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Science 10: Physics 1. Motion 2. Work & Energy 3. Efficiency.

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Presentation on theme: "Science 10: Physics 1. Motion 2. Work & Energy 3. Efficiency."— Presentation transcript:

1 Science 10: Physics 1. Motion 2. Work & Energy 3. Efficiency

2 Motion Motion is a change in position of an object with respect to time Uniform Motion: describes an object that is travelling at a constant rate of motion in a straight line. It is nearly impossible to achieve uniform motion in our everyday lives Even driving with cruise control on a straight highway there are factors which slow and speed the car up... Wind resistance, friction of the tires on the road, which make the engine work harder varying the rate of motion slightly.

3 Motion Kinematics is the mathematical description and study of motion.
Galileo was among the first to study motion experimentally, systematically, and mathematically. Einstein called Galileo the “Father of modern science” for his work.

4 Motion involves measuring aspects such as:
speed or velocity distance or displacement time acceleration direction

5 Vector and Scalar Quantities
Scalars only have magnitude (a number) Vectors have both magnitude and direction Direction may be defined as north/south or up/down or +/-

6 Physics needs vectors. But What is a vector? Physics 20/Kennedy/2016

7 Physics Phun Physics 20/Kennedy/2016

8 Physics Phun Physics 20/Kennedy/2016

9 Physics 20/Kennedy/2016

10 Physics Phun Physics 20/Kennedy/2016

11 The word is used everywhere!
Physics Phun The word is used everywhere! Physics 20/Kennedy/2016

12 Vectors have magnitude and direction
But what does the word “vector” mean in physics? Vectors have magnitude and direction Physics 20/Kennedy/2016

13 Scalars have magnitude only.
Vectors have magnitude and direction. Scalars have magnitude only. e.g., velocity, displacement, acceleration e.g., speed, time, distance Physics 20/Kennedy/2016

14 Arrows can be used to represent vectors.
Arrow length is magnitude. Arrow point is direction. North 10 m, east 5.0 m, east 6.0 m, west d A vector symbol may have an arrow over top as a reminder that it is a vector.

15 Vector Notation d d Some teacher may want the vector arrow over the symbol at all times. I don’t I see it as a reminder that the symbol represents a vector. Cluttering the equations with arrows and absolute value signs make it more difficult for the students. Physics 20/Kennedy/2016

16 Sign Conventions East – positive West – negative North – positive
South – negative Right – positive Left - negative Physics 20/Kennedy/2016

17 Direction ? How else can you report the direction of a vector ?
Cardinal direction and bearings N (0°) E (90°) W (270°) S (180°) Physics 20/Kennedy/2016

18 Practice Vector A Vector B 6m 2m 10m 8m Vector D Vector C
30° 2m 10m 40° 8m Vector D Vector C Remember !! Always give a direction for vectors  Physics 20/Kennedy/2016

19 Motion Origin a point of reference.
Position is the distance and direction away from a reference point. Displacement is a vector that describes an object’s change in position. Δd

20 Practice The car travelled 300 km. distance
vector scalar displacement The car travelled 300 km, west.

21 The car was travelling 100 km/h.
speed The car was travelling 100 km/h. vector scalar velocity The car was travelling 100 km/h to the west. Physics 20/Kennedy/2016

22 Distance and speed are scalars.
Displacement and velocity are vectors. Physics 20/Kennedy/2016

23 Physics 20/Kennedy/2016

24 Physics 20/Kennedy/2016

25 What about the units ?  500m = ? km 40hr = ? mins = ? s
***When doing calculations make sure you look at your units*** 500m = ? km 40hr = ? mins = ? s 8.75km = ? m = ? cm 7923s = ? Hr What about m/s  km/h Physics 20/Kennedy/2016

26 Page 101 5. A German Shepherd ran 10 m north and then 25 m south. Determine the a. distance travelled by the dog. b. dog’s displacement relative to its starting point. north 10 m, north 25 m, south d = d d2 = 10 m m = 15 m, south a. The dog travelled a distance of 35 m. b. The dog’s displacement relative to its starting point is 15 m, south. Physics 20/Kennedy/2016

