1. DYNAMICS 1. Newton’s Three Laws Newton’s First Law Newton’s Second Law
Existence of inertial systems of reference
In inertial system of reference, any object acted by no net force remains at rest or continues its motion along straight line with constant velocity
Newton’s Second Law
Newton’s Third Law
Note: these two forces act on different objects. Never add these forces!
Units:
(1 lb = N)

2. B A C 1.1 Newton’s First Law (examples)
In inertial system of reference, any object acted by no net force remains at rest or continues its motion along straight line with constant velocity
Example 1 (Snapped string):
A small ball attached to the end of a string moves in circles as shown below. If the string snaps, what will be the trajectory of the ball? C A B

3. Example 2: A book is lying at rest on a table
Example 2: A book is lying at rest on a table. The book will remain there at rest because:
A) there is a net force but the book has too much inertia
B) there are no forces acting on it at all
C) it does move, but too slowly to be seen
D) there is no net force on the book
E) there is a net force, but the book is too heavy to move
There are forces acting on the book, but the only forces acting are in the y-direction. Gravity acts downward, but the table exerts an upward force that is equally strong, so the two forces cancel, leaving no net force.

4. 1.2 Newton’s Second Law (examples)
Example 1: A hockey puck slides on ice at constant velocity. What is the net force acting on the puck?
A) more than its weight
B) equal to its weight
C) less than its weight but more than zero
D) depends on the speed of the puck
E) zero
The puck is moving at a constant velocity, and therefore it is not accelerating. Thus, there must be no net force acting on the puck.
Follow-up: Are there any forces acting on the puck? What are they?

5. Example 2: Car brakes provide a force F for 5 s
Example 2: Car brakes provide a force F for 5 s. During this time, the car moves 25 m, but does not stop. If the same force would be applied for 10 s, how far would the car have traveled during this time?
1) 100 m
2) 50 m < x < 100 m
3) 50 m
4) 25 m < x < 50 m
5) 25 m
Acceleration:
In the first 5 s, the car has still moved 25 m. However, since the car is slowing down,
in the next 5 s, it must cover less distance. Therefore, the total distance must be
more than 25 m but less than 50 m.

6. Example 3: A force F acting on a mass m1 results in an acceleration a1
Example 3: A force F acting on a mass m1 results in an acceleration a1. The same force acting on a mass m2 results in an acceleration a2 = 2a1. F a1 m1 F
a2 = 2a1 m2
If both masses are put together and the same force is applied to the combination, what is the resulting acceleration?
a ? m2 F m1
2/3 a1
3/2 a1
3/4 a1

7. 1.3 Newton’s Third Law (examples)
For every force, or action force, there is an equal but opposite force, or reaction force. A B
If object A exerts a force on object B (an “action”), then
object B exerts a force on body A (a “reaction”).
These two forces have the same magnitude but opposite direction.
Note: these two forces act on different objects.

8. Example: Two carts are put back-to-back on a track
Example: Two carts are put back-to-back on a track. Cart A has a spring-loaded piston; cart B, which has twice the mass of cart A, is entirely passive. When the piston is released, it pushes against cart B, and the carts move apart. Which of the two forces exerted by the two carts on each other has a larger magnitude?
1. The force exerted by A.
2. The two forces have equal magnitude.
3. The force exerted by B.
It’s a third law pair!! B A

9. Application of Newton’s Laws (Ropes and tension)
Example 1: You tie a rope to a tree and you pull on the rope with a force of 100 N. What is the tension in the rope?
The tension in the rope is the force that the rope “feels” across any section of it (or that you would feel if you replaced a piece of the rope). Since you are pulling with a force of 100 N, that is the tension in the rope.
Example 2: Two tug-of-war opponents each pull with a force of 100 N on opposite ends of a rope. What is the tension in the rope?
This is literally the identical situation to the previous question. The tension is not 200 N !! Whether the other end of the rope is pulled by a person, or pulled by a tree, the tension in the rope is still 100 N !!
Example 3: You and a friend can each pull with a force of 200 N. If you want to rip a rope in half, what is the best way?
1) You and your friend each pull on opposite ends of the rope
2) Tie the rope to a tree, and you both pull from the same end
3) It doesn’t matter -- both of the above are equivalent
Take advantage of the fact that the tree can pull with almost any force (until it falls down, that is!). You and your friend should team up on one end, and let the tree make the effort on the other end.

