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Welcome to the 2nd Annual WILDCAT INVITATIONAL

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Presentation on theme: "Welcome to the 2nd Annual WILDCAT INVITATIONAL"— Presentation transcript:

1 Welcome to the 2nd Annual WILDCAT INVITATIONAL
Thanks to our sponsors: Stafford Printing and Mu Alpha Theta Teachers please report to the front. Students please make sure you have 15 squares and a pencil. Write your full name, school, and level on each square. No calculators are allowed.

2 Good Luck! You will have 2 minutes per problem. Circle your answer.
Raise card immediately to submit. The awards ceremony will follow the Level II competition.

3 Find the maximum value for:
PRACTICE Find the maximum value for:

4 Answer Graph is translated down 4 units and has an amplitude of 12.
Therefore = 8 which becomes the maximum value.

5 1 Simplify the following:

6 Answer 1 This is:

7 2 Both roots of the quadratic equation
are positive prime numbers. Find the value(s) for k.

8 ANSWER 2 Let the roots be a and b, where ab=k and a + b = 63
or b = 63 – a Using substitution (63-a)b = k For b to be prime a = 2, so b=61 Therefore the only value for k is 122.

9 3 Simplify the following:

10 Answer 3 Rewriting using exponents: Therefore:

11 4 What is the area of the region inside the square of side length 5 and between the lines 2x + y = 4 and x + y = 6 ?

12 Answer 4 Area of square is 25 Area of lower triangle is 4
Area of upper triangle is 8 Therefore desired region is or 13 sq. units

13 5 Going in opposite directions along straight paths, a motorcyclist at 45mph and a train at 35mph pass each other. The train is 469 1/3 feet long. How many seconds does it take the cyclist to pass the caboose?

14 Answer 5 Combined rates is 45+35=80
d=rt so t=d/r where distance is the trains length, giving us:

15 6 Suppose g(-2) = g(7) =0 and these are the only zeroes of g. Find all the zeroes of:

16 ANSWER 6 So zeroes are -1, 2, and 5.

17 7 A sequence of integers: Is defined as follows: Find

18 ANSWER 7 Notice the pattern:

19 8 The population of a city is given by the exponential function If the population was 250,000 in 1940 and 300,000 in 1960, what was the population in 2000?

20 ANSWER 8 Population grows by 20% every 20 years
So 300,000(1.2)= 360,000 in 1980 And 360,000(1.2)=432,000 in 2000

21 9 Solve:

22 ANSWER 9 Determine common base

23 10 Find the area of trapezoid ABCD if AE has length 10, BC has length 11sqrt2, DE has length 4, AE is perpendicular to AB, as is EB and BC,, <BEC=45°, and triangle ABE has area 60.

24 ANSWER 10 Area of trapezoid ABCD

25 11 The average of a set of 25 numbers is 10.
If two numbers, 16 and 27, are removed from the set, what is the average of the remaining numbers?

26 ANSWER 11 Let x=sum of 1st 25 numbers So average is 9

27 12 Square ABCD has sides 8 units in length.
A circle is constructed through vertices B and C tangent to side AD. Find the radius of the circle.

28 ANSWER 12

29 13 The sum of three numbers is 205. The ratio of the first to the second is ¾ and the ratio of the second to the third is 3/5. What is the value of the second number.

30 ANSWER 13 So the 2nd number is 60.

31 14 If ,find the value of Leave answer in terms of x.

32 ANSWER 14 Rewriting in exponential form:

33 15 The measure of the interior angles of a convex polygon are in arithmetic progression. If the smallest angle is 100° and the largest angle is 140° find the number of sides the polygon has.

34 ANSWER 15 Let n= number of sides
The sum of the interior angles is (n-2)180 The sum of an arithmetic progression is n/2(sum of first and last term


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