1. AIM: How do we factor polynomials (pt 3)?
Do Now: Factor
t² ) 25a² - 144y²
3) y² - 12y – ) p² + 7p – 8
HW #5 – pgs #21-23,31,34,35
*Extra Credit Assignment +5 next test(due Fri)

2. If we have ax² + bx + c, what happens when a > 1?
Factoring Method #5
SLIDE and DIVIDE METHOD
Example:
3x² - x – 10
1)Pull out any GCF before starting
2) Slide the a to the end and multiply it by the constant.
3x² - x – 10 becomes x² - x - 30

3. 3) Factor the new trinomial normally x² - x – 30 = (x – 6) (x + 5) 4) “Put back” the number you slid out (for this example 3) by dividing this number into the constant in each factor (x – 6/3) (x + 5/3) 5) Simplify the fraction, if possible (x – 2) (x + 5/3) 6)If there’s a fraction left, the denominator becomes the coefficient of the variable term (x +2) (3x +5) Final answer

4. Example 2: 2x² - 7x + 5
1) x² - 7x + 10
2) (x – 5) (x – 2)
3) (x – 5/2) (x – 2/2)
4) (x – 5/2) (x – 1)
5) (2x – 5)(x – 1) Final answer

5. Try these: 3) 2x² - 5x – 3 4) 12a² -19a - 4

6. Factoring Method #6 Factoring Completely
1) Look for a GCF and factor the GCF out.
2) The remaining factor may still be factorable:
a) binomial – the difference of 2 squares
b) trinomial – trinomial methods
Example 5 : 9x³ - 36x
1) 9x (x² - 4)
2) 9x (x -2) (x + 2)

7. 6) 6x³ + 27x² - 15x ) 3x⁴ - 243