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ME 475/675 Introduction to Combustion

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1 ME 475/675 Introduction to Combustion
Lecture 34 Flammability limits, Flame quenching

2 Announcements HW 14 Ch. 8 (1, 13, 15, 16) Integrated BS/MS Degree
Due Wednesday Integrated BS/MS Degree Term Project Discuss on Monday

3 Laminar Premixed flames
So far, we talked about flame speeds and thickness Now What mixtures (equivalence ratios) can ignite? How much energy is required ignite a flammable mixture? What does it take to extinguish a self-sustaining flame?

4 Stoichiometric Air to Fuel Mass ratio, Table 8.4 page 291
𝜈= 𝐴 𝐹 π‘ π‘‘π‘œπ‘–π‘ Stoichiometric Air to Fuel Mass ratio, 𝜈= 𝐴 𝐹 π‘ π‘‘π‘œπ‘–π‘ For hydrocarbons ~15-17 Less for CO and Oxygenated hydrocarbons (contain O atoms) Greater for H2

5 Flammability Limits, Table 8.4 page 291
𝜈= 𝐴 𝐹 π‘ π‘‘π‘œπ‘–π‘ πœ’ 𝐢 𝐻 4 ,πΏπ‘’π‘Žπ‘› Flames only propagate within certain fuel/oxidizer mixture equivalence ratio ranges Ξ¦ π‘šπ‘–π‘› <Ξ¦< Ξ¦ π‘šπ‘Žπ‘₯ Ξ¦ π‘šπ‘–π‘› = Ξ¦ π‘™π‘œπ‘€π‘’π‘Ÿ = Ξ¦ π‘™π‘’π‘Žπ‘› Ξ¦ π‘šπ‘Žπ‘₯ = Ξ¦ π‘’π‘π‘π‘’π‘Ÿ = Ξ¦ π‘Ÿπ‘–π‘β„Ž See page 291, Table 8.4 for limits Ξ¦= 𝐴 𝐹 π‘ π‘‘π‘œπ‘–π‘ 𝐴 𝐹 = 𝜈 𝐴 𝐹 = π‘š 𝐹 π‘š 𝐹,𝑆𝑑 π‘š 𝐴,𝑆𝑑 π‘š 𝐴 πœ’ 𝐢 𝐻 4 ,πΏπ‘’π‘Žπ‘› = 𝑁 𝐢 𝐻 𝑁 𝐢 𝐻 𝑁 π΄π‘–π‘Ÿ = 𝑁 π΄π‘–π‘Ÿ 𝑁 𝐢 𝐻 = π‘š π΄π‘–π‘Ÿ π‘š 𝐢 𝐻 π‘€π‘Š 𝐢 𝐻 4 π‘€π‘Š π΄π‘–π‘Ÿ For some hydrocarbons Ξ¦ π‘šπ‘–π‘› β‰ˆ0.5 But smaller for acetylene (C2H2) (very wide range) Carbon monoxide (CO) N-Decane (C10H22) Ethylene (ethane) (C2H4) Hydrogen (H2)

6 Example 8.5, p 294 (turn in next time for EC)
A full propane cylinder from a camp stove leaks its contents of 1.02 lbm ( kg) into a 12’x14’x8’ (3.66 m x 4.27 m x 2.44 m) room at 20Β°C and 1 atm. After a long time, the fuel gas and room are well mixed. Is the mixture in the room flammable?

7 Williams Criteria How much energy is required to ignite a mixture?
What does it take to extinguish a flame? β€œWilliams Criteria” (rule of thumb) Ignition will occur if enough energy is added to a slab of thickness 𝛿 (laminar flame thickness) to raise it to the adiabatic flame temperature, Tad. A flame will be sustained if its rate of chemical heat release insides a slab is roughly equal to heat loss by conduction out of the slab (why not radiation?) Example extinguishment methods Pass a flame through a narrow tube or slot so it losses too much heat to the surfaces Dilute using water (or thermal?) Interrupt chemical kinetics (halogens) Blow reaction away (loses fuel or heat)

8 Cold Wall Quenching Define Quenching Distance, 𝑑
dTube dSlot Define Quenching Distance, 𝑑 Smallest dimension that allows flame to pass Experimentally determined by shutting off flow of a premixed stabilized flame dTube = (1.2 to 1.5) dSlot

9 Simplified Quenching Analysis for a Slot
𝐿 𝛿 𝑄 π‘π‘œπ‘›π‘‘ 𝑄 β€²β€²β€² 𝑉 𝑄 π‘π‘œπ‘›π‘‘ 𝑑 b>2 𝑇 b=2 π‘₯ To quench, we need: 𝑄 β€²β€²β€² 𝑉< 𝑄 π‘π‘œπ‘›π‘‘ =βˆ’π΄π‘˜ 𝑑𝑇 𝑑π‘₯ βˆ’ π‘š 𝐹 β€²β€²β€² Ξ” β„Ž 𝐢 𝛿𝐿𝑑 < 2𝛿𝐿 π‘˜ 𝑇 𝑏 βˆ’ 𝑇 𝑀 𝑑 𝑏 𝑑 2 < 2π‘π‘˜ 𝑇 𝑏 βˆ’ 𝑇 𝑀 βˆ’ π‘š 𝐹 β€²β€²β€² Ξ” β„Ž 𝑐 = 2π‘π‘˜ 𝑇 𝑏 βˆ’ 𝑇 𝑒 𝑆 𝐿 2 𝜌 𝑒 2𝛼 1+𝜈 𝑐 𝑝 𝜈+1 𝑇 𝑏 βˆ’ 𝑇 𝑒 = 4𝑏 𝛼 2 𝑆 𝐿 2 , so need 𝑑<2 𝛼 𝑆 𝐿 𝑏 If 𝑇 𝑀 = 𝑇 𝑒 ; and since Ξ” β„Ž 𝑐 = 𝑐 𝑝 𝜈+1 𝑇 𝑏 βˆ’ 𝑇 𝑒 and 𝑆 𝐿 2 =2𝛼 1+𝜈 βˆ’ π‘š 𝐹 β€²β€²β€² 𝜌 𝑒

