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1. For a = –12, find, –a and |a|. ANSWER 12, 12 2.

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Presentation on theme: "1. For a = –12, find, –a and |a|. ANSWER 12, 12 2."— Presentation transcript:

1 1. For a = –12, find, –a and |a|. ANSWER 12, 12 2. Evaluate |x| – 2 when x = –3. ANSWER 1

2 3. The change in elevation as a diver explored a reef was –0.5 feet, 1.5 feet, –2.5 feet, and 2.25 feet. Which change in elevation had the greatest absolute value? ANSWER –2.5 ft

3 EXAMPLE 1 Solve an absolute value equation Solve x = 7. SOLUTION The distance between x and 0 is 7. So, x = 7 or x = –7. ANSWER The solutions are 7 and –7.

4 EXAMPLE 1 GUIDED PRACTICE for Example 1 Solve (a) |x| = 3 and (b) |x| = 15. ANSWER 3, –3 a. 15, –15 b.

5 Solve an absolute value equation
EXAMPLE 2 Solve an absolute value equation x – 3 = 8. Solve SOLUTION Rewrite the absolute value equation as two equations. Then solve each equation separately. x – 3 = 8 Write original equation. x – 3 = 8 or x – 3 = –8 Rewrite as two equations. x = 11 or x = –5 Add 3 to each side. ANSWER The solutions are 11 and –5. Check your solutions.

6 Solve an absolute value equation
EXAMPLE 2 Solve an absolute value equation CHECK |x – 3| = |x – 3| = 8 Write original inequality. |11 – 3| = |–5 – 3| = 8 ? Substitute for x. | 8| = |–8| = 8 ? Subtract. 8 = = 8 Simplify. The solution checks.

7 Rewrite an absolute value equation
EXAMPLE 3 Rewrite an absolute value equation 3 2x – 7 – 5 = 4. Solve SOLUTION First, rewrite the equation in the form ax + b = c. 3 2x – 7 – 5 = 4 Write original equation. 3 2x – 7 = 9 Add 5 to each side. 2x – 7 = 3 Divide each side by 3.

8 Rewrite an absolute value equation
EXAMPLE 3 Rewrite an absolute value equation Next, solve the absolute value equation. 2x – 7 = 3 Write absolute value equation. 2x – 7 = or 2x – 7 = –3 Rewrite as two equations. 2x = 10 or x = 4 Add 7 to each side. x = or x = 2 Divide each side by 2. ANSWER The solutions are 5 and 2.

9 GUIDED PRACTICE for Examples 2 and 3 Solve the equation. r – 7 = 9 2. 16, –2 ANSWER

10 GUIDED PRACTICE for Examples 2 and 3 Solve the equation. 2 s = 18.9 3. 7.4, –7.4 ANSWER

11 GUIDED PRACTICE for Examples 2 and 3 Solve the equation. 4 t + 9 – 5 = 19 4. –3, –15 ANSWER

12 Decide if an equation has no solutions
EXAMPLE 4 Decide if an equation has no solutions 3x = –2, if possible. Solve 3x = –2 Write original equation. 3x + 5 = –8 Subtract 6 from each side. ANSWER The absolute value of a number is never negative. So, there are no solutions.

13 EXAMPLE 5 Use absolute deviation BASKETBALLS Before the start of a professional basketball game, a basketball must be inflated to an air pressure of 8 pounds per square inch (psi) with an absolute error of 0.5 psi. (Absolute error is the absolute deviation of a measured value from an accepted value.) Find the minimum and maximum acceptable air pressures for the basketball.

14 EXAMPLE 5 Use absolute deviation SOLUTION Let p be the air pressure (in psi) of a basketball. Write a verbal model. Then write and solve an absolute value equation. 0.5 = p 8

15 Use absolute deviation
EXAMPLE 5 Use absolute deviation p 8 0.5 = Write original equation. p 8 0.5 = or –0.5 = Rewrite as two equations. p 8.5 = or 7.5 = Add 8 to each side. ANSWER The minimum and maximum acceptable pressures are 7.5 psi and 8.5 psi.

16 GUIDED PRACTICE for Examples 4 and 5 Solve the equation, if possible m – = 2 ANSWER no solution

17 GUIDED PRACTICE for Examples 4 and 5 Solve the equation, if possible –3 n +2 –7 = –10 ANSWER −1, −3

18 GUIDED PRACTICE for Examples 4 and 5 7. The absolute deviation of x from 7.6 is 5.2. What are the values of x that satisfy this requirement? 12.8, 2.4 ANSWER

19 Daily Homework Quiz A pattern for a 26-inch skirt allows for an absolute deviation of 1.5 inches. Find the minimum and maximum skirt lengths that can be made from the pattern. 5. ANSWER minimum : 24.5 in.; maximum 27.5 in.

20 Warm-up: Page 329 #1-8 all and #46 Homework: Page 335 #3-31 all

21 Daily Homework Quiz Solve the equation, if possible. | x – 4 | = 13 ANSWER –9, 17 2. | x + 2 | + 7 = 3 ANSWER no solutions

22 Daily Homework Quiz Solve the equation. If possible. | 2x – 6 | + 4 = 20 ANSWER –5, 11 4. –2 | x – 5 | + 7 = 12 ANSWER no solutions


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