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Lesson 20.1 Justifying Circumference and area of a circle

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1 Lesson 20.1 Justifying Circumference and area of a circle
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2 Circumference & Area of a Circle
π‘…π‘Žπ‘‘π‘–π‘’π‘ =π‘Ÿ π·π‘–π‘Žπ‘šπ‘’π‘‘π‘’π‘Ÿ=2π‘Ÿ πΆπ‘–π‘Ÿπ‘π‘’π‘šπ‘“π‘’π‘Ÿπ‘’π‘›π‘π‘’=2πœ‹π‘Ÿ or πœ‹π‘‘ π΄π‘Ÿπ‘’π‘Ž=πœ‹ π‘Ÿ 2

3 Example 1 – Find the circumference and area of each circle with the given radius or diameter. Round to the nearest tenth. Use 3.14 for πœ‹. π‘Ž) π‘Ÿ=14 π‘π‘š 𝑏) 𝑑=24 𝑓𝑑 𝐢=2πœ‹π‘Ÿ 𝐢=πœ‹π‘‘ 𝐢=2(3.14)(14) 𝐢=(3.14)(24) 𝐢=28(3.14) 𝐢=75.36 𝑓𝑒𝑒𝑑 𝐢=28(3.14) 𝐴=πœ‹ (12) 2 𝐢=87.92 π‘π‘š 𝐴=(3.14)(144) 𝐴=πœ‹ π‘Ÿ 2 𝐴= 𝑓𝑑 2 𝐴=(3.14) (14) 2 𝐴= 𝐴= π‘π‘š 2

4 Assignment # Pg. 1082 #2-23 all


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