10 Quenching will take place when
𝑄 β€²β€²β€² 𝑉 𝑄 π‘π‘œπ‘›π‘‘ 𝑑 𝛿 𝐿 𝑇 π‘₯ b=2 b>2 𝑑 𝛿 𝑑<2 𝛼 𝑆 𝐿 𝑏 = 𝑏 𝛿, 𝑏 = 2 or larger But 𝛿= 2𝛼 𝑆 𝐿 See data for methane/air mixtures Flame temperature decreases and thickness increases for non-stoichiometric mixtures Quenching distance increases (follows flame thickness behavior)

11 Data, Table 8.4 page 291 Highest temperature and thinnest flame at Ξ¦>1, Also smallest 𝑑

12 Example 8.4, page 290 Turn in next time for EC
Consider the design of a laminar-flow, adiabatic, flat-flame burner consisting of a square arrangement of thin-walled tubes as illustrated in the sketch. Fuel-air mixture flows through both the tubes and the interstices between the tubes. It is desired to operate the burner with a stoichiometric methane-air mixture exiting the burner tubes at 300 K and 5 atm. Determine the mixture mass flow rate per unit cross-sectional area at the design condition. Estimate the maximum tube diameter allowed so that flashback will be prevented. Methane (CH4)/air, Ξ¦=1, T=300 K, P=5 atm

13 End 2017 Ran out of time by a 2 minutes

14 Ignition 𝑑𝑇 𝑑π‘₯ 𝑅 πΆπ‘Ÿπ‘–π‘‘ The minimum electrical spark energy capable of igniting a flammable mixture. It is dependent on the temperature, pressure and equivalence ratio of the mixture What is the critical (minimum) radius of a spark that will propagate 𝑄 β€²β€²β€² 𝑉> 𝑄 π‘π‘œπ‘›π‘‘ βˆ’ π‘š 𝐹 β€²β€²β€² Ξ” β„Ž 𝑐 πœ‹ 𝑅 π‘π‘Ÿπ‘–π‘‘ 3 >π‘˜ 4πœ‹ 𝑅 π‘π‘Ÿπ‘–π‘‘ 𝑑𝑇 𝑑π‘₯ 𝑅 πΆπ‘Ÿπ‘–π‘‘ ~π‘˜ 4πœ‹ 𝑅 π‘π‘Ÿπ‘–π‘‘ 2 𝑇 𝑏 βˆ’ 𝑇 𝑒 𝑅 π‘π‘Ÿπ‘–π‘‘ 𝑅 π‘π‘Ÿπ‘–π‘‘ 2 β‰₯ 3π‘˜ 𝑇 𝑏 βˆ’ 𝑇 𝑒 βˆ’ π‘š 𝐹 β€²β€²β€² Ξ” β„Ž 𝑐 = 2𝛼 1+𝜈 𝜌 𝑒 𝑆 𝐿 2 3π‘˜ 𝑇 𝑏 βˆ’ 𝑇 𝑒 𝑐 𝑝 1+𝜈 𝑇 𝑏 βˆ’ 𝑇 𝑒 = 6 𝛼 2 𝑆 𝐿 2 ; 𝑅 π‘π‘Ÿπ‘–π‘‘ β‰₯ 6 𝛼 𝑆 𝐿 = 𝛿 𝑆 𝐿 2 =2𝛼 1+𝜈 βˆ’ π‘š 𝐹 β€²β€²β€² 𝜌 𝑒 ; 1 βˆ’ π‘š 𝐹 β€²β€²β€² = 2𝛼 1+𝜈 𝜌 𝑒 𝑆 𝐿 2 ; Ξ” β„Ž 𝑐 = 𝑐 𝑝 1+𝜈 𝑇 𝑏 βˆ’ 𝑇 𝑒 ; 𝛼= π‘˜ 𝜌 𝑒 𝑐 𝑝 ; 𝛿= 2𝛼 𝑆 𝐿

15 Energy to bring critical volume to Tb
𝐸 𝑖𝑔𝑛 = π‘š π‘π‘Ÿπ‘–π‘‘ 𝑐 𝑝 𝑇 𝑏 βˆ’ 𝑇 𝑒 π‘š π‘π‘Ÿπ‘–π‘‘ = 4 3 πœ‹ 𝑅 π‘π‘Ÿπ‘–π‘‘ 3 𝜌 𝑏 = 4 3 πœ‹ 𝛼 𝑆 𝐿 𝜌 𝑏 = 𝛼 𝑆 𝐿 𝑃 𝑅 𝑏 𝑇 𝑏 𝐸 𝑖𝑔𝑛 =61.56𝑃 𝛼 𝑆 𝐿 𝑐 𝑝 𝑅 𝑏 𝑇 𝑏 βˆ’ 𝑇 𝑒 𝑇 𝑏 ~ 𝑃 𝑃 3 ~ 𝑃 βˆ’2 𝛼~ 𝑇 𝑒 𝑇 𝑃 ; 𝑆 𝐿 ~ 𝑇 𝑃 0 𝑒π‘₯𝑝 𝐸 𝐴 2 𝑅 𝑒 𝑇 𝑏 not normally considered reliable Agrees with measurements at low pressure Need lots of energy at low pressure Hard to restart jet engines at low pressures 𝐸 𝑖𝑔𝑛 decreases as Tu increases Table 8.5 page 298 Different fuels

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