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BIOL 2416 Chapter 15: Gene Mapping in Bacteria and Viruses

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Presentation on theme: "BIOL 2416 Chapter 15: Gene Mapping in Bacteria and Viruses"— Presentation transcript:

1 BIOL 2416 Chapter 15: Gene Mapping in Bacteria and Viruses

2 Gene mapping in bacteria by
Conjugation Bacterial “sex” between donor (Hfr) and recipient (F-) cells Interrupted mating experiment determine gene order Transformation Donor DNA is isolated and added to recipient cells Donor DNA integrates by homologous recombination (Xover) Look for frequent co-transformation of close genes Transduction DNA transferred from donor cell to recipient cell by transducing phages Can be generalized or specific transduction In generalized transduction, ANY random piece of DNA can be transduced Look for high co-transduction frequency of selectable markers to figure out which genes are close together.

3 Fig. 14.5a Transfer of genetic material during conjugation in E. coli
Peter J. Russell, iGenetics: Copyright © Pearson Education, Inc., publishing as Benjamin Cummings.

4 Fig. 14.5b Transfer of genetic material during conjugation in E. coli
Peter J. Russell, iGenetics: Copyright © Pearson Education, Inc., publishing as Benjamin Cummings.

5 Fig. 14.7 Interrupted-mating experiment
Peter J. Russell, iGenetics: Copyright © Pearson Education, Inc., publishing as Benjamin Cummings.

6 Fig Interrupted-mating experiments with a variety of Hfr strains, showing that the E. coli linkage map is circular 100 minutes Peter J. Russell, iGenetics: Copyright © Pearson Education, Inc., publishing as Benjamin Cummings.

7 Fig. 14.10 Transformation in Bacillus subtilis
Peter J. Russell, iGenetics: Copyright © Pearson Education, Inc., publishing as Benjamin Cummings.

8 Fig. 14.11 Demonstration of determining gene order by cotransformation
Done when conjugation or transduction is impossible. Frequent cotransformation Indicates close gene proximity. Peter J. Russell, iGenetics: Copyright © Pearson Education, Inc., publishing as Benjamin Cummings.

9 Temperate Phages such as Lambda may go through the lytic
or lysogenic cycle after infecting a bacterial host cell: (involves packaging of viral DNA)

10 Fig. 14.13 Generalized transduction between strains of E. coli
Phage P1 can do generalized transduction, where ANY piece of bacterial DNA can be transferred to the next host bacterium due to sloppy packaging. (Lambda phage can only do specialized transduction, where only certain sections of host DNA can get transferred.) (sloppy packaging possible here)

11 Typical transduction mapping data (looking for frequent cotransduction):
Selected marker: leu+ (does not require leu to grow) thr+ Corresponding unselected markers: 50% = aziR (sodium azide resistant) 2% = thr+(does not require thr) 3% = leu+ 0% = aziR thr leu azi Gene map:

12 Mapping genes of bacteriophages
By 2-, 3- or 4-gene crosses, involving bacteria infected with phages of different phenotypes Plaque = cleared area on a bacterial lawn where the phage has lysed the bacterial host cells (so indicates infected host cells, presence of phage) Distinguishable phage phenotypes may include different plaque morphology and/or host range Very similar strategy to 2-pont test crosses seen before

13 Bacteriophage gene mapping, cont’d:
Co-infect E.coli with two strains of T2 phage: T2-1 with genotype h+ r can lyse E.coli strain B, but not strain B/2 (h+), and forms large distinct plaques (r) T2-2 with genotype h r+ can lyse both B and B/2 (h), and forms small, fuzzy plaques (r+) When phage DNA is packaged, can get parental combination: h+ r and h r+ Or re-combination due to crossover between phage DNAs: h+ r+ and h r Frequency of recombinants = frequency of crossover = relative genetic distance between viral genes

14

15 Complementation tests
To determine how many genes are involved in a set of mutations that produce a given phenotype Used in many types of organisms E.g. two true-breeding mutant strains with black bodies are mated > all F1 offspring turns out to have wt grey bodies. First black parent had a mutation in the gene A (aa BB genotype) Second black parent had a mutation in gene B (AA bb genotype) The two mutations complemented (overcame) one another (F1’s were all AaBb wt grey)


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