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9P9: Solve 2X2 systems by substitution

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Presentation on theme: "9P9: Solve 2X2 systems by substitution"— Presentation transcript:

1 9P9: Solve 2X2 systems by substitution

2 Find the solution by substitution
Steps 1 Solve 1 of equations for x or y 2 Substitute into other equation 3 Solve for other variable 4 Use answer to find original variable 5 Write answer as ordered pair 6 Check

3 Ex1:Solve by Substitution
x + y = 6 and x = y + 2 1) Done (eqn 2 solved for x) 2) Substitute 3) Solve 4) Find x: x = y so x = or x =4 5) Write solution (4,2) 6) Check =6 yes and 4 = 2 +2 yes (y+2)+y =6 2y +2 =6 2y=4 y=2

4 Example 2: 4x-y =5 and 2x +y =10 1) Which letter is easiest to solve for? y 4x - y =5 and 2x +y =10 y = x 2) Substitute 4x-(10-2x)=5 3) Solve x-10 +2x = 5 6x -10 = 5 6x=15 4) Find y: so y = y=5 5) ( 5/2,5) is the solution

5 Problem Solving Translate to a system then solve
The sum of two numbers is 82. One number is 12 more than the other N1: x N2: y x + y = and y = x S1) #2 already solved for y S2) x +(x+12) =82 S3) 2x +12 = 82 2x =70 x =35 S4) =y 47 =y S5) The numbers are 35 and 47

6 Assignment 8-2/ /11-29 o, 36-46e,47


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