27 Page 101 6. A construction crane lifts a concrete block 9.0 m directly up and then lowers it 6.0 m directly downwards and stops. Determine the a. total distance the block travelled. b. block’s displacement relative to the ground. a. The block travelled 15.0 m. b. The block’s displacement relative to the ground is 3.0 m above the ground. p. 100 #1 - 7 Do Physics 20/Kennedy/2016

28 Lesson 2 – Speed and Velocity
Speed is a scalar quantity that describes how fast an object is moving. Velocity is a vector that describes an object’s change in position during time Where: v is speed or velocity, v d is distance(speed) or displacement(velocity) d t is time

29 Example A person walks 10.0m away from a bus stop in 5.00s. What is the average speed of the person? Physics 20/Kennedy/2016

30 Example A dog runs 20 m [N] chasing a ball and then turns around and runs 15 m [S] towards its owner. It takes the dog 12.5s. What is the average speed and velocity of the dog? Physics 20/Kennedy/2016

31 Page 102 9. The cheetah is the fastest land animal. Determine a cheetah’s speed if it can travel 150 m in 5.0 s. The cheetah’s speed is 30 m/s. Physics 20/Kennedy/2016

32 i. List the given and required information (draw a diagram)
Problem Solving i. List the given and required information (draw a diagram) ii. Write down the formula(e) iii. Isolate the desired variable (algebra) iv. Substitute the variables with numbers including the units v. Solve for the answer vi. Write the answer in a sentence (including significant digits and appropriate units) p. 102 #8 - 10 Do Physics 20/Kennedy/2016

33 Page 103 11. A car travels at 22 m/s for a time of 128 s. Determine the distance travelled. The car travels 2.8 km. Show answer in scientific notation or change the units to km for proper significant digits. The car travels 2.8 x 103 m. p. 103 # Do Physics 20/Kennedy/2016

34 Motion Quiz 1 Show all work. Include units and answer in a sentence with the appropriate amount of significant digits. 1. Determine the speed of an airplane if it travels 200 m in a time of 3.1 s. 2. A car travels 22 m/s for a time of 128 s. Determine the distance the car travelled. 3. A bird flies 100m [N] then heads 28m [S] for a time of 4 mins. Determine the birds velocity in m/s and km/h Physics 20/Kennedy/2016

35 Speeding up or slowing down.
2. Non-Uniform Motion Page 107  Notes: Acceleration is a vector that describes an objects change in velocity over time. Speeding up or slowing down. accelerated motion can be determined using: or a = ∆v ∆t N.B., Final and initial do not have to be actually start and stops. Where: a is acceleration (m/s2) vf is final speed or velocity (m/s) vi is initial speed or velocity (m/s) t is time (s) Physics 20/Kennedy/2016

36 m/s m/s2 Velocity Acceleration 2. Non-Uniform Motion Page 107
Physics 20/Kennedy/2016

37 Positive and Negative acceleration
Vector Directions Positive and Negative acceleration Page 107 v a Speeding up v a v Slowing down a v a p. 108 #1 - 7 Do Physics 20/Kennedy/2016

38 Positive and Negative A
Positive Acceleration Occurs in Two Ways When an object’s velocity is increasing in a positive direction. When an object’s velocity is decreasing in a negative direction Negative Acceleration Occurs in Two Ways When an object’s velocity is decreasing in a positive direction When an object’s velocity in increasing in a negative direction Physics 20/Kennedy/2016

39 i. List the given and required information (draw a diagram)
Problem Solving i. List the given and required information (draw a diagram) ii. Write down the formula(e) iii. Isolate the desired variable (algebra) iv. Substitute the variables with numbers including the units v. Solve for the answer vi. Write the answer in a sentence (including significant digits and appropriate units) Physics 20/Kennedy/2016

40 Example A racing car accelerates from rest to a speed of 200km/h (55.6m/s) [E] in 6.00s. What is the acceleration of the car. Physics 20/Kennedy/2016

41 Solution a = vf - vi ∆t a = 55.6m/s – 0.00m/s 6.00s = 9.27m/s2 The car’s velocity is increasing at the rate of 9.27m/s2 [E] (This is positive acceleration) Physics 20/Kennedy/2016