10. NBT WBE NTE WTE NTB WET WEB NET 2. Free Body Diagram
Example: Book on Table – The full story
Action-Reaction Pairs:
NBT
Normal force between book and table
NBT = –NTB
WBE
Gravitational force between book and earth
WBE = –WEB
NTE
Normal force between table and earth
NTE = –NET
WTE
NTB
Gravitational force between table and earth
WTE = –WET
Analyze on board first and then put this up as a summary
WET
WEB
The book does not accelerate WBE+NBT=0
The table does not accelerate WTE+NTB+NTE=0
NET
Does the earth accelerate?

11. 3. Weight
Example: You see two cases: a student pulling or pushing a sled with a force F which is applied at an angle . In which case is the normal force greater?
1) case 1
2) case 2
3) it’s the same for both
4) depends on the magnitude of the force F
5) depends on the ice surface
Case 1
Case 2
In Case 1, the force F is pushing down
(in addition to mg), so the normal force needs to be larger.
In Case 2, the force F is pulling up, against gravity, so the normal force is lessened.

12. Question 1: What can you say about the force of gravity Fg acting on a stone and a feather?
1) Fg is greater on the feather
2) Fg is greater on the stone
3) Fg is zero on both due to vacuum
4) Fg is equal on both always
5) Fg is zero on both always
The force of gravity (weight) depends on the mass of the object!! The stone has more mass, therefore more weight.
Question 2: What can you say about the acceleration of gravity acting on the stone and the feather?
1) it is greater on the feather
2) it is greater on the stone
3) it is zero on both due to vacuum
4) it is equal on both always
5) it is zero on both always
The acceleration is given by F/m The force of gravity (weight) is F=mg, then we end up with acceleration g for both objects.

13. T m=100kg a=2.2m/s2 T=m(g+a) T=? T=100kg*(9.8 m/s2 +2.2 m/s2 )= 1200 N
Example 1: A box with a mass of 100 kg is given an upward acceleration of 2.2 m/s² by a cable. What is the tension in the cable? T
m=100kg
a=2.2m/s2
T=?
Newton’s equation: T-mg=ma
T=m(g+a)
T=100kg*(9.8 m/s m/s2 )= 1200 N m mg
Note: this tension is bigger than the box’s weight, w=mg=100 kg* 9.8 m/s2 = 980 N
Example 2: The same box as in example 1 is given an downward acceleration of 2.2 m/s² by a cable. What is the tension in the cable?
m = 100 kg
a = -2.2 m/s2
T=?
T=m(g+a)
T=100 kg*(9.8 m/s m/s2 )= 760 N
Note: this tension is smaller than the box’s weight, w=mg=100kg* 9.8m/s2 = 980N Compare examples 1 & 2: the tension depends on acceleration & is independent from velocity. The tension is equal to the weight if there is no acceleration (a=0).

14. 4. Pressure A – area 5. Work [P] = N/m2 = Pa
Units:
[P] = N/m2 = Pa
5. Work
Work done by forces that oppose the direction of motion will be negative.
Units:
[W] = N*m = J

15. 8. Conservation of energy
6. Kinetic energy
7. Potential energy
a) Gravitational potential energy:
b) Elastic potential energy (spring):
8. Conservation of energy

16. Example: A box of unknown mass and initial speed v0 = 10 m/s moves up a frictionless incline. How high does the box go before it begins sliding down? m
Only gravity does work (the normal is perpendicular to the motion), so mechanical energy is conserved.
We can apply the same thing to any “incline”! h
Turn-around point: where K = 0
E K U
v = 0

17. Example: A roller coaster starts out at the top of a hill of height h.
How fast is it going when it reaches the bottom? h
Example: An object of unknown mass is projected with an initial speed, v0 = 10 m/s at an unknown angle above the horizontal. If air resistance could be neglected, what would be the speed of the object at height, h = 3.3 m above the starting point?