Presentation is loading. Please wait.

Presentation is loading. Please wait.

Ratios and Proportions

Similar presentations


Presentation on theme: "Ratios and Proportions"— Presentation transcript:

1 Ratios and Proportions
Objective I will solve proportions using reciprocals and cross products. I will use proportions to solve real-life problems.

2 Vocabulary Proportion - an equation in which one ratio is set equal to another ratio (Written in the form of , which is read as “a is to b, as c is to d”)

3 Using the Reciprocal Property
Solve the proportion SOLUTION Write original proportion Use reciprocal property Multiply each side by 4 Simplify

4 Using the Reciprocal Property
Solve the proportion CHECK Substitute

5 Using the Cross Product Property
Solve the proportion Write original proportion Use cross product property Simplify Take square root of both sides The solutions are x=-8 and x=8. Check both answers.

6 Checking Solutions Solve the proportion. Use cross product property
Use distributive property Isolate variable term Take square root of both sides

7 Checking Solutions Check each solution. x = 4: x = -4
The solution x = -4 is extraneous because the check results in a false statement. The correct solution is x = 4.

8 Proportions in Real-Life
Archaeologists excavated three pits containing the clay army. To estimate the number of warriors in Pit 1 shown below, an archaeologist might excavate three sites. The sites at the ends together contain 450 warriors. The site in the central region contains 282 warriors. This 10-meter-wide site is thought to be representative of the 200-meter central region. Estimate the number of warriors in the central region. Then estimate the total number of warriors in Pit 1.

9 Proportions in Real-Life
282 warriors 62m 240 warriors 210 warriors 10m Central Region 200m 5m 5m SOLUTION Let n represent the number of warriors in the 200-meter central region. You can find the value of n by solving a proportion.

10 Proportions in Real-Life
Number of warriors found Number of meters excavated = Total number of warriors Total number of meters 282 = 10 n 200 The solution is n = 5640, indicating that there are about 5640 warriors in the central region. With the 450 warriors at the ends, that makes a total of about 6090 warriors in Pit 1.

11 Practice


Download ppt "Ratios and Proportions"

Similar presentations


Ads by Google