42 Example A rocket accelerates from rest at a rate of 500 m/s2 [up] to a speed of m/s [up]. How long does it take to reach top speed ? Physics 20/Kennedy/2016

43 Solution The time it takes for the rocket ro reach top speed is 300 s
t = vf - vi a t = m/s[up] – 0.00m/s 500m/s2 [up] = 300s The time it takes for the rocket ro reach top speed is 300 s Physics 20/Kennedy/2016

44 Page 111 13. Use the acceleration equation and isolate each variable. You will have a total of four different versions. t vf vi Physics 20/Kennedy/2016

45 m/s m/s2 Constant Velocity Acceleration Page 107 p. 109 #8 - 14 Do
Physics 20/Kennedy/2016

46 Page 108 3. A sprinter reaches a speed of 10.9 m/s in a time of 5.2 s. Calculate the magnitude of his acceleration if he started from rest. vi = 0 The sprinter’s acceleration is 2.1 m/s2. Physics 20/Kennedy/2016

47 Page 110 9. A car accelerates to the north at 4.5 m/s2 for a time of 2.54 s. Calculate its final velocity if its initial velocity is 12.3 m/s to the north. The car’s final velocity is 24 m/s to the north. Physics 20/Kennedy/2016

48 Motion Quiz 2 Show all work. Include units and answer in a sentence with the appropriate amount of significant digits. 1. Calculate the magnitude of the acceleration for an object that takes 2.51 s to increase its speed from 3.5 x 102 m/s to 6.6 x 103 m/s. 2. A car accelerates to the north at 4.5 m/s2 for a time of 2.54 s. Calculate its final velocity if its initial velocity is 12.3 m/s north. Physics 20/Kennedy/2016

49 Motion Quiz 2 Show all work. Include units and answer in a sentence with the appropriate amount of significant digits. 1. Calculate the magnitude of the acceleration for an object that takes 1.52 s to increase its speed from 3.5 x 103 m/s to 6.6 x 104 m/s. 2. A car accelerates to the south at 6.5 m/s2 for a time of 1.54 s. Calculate its final velocity if its initial velocity is 10.3 m/s south . Physics 20/Kennedy/2016

50 Graphing Linear Motion
Physics 20/Kennedy/2016

51 Graphing Motion Graphs can be used to communicate motion.
Aspects of motion include: time displacement velocity acceleration Physics 20/Kennedy/2016

52 Motion Motion may communicated using words, equations or graphs.
Page 2 Motion may communicated using words, equations or graphs. Motion Words Equations Graphs We must be able to translate between the three different modes of communications. Physics 20/Kennedy/2016

53 sketch graphs from written descriptions
vs. Plotting a Graph Sketching a graph We must be able to: sketch graphs from written descriptions write descriptions from graphs Physics 20/Kennedy/2016

54 Uniform Motion Graphs Physics 20/Kennedy/2016

55 Questions  What is a distance(position)-time graph?
What is a speed(velocity)-time graph? How do features on one graph translate into features on the other? Physics 20/Kennedy/2016

56 D-T Graphs Show an object’s position as a function of time.
x-axis: time y-axis: position Physics 20/Kennedy/2016

57 We only use quadrant I and II for our motion graphs in Science 10.
Quadrants of the Cartesian Coordinate System + II I Time is almost always on the x-axis + We only use quadrant I and II for our motion graphs in Science 10. III IV Physics 20/Kennedy/2016

58 D-T Graphs Imagine a ball rolling along a table, illuminated by a strobe light every second. You can plot the ball’s position as a function of time. 0 s 1 s 2 s 3 s 4 s 5 s 6 s 7 s 8 s 9 s 10 s Physics 20/Kennedy/2016

59 1 2 3 4 5 6 7 8 9 10 time (s) position (cm) Physics 20/Kennedy/2016

60 What are the characteristics of this graph?
Straight line, upward slope What kind of motion created this graph? Constant speed 1 2 3 4 5 6 7 8 9 10 time (s) position (cm) Physics 20/Kennedy/2016

61 Each type of motion has a characteristic shape on a D-T graph.
Constant speed Zero speed (at rest) Accelerating (speeding up) Decelerating (slowing down) Physics 20/Kennedy/2016

