5. Inside Versus Outside Changes
Translations of a function f(x) can be expressed in the form y = f(x − h) + k. • Outside change by a constant k shifts the graph up by k units if k > 0 (down if k < 0) • Inside change by a constant h shifts the graph right by h units if h > 0 (left if h < 0)
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

6. Combining Horizontal and Vertical Shifts
Example A graph of f(x) = x2 is shown in blue. Define g by shifting the graph of f to the right 2 units and down 1 unit; the graph of g is shown in red. Find a formula for g in terms of f. Find a formula for g in terms of x. Solution
The graph of g is the graph of f shifted to the right 2 units and down 1 unit, so a formula for g is g(x) = f(x − 2) − 1. Since f(x) = x2, we have f(x − 2) = (x − 2)2. Therefore, g(x) = (x − 2)2 − 1.
y = f(x)
y = g(x)
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

7. A Formula for a Reflection
For a function f: • The graph of y = −f(x) is a reflection of the graph of y = f(x) about the x-axis. • The graph of y = f(−x) is a reflection of the graph of y = f(x) about the y-axis.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

8. Combining Shifts and Reflections
Consider the function
f(x) = 1/x.
Consider the reflection of this function through the x-axis together with a shift of 4 units in the positive vertical direction
g(x) = 4 – 1/x
Notice how both functions are asymptotic to the y-axis, but the horizontal asymptote for the transformed function has shifted up 4 units.
Graph of y = f(x) = 1/x
and y = g(x) = 4 – 1/x
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

9. Even Functions Are Symmetric About the y-Axis
If f is a function, then f is called an even function if, for all values of x in the domain of f, f(−x) = f(x). The graph of f is symmetric about the y-axis.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

10. Example of an Even Function
Consider the function f(x) = x2 – 4. Note that f(– x) = (– x)2 – 4 = x2 – 4 So f(x) = f(–x) . This means that f(x) is an even function, as is verified in the graph by its symmetry with respect to the y-axis.
Graph of y = f(x) = x2 – 4
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

11. Odd Functions Are Symmetric About the Origin
If f is a function, then f is called an odd function if, for all values of x in the domain of f, f(−x) = − f(x). The graph of f is symmetric about the origin.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

12. Example of an Odd Function
Consider the function f(x) = x3. Note that f(–x) = (– x)3 = – x3 So f(x) = – f(–x) . This means that f(x) is an odd function, as is verified in the graph by its symmetry with respect to the origin.
Graph of y = f(x) = x3
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

13. VERTICAL STRETCHES AND COMPRESSIONS
6.2
VERTICAL STRETCHES AND COMPRESSIONS
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

14. Formula for Vertical Stretch or Compression
If f is a function and k is a constant, then the graph of y = k · f(x) is the graph of y = f(x) • Vertically stretched by a factor of k, if k > 1. • Vertically compressed by a factor of k, if 0 < k < 1. • Vertically stretched or compressed by a factor |k| and reflected across x-axis, if k < 0.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

15. Vertical Stretch: An Amplifier
An amplifier takes a weak signal from a recording and transforms it into a stronger signal to power a set of speakers. Notice that the wave crests of the amplified signal are 3 times as high as those of the original signal; similarly, the amplified wave troughs are 3 times deeper than the original wave troughs. The amplifier has boosted the strength of the signal by a factor of 3. If f is the original signal function and V is the amplified signal function, then V(t) = 3・f(t). As expected, a vertical stretch of the graph of f(t) corresponds to an outside change in the formula.
The figure shows a graph of an audio signal (in volts) as a function of time, t, both before and after amplification.
Signal strength
(volts)
Amplified signal V(t)
Original signal f(t)
t, time
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

16. Negative Stretch Factor
The Figure gives a graph of a function y = f(x), together with a graph of y =− 2 · f(x) and the intermediate transformation y =2 · f(x).
The stretch factor is k = −2. We think of y = −2 f(x) as a combination of two separate transfor-mations of y = f(x). First, the graph is stretched by a factor of 2, then it is reflected across the x-axis.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

17. Stretch Factors and Average Rates of Change
If g(x) = k · f(x), then on any interval, the average rate of change of g equals k · (Average rate of change of f) .
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

