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Chapter 2.6 (Part 1): Prove Statements about Segments and Angles

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Presentation on theme: "Chapter 2.6 (Part 1): Prove Statements about Segments and Angles"— Presentation transcript:

1 Chapter 2.6 (Part 1): Prove Statements about Segments and Angles
Goal: You will write proofs using geometric theorems.

2 Example 2. AC = AB + BC 3. AC = AB + AB
Three steps of a proof are shown. Give the reasons for the last two steps. 2. AC = AB + BC 3. AC = AB + AB

3 Example 2. 2. Definition of Angle Bisector 3.
3. Definition of congruent angles 4. m<1 + m<2 = m<ABC 4.

4 Example (cont) 5. 5. Substitution Property of Equality 6. 6. Simplify

5 Example 2. Angle Addition Postulate 3. Angle Addition Postulate 2. 3.
4. m<1 + m<2 = m<3 + m<4 4.

6 Example 6. 6. Substitution Property of Equality 7. m<1 = m<4 7.

7 Example Given: <1 and <2 are a linear pair
Prove: m<2 = 180° - m<1 Statement Reason 1. <1 and <2 are a linear pair 2. <1 and <2 are supplementary 3. m<1 + m<2 = 180° 4. m<1 = 180° - m<2 1. Given 2. The angles in a linear pair are supplementary 3. Def of Supplementary Angles 4.Subtraction Prop of Equality

8 Theorem 2.1:Congruence of Segments
Segment congruence is reflexive, symmetric, and transitive.

9 Theorem 2.2:Congruence of Angles
Angle congruence is reflexive, symmetric, and transitive.

10 Example 1. Given 1. AB = 5 2. Given 2. BC = 5 3. Substitution
Given: AB = 5, BC = 5, BC CA Prove: AB DE Statement Reason C B 1. Given 2. Given 3. Substitution 4. Definition of Congruent Segments 5. Given 6. Substitution ( or Transitive) 1. AB = 5 2. BC = 5 3. AB = BC 4. AB BC 5. BC CA 6. AB CA

11 Example 1. <3 and <2 are supplementary. 1. Given
Given: <3 and <2 are supplementary. m <1 + m <2 = 180° Prove: <1 <3 Statement Reason 1 2 3 1. <3 and <2 are supplementary. 2. m <1 + m <2 = 180° 3. m <3 + m <2 = 180° 4. m <1 + m <2 = m <3 + m <2 5. m <1 = m <3 6. <1 <3 1. Given 2. Given 3. Def. of Supplementary Angles 4. Substitution 5. Subtraction Property 6. Def. of Congruent Angles


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