62 Constant speed is represented by a straight diagonal segment on the D-T graph.
time (s) pos. (m) Constant speed in positive direction. time (s) pos. (m) Constant speed in negative direction. Physics 20/Kennedy/2016

63 zero speed is represented by a straight, flat segment on the P-T graph.
time (s) pos. (m) A horizontal segment means the object is at rest. Physics 20/Kennedy/2016

64 Displacement – time graphs
Time is always on the x-axis Slope = velocity Stationary Constant velocity time displacement time displacement Physics 20/Kennedy/2016

65 Example Identify the graph that shows an object furthest from the reference point. a. b. time displacement time displacement Furthest from reference Physics 20/Kennedy/2016

66 Identify the graph that represents the faster object.
Example Identify the graph that represents the faster object. a. b. time displacement time displacement Faster Physics 20/Kennedy/2016

67 Negative slope = negative direction
Example Identify the graph that shows an object travelling to the left (assuming right is positive). a. b. time displacement time displacement Travelling to the left Travelling to the right Negative slope = negative direction Positive slope = positive direction Physics 20/Kennedy/2016

68 Example C D B A E 4 moving to right, slower 3 moving to left, faster
Time (s) Displacement (m) 2 4 1 3 moving to right, slower moving to left, faster A B C D E stationary stationary moving to right The teacher can walk the motion described by the graph while explaining the graph. Physics 20/Kennedy/2016

69 The slope of a D-T graph is equal to the object’s velocity in that segment.
change in y change in x (30 m – 10 m) (30 s – 0 s) (20 m) (30 s) slope = 0.67 m/s time (s) position (m) 10 20 30 40 50 Physics 20/Kennedy/2016

70 V-T Graphs A velocity-time (V-T) graph shows an object’s velocity as a function of time. A horizontal line = constant velocity. A straight sloped line = constant acceleration. Acceleration = change in velocity over time. Positive slope = positive acceleration. Not necessarily speeding up! Negative slope = negative acceleration. Not necessarily slowing down! Physics 20/Kennedy/2016

71 A horizontal line on the V-T graph means constant velocity.
time (s) velocity (m/s) N S Object is moving at a constant velocity North. Physics 20/Kennedy/2016

72 A horizontal line on the V-T graph means constant velocity.
time (s) velocity (m/s) N S Object is moving at a constant velocity South. Physics 20/Kennedy/2016

73 If an object isn’t moving, its velocity is zero.
time (s) velocity (m/s) N S Object is at rest Physics 20/Kennedy/2016

74 If the V-T line has a positive slope, the object is undergoing acceleration in positive direction.
If v is positive also, object is speeding up. If v is negative, object is slowing down. Physics 20/Kennedy/2016

75 V-T graph has positive slope
time (s) velocity (m/s) N S Positive velocity and positive acceleration: object is speeding up! time (s) velocity (m/s) N S Negative velocity and positive acceleration: object is slowing down. Physics 20/Kennedy/2016

76 If the V-T line has a negative slope, the object is undergoing acceleration in the negative direction. If v is positive, the object is slowing down. If v is negative also, the object is speeding up. Physics 20/Kennedy/2016

77 V-T graph has negative slope.
time (s) velocity (m/s) N S Positive velocity and negative acceleration: object is slowing down, time (s) velocity (m/s) N S Negative velocity and negative acceleration: object is speeding up! (in negative direction) Physics 20/Kennedy/2016

78 Slope = acceleration Area = displacement Page 99
Velocity - time graphs for Uniform Motion Slope = acceleration Area = displacement time velocity a. b. time velocity Constant velocity Acceleration Physics 20/Kennedy/2016

79 How a d-t graph relates to a v-t graph.
Compare: How a d-t graph relates to a v-t graph. a. time velocity b. time displacement 10 m/s If slope = 10 m/s Slope = speed Slope = acceleration Both graphs describe the same motion – constant velocity. Physics 20/Kennedy/2016

80 Compare: Note that the two graphs below look identical but mean totally different things. time displacement velocity a. b. Uniform motion (constant velocity) Non-uniform motion (acceleration) Physics 20/Kennedy/2016