18. Stretch Factors and Average Rates of Change
Example The function s(t) gives the distance (miles) in terms of time (hours). If the average rate of change of s(t) on 0 ≤ t ≤ 4 is 70 mph, what is the average rate of change of ½ s(t) on this interval? Solution The average rate of change of ½ s(t) on the interval 0 ≤ t ≤ 4 is ½ the average rate of change of s(t) on that interval, so it is ½ of 70 or 35 mph.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

19. Combining Stretches and Shifts
Example 3
The function y = f(x)
has the graph shown:
Graph the function
g(x) = − ½ f(x + 3) − 1.
Solution
To combine several transformations, always work from inside the parentheses outward. The graphs corresponding to each step are shown.
Step 1: shift 3 units
to the left
Step 2: vertically
compress by ½
Step 3: reflect about
the x-axis
Step 4: shift down 1 unit
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

20. HORIZONTAL STRETCHES AND COMBINATIONS OF TRANSFORMATIONS
6.3
HORIZONTAL STRETCHES AND COMBINATIONS OF TRANSFORMATIONS
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

21. Formula for Horizontal Stretch or Compression
If f is a function and k a positive constant, then the graph of y = f(k∙x) is the graph of y = f(x)
• Horizontally compressed by a factor of 1/k if k > 1,
• Horizontally stretched by a factor of 1/k if k < 1.
Horizontally stretched or compressed by a factor 1/|k| and reflected across y-axis, if k < 0.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

22. A Horizontal Stretch
Example 1 The values and graph of the function f(x) are shown in blue. Make a table and a graph of the function g(x) = f(½ x). Solution x
f(x)
g(x) -3 -6 -2 2 -4 -1 1 4 3 6
g(x) = f(½ x)
f(x)
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

23. Examples: Horizontal Stretch or Compression
Example 3 Match the functions f(t) = et, g(t) = e0.5t, h(t) = e0.8t, j(t) = e2t with the graphs Solution Since the function j(t) = e2t climbs fastest of the four and g(t) = e0.5t climbs slowest, graph A must be j and graph D must be g. Similarly, graph B is f and graph C is h. A B C D
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

24. Multiple Inside Changes
Example
(a) Rewrite the function y = f(2x − 6) in the form y = f(B(x − h)).
(b) Use the result to describe the graph of y = f(2x − 6) as the result of first applying a horizontal stretch or compression to the graph of f and then applying a horizontal shift. What is the stretch/compression factor? What is the shift?
Solution
(a) We have f(2x − 6) = f(2(x − 3)).
(b) Thus, the graph of y = f(2x − 6) can be obtained from the graph of y = f(x) by first horizontally compressing it by a factor of ½ and then shifting horizontally right by h = 3 units.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

25. Ordering Horizontal and Vertical Transformations
For nonzero constants A, B, h and k, the graph of the function y = A f(B (x − h)) + k is obtained by applying the transformations to the graph of f(x) in the following order: • Horizontal stretch/compression by a factor of 1/|B| • Horizontal shift by h units • Vertical stretch/compression by a factor of |A| • Vertical shift by k units If A < 0, follow the vertical stretch/compression by a reflection about the x-axis. If B < 0, follow the horizontal stretch/compression by a reflection about the y-axis.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally

26. Multiple Transformations
Example 4 (a) Let y = 5(x + 2) Determine the values of A, B, h, and k when y is put in the form y = Af(B(x − h)) + k with f(x) = x2. List the transformations applied to f(x) = x2 to give y = 5(x + 2) (b) Sketch a graph of y = 5(x + 2)2 + 7, labeling the vertex. Solution
(b)
If f(x) = x2, we see y = 5(x + 2)2 + 7 =
5f(x + 2) + 7, so A = 5, B = 1, h = −2, and k = 7. Based on the values of these constants, we carry out these steps:
• Horizontal shift 2 to the left of the graph of f(x) = x2.
• Vertical stretch of the resulting graph by a factor of 5.
• Vertical shift of the resulting graph up by 7.
Since B = 1, there is no horizontal compression, stretch, or reflection.
Functions Modeling Change: A Preparation for Calculus, 5th Edition, 2014, Connally