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Review of Diprotic Acid Titration

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Presentation on theme: "Review of Diprotic Acid Titration"— Presentation transcript:

1 Review of Diprotic Acid Titration

2 Analysis of 0.181g Carbonate / Bicarbonate Sample
# mol HCO3- = ( L) x ( M) x (1 mol HCO3- / 1 mol HCl) = mol HCO3- # mole CO32- = ( L) x ( M) x (1 mol CO32- / 1 mol HCl) = mol CO32- # mole HCO3- in original mixture = # mol HCO # mol HCO3- produced in titration to Phen. End Pt. = # mol HCO # mol CO32- = mol mol = mol HCO3-   #g NaHCO3 = ( mol) x ( g/mol) = g #g Na2CO3 = ( mol) x ( g/mol) = g   wt% NaHCO3 = (0.102g / 0.181g) x 100 = % wt % Na2CO3 = (0.072g / 0.181g) x 100 = %

3 Complexometric Titration

4 Typical Complexing Agents

5 EDTA

6

7

8 Ca-EDTA Titration

9 0.00 mL Titrant Added Titration Reaction EDTA Ca2+ CaEDTA2+ end = 0 M = M = 0 M Equilibrium Reaction Initial [Ca2+] = M Concentration pCa = - log( ) = 2.30

10 25.00 mL Titrant Added (Equivalence Point)
Titration Reaction EDTA Ca2+ CaEDTA2+ start (0.0100M)( L) (0.0050M)( L) = mol = mol = 0 mol end 0 mol 0 mol mol ( mol)/( L) = 0 M = 0 M = M Equilibrium Reaction EDTA Ca2+ CaEDAT2+ Initial Change + x + x - x Equilibrium x x ~ 1.75 x = ( ) / x2 x = [Ca+] = 4.36 x 10-7 M Concentration pCa = - log(4.36 x 10-7) = 6.36

11 50.00 mL Titrant Added Titration Reaction EDTA Ca2+ CaEDTA2+ start (0.0100M)( L) (0.0050M)( L) = mol = mol = 0 mol end mol 0 mol mol ( mol)/(0.1000L) ( mol)/(0.1000L) = M = 0 M = M Equilibrium Reaction EDTA Ca2+ CaEDAT2+ Initial Change + x + x - x Equilibrium ~ x ~ 1.75 x = ( ) / ( ) x x = [Ca+] = 5.71 x M Concentration pCa = - log(5.71 x 10-11) =

12

13 Indicators

14


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