81 Page 104 19. Use the graph to determine velocity. y2 – y1 Slope =
x2 – x1 Slope = 10.0 m – 4.0 m 9.0 s – 0.0 s 10.0, 9.0 10.0 Slope = 0.67 m/s Position (m) 5.0 The velocity is 0.67 m/s to the west 4.0, 0.0 p. 104 # Do Time (s) Physics 20/Kennedy/2016

82 Vector Meaning of +/- d where you are at v where you are going
a ambiguous Physics 20/Kennedy/2016

83 Non-Uniform (acceleration) Motion Graphs

84 Displacement – Time Graphs for Non Uniform Motion (acceleration)
Physics 20/Kennedy/2016

85 Curved segments on the D-T graph mean the object’s speed is changing.
time (s) pos. (m) Speeding up in positive direction. time (s) pos. (m) Speeding up in negative direction. Physics 20/Kennedy/2016

86 Curved segments on the P-T graph mean the object’s speed is changing.
time (s) pos. (m) Traveling in positive direction, but slowing down. time (s) pos. (m) Traveling in negative direction, but slowing down. Physics 20/Kennedy/2016

87 Displacement – Time Graphs (Non-uniform Motion)
Compare: Constant speed (Uniform Motion) time displacement Accelerating (Non-uniform Motion) time displacement This graph gradually gets steeper The steeper the line the faster the speed. p. 111 # Do Physics 20/Kennedy/2016

88 The following P-T graph corresponds to an object moving back and forth along a straight path. Can you describe its movement based on the graph? Physics 20/Kennedy/2016

89 time (s) position (m) N S

90 Velocity – Time Graphs for Non Uniform Motion (acceleration)
Physics 20/Kennedy/2016

91 Page 111 Velocity – Time Graphs (Non-uniform Motion) Constant velocity time velocity Accelerating (non-uniform motion) time velocity The steeper the line the greater the acceleration. The acceleration of an object can be determined using the slope of a velocity-time graph. Physics 20/Kennedy/2016

92 Graph a is steeper (larger slope) therefore greater acceleration.
Example time velocity Identify the graph representing motion having the greater acceleration. a. b. Graph a is steeper (larger slope) therefore greater acceleration. Physics 20/Kennedy/2016

93 The area between the graph and x-axis = displacement
Velocity – Time Graphs time velocity The area between the graph and x-axis = displacement Slope = acceleration Area = displacement p. 112 # Do Physics 20/Kennedy/2016

94 Slope/Area Relationship
d v a area Physics 20/Kennedy/2016

95 Strategy – examine one column at a time
Example A speed-time graph for a car is shown below. The slope of the graph is the _____i____ and the area is the ___ii_____ v(m/s) t (s) i ii a. acceleration velocity b. distance c. d. Strategy – examine one column at a time Science 10/Kennedy/2016

96 Transposing Graphs Transposing graphs is changing one type of graph to another type of graph both representing the same motion. Physics 20/Kennedy/2016

97 Line trends Acceleration Constant velocity Stationary d v curve
diagonal horizontal zero d v Acceleration Constant velocity Stationary Physics 20/Kennedy/2016

98 Line Trends d v a d v a d v a d v slope area zero horizontal curve
diagonal d v a d v a d v Physics 20/Kennedy/2016

99 Motion Motion may communicated using words, equations or graphs.
We must be able to translate between the three different modes of communications. Physics 20/Kennedy/2016

100 Transposing graphs – remember the trends
Graphing Summary d v a slope area Transposing graphs – remember the trends zero horizontal curve diagonal d v a d v a d v Physics 20/Kennedy/2016

101 Examine and compare one section at a time
zero horizontal curve diagonal d v a d v a d v Example d t Examine and compare one section at a time Identify the v- t graph that best corresponds with the d-t graph a. b. c. d. e. Physics 20/Kennedy/2016

102 Examine and compare one section at a time
zero horizontal curve diagonal d v a d v a Example v t Examine and compare one section at a time Identify the d- t graph that best corresponds with the v-t graph a. b. c. d. e. Physics 20/Kennedy/2016

103 Graph Summary d v a d v a d v a d v slope area zero horizontal curve
diagonal d v a d v a d v p. 113 #23, 24 Do Physics 20/Kennedy/2016


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