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Problem 2: A cone, 50 mm base diameter and 70 mm axis is

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1 Problem 2: A cone, 50 mm base diameter and 70 mm axis is
standing on it’s base on Hp. It cut by a section plane 450 inclined to Hp through base end of end generator.Draw projections, sectional views, true shape of section and development of surfaces of remaining solid. Solution Steps:for sectional views: Draw three views of standing cone. Locate sec.plane in Fv as described. Project points where generators are getting Cut on Tv & Sv as shown in illustration.Join those points in sequence and show Section lines in it. Make remaining part of solid dark. TRUE SHAPE OF SECTION X1 Y1 A SECTIONAL S.V o’ B SECTION PLANE DEVELOPMENT C D E a’ b’ d’ e’ c’ g’ f’ h’ X g” h”f” a”e” b”d” c” Y F h a b c d e g f For True Shape: Draw x1y1 // to sec. plane Draw projectors on it from cut points. Mark distances of points of Sectioned part from Tv, on above projectors from x1y1 and join in sequence. Draw section lines in it. It is required true shape. G For Development: Draw development of entire solid. Name from cut-open edge i.e. A. in sequence as shown.Mark the cut points on respective edges. Join them in sequence in curvature. Make existing parts dev.dark. H A SECTIONAL T.V

2 Problem 3: A cone 40mm diameter and 50 mm axis is resting on one generator on Hp( lying on Hp) which is // to Vp.. Draw it’s projections.It is cut by a horizontal section plane through it’s base center. Draw sectional TV, development of the surface of the remaining part of cone. Follow similar solution steps for Sec.views - True shape – Development as per previous problem! DEVELOPMENT o’ A B C D E F G H HORIZONTAL SECTION PLANE a’ h’b’ e’ c’g’ d’f’ X e’ a’ b’ d’ c’ g’ f’ h’ o’ Y O h a b c d e g f O a1 h1 g1 f1 e1 d1 c1 b1 o1 SECTIONAL T.V (SHOWING TRUE SHAPE OF SECTION)

3 Problem 5:A solid composed of a half-cone and half- hexagonal pyramid is
shown in figure.It is cut by a section plane 450 inclined to Hp, passing through mid-point of axis.Draw F.v., sectional T.v.,true shape of section and development of remaining part of the solid. ( take radius of cone and each side of hexagon 30mm long and axis 70mm.) 7 1 6 5 4 3 2 TRUE SHAPE X1 Y1 Note: Fv & TV 8f two solids sandwiched Section lines style in both: Development of half cone & half pyramid: O’ A B C D E F G O DEVELOPMENT 1’ 2’ 3’ 4’ 5’ 6’ 7’ F.V. 4 5 3 6 2 7 1 X Y d’e’ c’f’ g’b’ a’ a b c d e f g 7 1 5 4 3 2 6 SECTIONAL TOP VIEW.

4 =  +  TO DRAW PRINCIPAL VIEWS FROM GIVEN DEVELOPMENT. X Y
Problem 6: Draw a semicircle 0f 100 mm diameter and inscribe in it a largest circle.If the semicircle is development of a cone and inscribed circle is some curve on it, then draw the projections of cone showing that curve. A B C D E F G H O = R L + 3600 R=Base circle radius. L=Slant height. o’ 1 3 2 4 7 6 5 L 1’ 2’ 3’ 4’ 5’ 6’ 7’ X Y a’ b’ c’ g’ d’f’ e’ h’ L h a b c d g f o e 1 2 3 4 5 6 7 Solution Steps: Draw semicircle of given diameter, divide it in 8 Parts and inscribe in it a largest circle as shown.Name intersecting points 1, 2, 3 etc. Semicircle being dev.of a cone it’s radius is slant height of cone.( L ) Then using above formula find R of base of cone. Using this data draw Fv & Tv of cone and form 8 generators and name. Take o -1 distance from dev.,mark on TL i.e.o’a’ on Fv & bring on o’b’ and name 1’ Similarly locate all points on Fv. Then project all on Tv on respective generators and join by smooth curve.

5 =  +  TO DRAW PRINCIPAL VIEWS FROM GIVEN DEVELOPMENT. X Y
Problem 6: Draw a semicircle 0f 100 mm diameter and inscribe in it a largest circle.If the semicircle is development of a cone and inscribed circle is some curve on it, then draw the projections of cone showing that curve. A B C D E F G H O = R L + 3600 R=Base circle radius. L=Slant height. o’ 1 3 2 4 7 6 5 L 1’ 2’ 3’ 4’ 5’ 6’ 7’ X Y a’ b’ c’ g’ d’f’ e’ h’ L h a b c d g f o e 1 2 3 4 5 6 7 Solution Steps: Draw semicircle of given diameter, divide it in 8 Parts and inscribe in it a largest circle as shown.Name intersecting points 1, 2, 3 etc. Semicircle being dev.of a cone it’s radius is slant height of cone.( L ) Then using above formula find R of base of cone. Using this data draw Fv & Tv of cone and form 8 generators and name. Take o -1 distance from dev.,mark on TL i.e.o’a’ on Fv & bring on o’b’ and name 1’ Similarly locate all points on Fv. Then project all on Tv on respective generators and join by smooth curve.

6 = X Y   + TO DRAW PRINCIPAL VIEWS FROM GIVEN DEVELOPMENT.
Problem 7:Draw a semicircle 0f 100 mm diameter and inscribe in it a largest rhombus.If the semicircle is development of a cone and rhombus is some curve on it, then draw the projections of cone showing that curve. Solution Steps: Similar to previous Problem: o’ A B C D E F G H O 1’ 2’ 3’ 4’ 5’ 6’ 7’ a’ b’ d’ c’ g’ f’ h’ e’ X Y h a b c d g f e L 1 2 3 4 5 6 7 = R L + 3600 R=Base circle radius. L=Slant height.

7 TO DRAW A CURVE ON PRINCIPAL VIEWS FROM DEVELOPMENT.
Problem 8: A half cone of 50 mm base diameter, 70 mm axis, is standing on it’s half base on HP with it’s flat face parallel and nearer to VP.An inextensible string is wound round it’s surface from one point of base circle and brought back to the same point.If the string is of shortest length, find it and show it on the projections of the cone. TO DRAW A CURVE ON PRINCIPAL VIEWS FROM DEVELOPMENT. Concept: A string wound from a point up to the same Point, of shortest length Must appear st. line on it’s Development. Solution steps: Hence draw development, Name it as usual and join A to A This is shortest Length of that string. Further steps are as usual. On dev. Name the points of Intersections of this line with Different generators.Bring Those on Fv & Tv and join by smooth curves. Draw 4’ a’ part of string dotted As it is on back side of cone. a’ b’ c’ d’ o’ e’ A B C D E O 2 3 4 1 1’ 2’ 3’ 4’ X Y a b c d o e 1 2 3 4


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