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Vector Components Topic – Physics 2a Key words
Component force, horizontal, vertical, right angled triangle,
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Force as a vector Forces that act directly on a body are called contact forces as the body will only experience the force when in contact Forces that act on a body from a distance are called non-contact forces
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Examples of contact forces
Bouncing ball Adhesion – sellotape and paper Cohesion – attraction between particles of the same material – water droplets Surface tension –across molecules of a liquid Any force that occurs when 2 or more bodies touch
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Forces make objects ….. Change shape Change speed
Change direction of motion
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Forces Measured in Newtons (N)
A force of 1N is the force required to hold 100g of mass against the force of gravity
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Force as a vector quantity
Magnitude and direction of a force is needed if effect of force is to be determined Force is therefore a VECTOR quantity = magntude + direction. Force symbol = F
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Drawing forces A vector is represented by a line segment
4N left 2F = 8N left ½ F = 2N left -F = 4N right A vector is represented by a line segment Line is drawn to a specific scale If the force is doubled = 2F Half the force = ½ F Multiplying the forces by a number (scalar) affects only the magnitude of force not the direction. When a vector is multiplied by a negative number the sign is interpreted by reversing the direction of the vector
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Direction conventions
A full circle bearing describes north as zero degrees true Written as 0oT 90oT = 90 degres clockwise from north 180oT = due south 270oT = due west 45oT = NE or N45E 315oT = NW or N45W
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convert Convert quadrant bearing S50W to a full circle bearing in To
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convert Convert quadrant bearing S50W to a full circle bearing in To
Answer: South is 180 = 50 further west = 230 230oT
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Notes – Vector techniques Forces
Copy summary notes 3.2 vector techniques page 96
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Vector techniques If only one force acts upon a body at rest the body has no alternative than to move in the direction of that force – e.g. golf ball being hit by a golf club If more than one force acts on a body the body behaves as if only one force is acting – the vector sum This is called the resultant or the net force €F
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Adding vectors Because force is a vector adding numbers must take direction into account 2N + 3N in the same direction would be 5N in that direction. However 2N left + 3N right = 1N right When at an angle to each other the magntude will be somewhere between 1 and 5
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Adding vectors graphically
A vector diagram is drawn Either to scale = resultant vector can be measured Or Sketched and use mathematical equations
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Adding vectors graphically = page 96
Steps: Draw ref grid of direction NSEW Determine scale Write vector equation – EF (net) Draw first vector to scale From head of arrow draw second vector to be added Resultant vector will be the direct line from tail of first vector to head of second vector Magnitude will be the length Direction is direction of the vector
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Vector components – pg 94 If a hockey puck is hit at a force 100N north 30o west Some of this is a northerly component Some is a westerly component To determine component forces you need to construct a right angled triangle around the force vector. Either trigonometry or scale diagram can be used to calculate the components. Fh= sinθ Fv= cosθ F 100N θ θ = 30o 1 cm represents 25N N = 87N W = 50N
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Example – pg 95 Foot pushes down and backwards when walking
400N backwards and 600N down What is the total force applied by her foot? F = FH + FV draw vector diagram F =√ FH2 + FV2 F =√ F = 721 N F ? Fv= cosθ 600N θ Fh= sinθ 400N θ= tan-1 (opp/adj) θ= tan-1 (600/400) tan-1= 1.5 = 56o
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Question -pg 95 A skier is pulled up a hill at a force of 1500N at an angle of 30o. Determine the horizontal and vertical force? F 1800 = FH + FV draw vector diagram Fv = Fcosθ= 1500cos30o = _________ Fh= Fsinθ = 1500sin30o= _______ F 1800 Fv= cosθ ? θ Fh= sinθ ?
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Question – try this one A skier is pulled up a hill at a force of 1800N at an angle of 40o. Determine the horizontal and vertical force? F 1800 = FH + FV draw vector diagram Fv = Fcosθ= 1800cos40o = _________ Fh= Fsinθ = 1800sin40o= _______ F 1800 Fv= cosθ ? θ Fh= sinθ ?
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